Questions

BLANKS [1 Marks Each]

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49 questions · self-marked practice — reveal the answer and mark yourself.

Question 11 Mark
Fill in the box with the correct symbol out of $>, <$, and =, $0 \;\; \square \frac{-7}{6}$
Answer
Here,
We have,
$0$ and $\frac{-7}{6}$
As you know, that Zero is greater than any negative rational number.
Hence,
$0 > \frac{-7}{6}$
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Question 21 Mark
Fill in the box with the correct symbol out of $>, <$, and = $\frac{5}{-11} \square \frac{-5}{11}$
Answer
We have,
$\frac{-5}{11} \text { and } \frac{5}{-11}$
Now, the two fractions already have like denominators, so we just need to check which is the fraction in which the numerator is larger.
Note: The fraction is considered negative if it has a negative sign either in numerator or in denominator.
$-5$ is equal to $-5$
Hence,
$\frac{-5}{11}=\frac{5}{-11}$
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Question 31 Mark
Fill in the box with the correct symbol out of $>, <$, and = $\frac{1}{-3} \square \frac{-1}{4}$
Answer
According to the given information we have numbers $\frac{1}{-3}$ and $\frac{-1}{4}$
Since both the given numbers are negative
Now ignoring the sign, we get
$\frac{1}{3}$ and $\frac{1}{4}$
Now we have to compare the numbers but since the denominator of both the numbers is different so we have to make the same denominator
To find the common denominator for both of the numbers let's find the $L.C.M$ of $3$ and $4$
$3$ $3, 4$
$4$ $1, 4$
  $1, 1$
So. the $L.C.M$ of $3.4 = 3 \times 4$
$L.C.M$ of $3,4 = 12$
Now multiplying and dividing $R.H.S$ by $3$ and $L.H.S$ by $4$ we get
$\mathrm{L.H.S}=\frac{1}{3} \times \frac{4}{4}=\frac{4}{12}$
$\mathrm{R.H.S}=\frac{1}{4} \times \frac{3}{3}=\frac{3}{12}$
Multiplying both the numbers by $-1$ we get
$\frac{4}{-12}$ and $\frac{-3}{12}$
Now comparing the numbers, we can conclude that
$\frac{4}{-12}<\frac{-3}{12}$
Here denominator is same so we compare only numerator, on the number line if we go to the negative direction as magnitude increases number becomes small, Hence
It can also be written as $ \frac{1}{-3}<\frac{-1}{4}$
Therefore, the symbol which should be filled in the given problem is" $<.$
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Question 41 Mark
Fill in the box with the correct symbol out of $>, <$, and = ,$\frac{-8}{5} \square \frac{-7}{4}$
Answer
We have,
$\frac{-8}{5} \text { and } \frac{-7}{4}$
Writing the fractions in the form of like denominators we get,
$\frac{-8}{5} \text { and } \frac{-7}{4}$
And, $\frac{-7}{4}=\frac{-7 \times 5}{4 \times 5}=\frac{-35}{20}$
Since,
$-32$ is greater than $-35$
Hence,
$\frac{-8}{5}>\frac{-7}{4}$
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Question 51 Mark
Fill in the box with the correct symbol out of $>, <$, and = $\frac{-7}{8} \square \frac{14}{-16}$
Answer
We have,
$\frac{-14}{16} \text { and } \frac{-7}{8}$
Writing the fractions in the form of like denominators we get,
And, $\frac{-14}{16}$
$\frac{-7}{8}=\frac{-7 \times 2}{8 \times 2}$
Since,
$-14$ is equal to $-14$
Hence,
$\frac{-7}{8}=\frac{14}{-16}$
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Question 61 Mark
Fill in the box with the correct symbol out of $>, <$, and = $\frac{-4}{5} \square \frac{-5}{7}$
Answer
We have,
$-\frac{5}{7} \text { and } \frac{-4}{5}$
Writing the fractions in the form of like denominators we get,
$\frac{-5}{7}=\frac{-5 \times 5}{7 \times 5}=\frac{-25}{35}$
And,
$\frac{-4}{5}=\frac{-4 \times 7}{5 \times 7}=\frac{-28}{35}$
Since,
$-25$ is greater than $-28$
Hence,
$\frac{-4}{5}<\frac{-5}{7}$
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Question 71 Mark
Fill in the box with the correct symbol out of $>, <$, and = $\frac{-5}{7} \square \frac{2}{3}$
Answer
We have,
$-\frac{5}{7} \text { and } \frac{2}{3}$
Writing the fractions in the form of like denominators we get,
$-\frac{5}{7} \text { and } \frac{2}{3}$
And, $\frac{2}{3}=\frac{2 \times 7}{3 \times 7}=\frac{14}{21}$
Since,
$14$ is greater than $-15$
Hence,
$\frac{-5}{7}<\frac{2}{3}$
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Question 81 Mark
$0.2 \%=$.............. $\left(\frac{2}{10}, \frac{2}{100}, \frac{2}{1000}\right)$
Answer
$\frac{2}{1000}$
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Question 141 Mark
$............\%$ of a circle is removed, if its $\frac{1}{8}$ th part is removed. $(40, 80, 12.5)$
Answer
$12.5$
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Question 251 Mark
An item costs $₹70$. If $20\%$ of its price is increased, then its cost is $............ (140, 84, 90)$
Answer
$84$
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Question 261 Mark
If cost of an item is increased from $₹40$ to $₹50............$. then percentage of price is increased. $(10, 20, 25)$
Answer
$25$
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Question 281 Mark
$0.2 \%=$.............. $\left(\frac{2}{10}, \frac{2}{100}, \frac{2}{1000}\right)$
Answer
$\frac{2}{1000}$
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Question 341 Mark
$...........\%$ of a circle is removed, if its $\frac{1}{8}$ th part is removed. $(40, 80, 12.5)$
Answer
$12.5$
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Question 451 Mark
An item costs $₹70.$ If $20\%$ of its price is increased, then its cost is $............ (140, 84, 90)$
Answer
$84$
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Question 461 Mark
If cost of an item is increased from $₹40$ to $₹50.............$ then percentage of price is increased. $(10, 20, 25)$
Answer
$25$
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Question 481 Mark
Fill in the blank. If $\text{A}=\frac{1}{3} B$ and $\text{B}=\frac{1}{2} C$ then $A : B : C =$ ______.
Answer
If $\text{A}=\frac{1}{3}$ B and $\text{B}=\frac{1}{2} C$ then $A : B : C = 1 : 3 : 6.$
Solution: Given, $\text{A}=\frac{1}{3}$ B and $\text{B}=\frac{1}{2} C \text{A : B : C}=\frac{1}{3}\text{B : B : }2\text{B}=1:2:3$
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Question 491 Mark
Mark against the correct answer in the following: If $10$ metres of a uniform rod weighs $18\ kg$, then the weight of $6$ metres of the rod is _____ kg.
Answer
If $10$ metres of a uniform rod weighs $18\ kg$, then the weight of $6$ metres of the rod is $10.8\ kg$.
Solution: A rod of length $10\ m$ weighs $18\ kg$.
A rod of length 6 m will weigh $\frac{18}{10}\times6=10.8\text{kg.}$
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