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Maths M.C.Q. [1 Marks Each]

Comparing Quantities · Jharkhand Board (JAC) STD 7 (Jharkhand - English Medium). 22 questions.

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M.C.Q. [1 Marks Each]

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22 questions · auto-graded multiple-choice test.

MCQ 11 Mark
The per cent that represents the shaded region in the figure is:
  • ✓
    $36\%$
  • B
    $64\%$
  • C
    $27\%$
  • D
    $48\%$
Answer
Correct option: A.
$36\%$
Given, total parts $= 10 \times 10 = 100$
$\therefore$ Shaded parts $= 36$
$\therefore$ Per cent of shaded parts $=\frac{36}{100}\times100\%=36\%$
Then, per cent of unshaded parts$ = 100 - 60 = 40\%$
Hence, the unshaded region is $36\%$
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MCQ 21 Mark
Amount received on $Rs. 3000$ for $2$ year at the rate of $11\%$ per annum is:
  • ✓
    $Rs. 2340$
  • B
    $Rs. 3660$
  • C
    $Rs. 4320$
  • D
    $Rs. 3330$
Answer
Correct option: A.
$Rs. 2340$
Given, $P = Rs. 3000,$
$T = 2$ year
$R = 11\%$
$\therefore\text{I}=\frac{\text{P}\times\text{R}\times\text{T}}{100}=\frac{3000\times11\times2}{100}=\text{Rs. }660$
Now, amount$(A) = P + I$
$= 3000 + 660$
$= Rs. 3660$
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MCQ 31 Mark
The per cent that represents the unshaded region in the figure, is:
  • A
    $75\%$
  • B
    $50\%$
  • ✓
    $40\%$
  • D
    $60\%$
Answer
Correct option: C.
$40\%$
Given, total parts$ = 10 \times 10 = 100$
$\therefore$ Shaded parts $= 60$
$\therefore$ Per cent of shaded parts $=\frac{60}{100}\times100\%=60\%$
Then, per cent of unshaded parts $= 100 - 60 = 40\%$
Hence, the unshaded region is $40\%$
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MCQ 41 Mark
If $90\%$ of $x$ is $315\km$, then the value of $x$ is:
  • A
    $325\ km.$
  • ✓
    $350\ km.$
  • C
    $405\ km.$
  • D
    $340\ km.$
Answer
Correct option: B.
$350\ km.$
Given, $90\%$ of $x = 315\ km.$
$\Rightarrow\frac{90}{100}\times\text{x}=315\Rightarrow\text{x}=\frac{315\times100}{90}$
$\therefore\text{x}=350\text{km.}$
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MCQ 51 Mark
A farmer bought a buffalo for $Rs. 44000$ and a cow for $Rs. 18000$. He sold the buffalo at a loss of $5\%$ but made a profit of $10\%$ on the cow. The net result of the transaction is:
  • A
    Loss of $Rs. 200$
  • B
    Profit of $Rs. 400$
  • ✓
    Loss of $Rs. 400$
  • D
    Profit of $Rs. 200$
Answer
Correct option: C.
Loss of $Rs. 400$
For bufalo, $CP = Rs. = 44000$
Loss$ \% = 5\%$
$\therefore\text{Loss}\%=\frac{\text{Loss}}{\text{CP}}\times100\%$
$\Rightarrow5=\frac{\text{Loss}}{44000}\times100$
$\Rightarrow\text{Loss}=5\times440=\text{Rs.}2200$
So, $SP = CP$ - Loss $= 44000 - 2200 = Rs. 41800$
For cow, $CP = Rs. 18000$
Profit$ \% = 10\%$
$\therefore\text{Profit}\%=\frac{\text{Profit}}{\text{CP}}\times100\%$
$\Rightarrow10=\frac{\text{Profit}}{18000}\times100$
Profit $= Rs. 1800$
So, $SP = CP$ + Profit $= 18000 + 1800 = Rs. 19800$
Total $CP$ of buffalo and cow $= 44000 + 18000 = Rs. 62000$
Total $SP$ of buffalo and cow $= 41800 + 19800 = Rs. 61600$
Net loss $= CP - SP = 62000 - 61600 = Rs. 400$
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MCQ 61 Mark
$5.2$ is equal to:
  • A
    $52\%$
  • B
    $5.2\%$
  • ✓
    $520\%$
  • D
    $0.52\%$
Answer
Correct option: C.
$520\%$
We have, $5.2$
In percentage, $\frac{52}{10}\times100\%=520\%$
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MCQ 71 Mark
If Mohan’s income is $25\%$ more than Raman’s income, then Raman’s income is less than Mohan’s income by:
  • A
    $25\%$
  • B
    $80\%$
  • ✓
    $20\%$
  • D
    $75\%$
Answer
Correct option: C.
$20\%$
Let the Raman’s income be $x$. it is given that Mohan’s income is $25\%$ more than Raman’s income.
The, Mohan's income $=\text{x}+20\%\text{ of } \text{x}+\frac{25}{100}\text{x}=\text{x}\Big(1+\frac{25}{100}\Big)$
$=\text{x}\Big(\frac{100+25}{100}\Big)=\frac{125}{100}\text{x}$
$\therefore$ Raman's income as compared to Mohan's income.
$=\frac{\text{Mohan's income - Raman's income}}{\text{Mohan's income}}\times100\%$
$\frac{\frac{125}{100}\text{x-x}}{\frac{125}{100}\text{x}}\times100\%=\frac{\frac{125\text{x}-100\text{x}}{100}}{\frac{125}{100}\text{x}}\times100\%$
$=\frac{25\text{x}}{125\text{x}}\times100\%=20\%$
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MCQ 81 Mark
$\frac{25\%\text{ of } 50\%\text{ of }100\%}{25\times50}\text{is equal to}$
  • A
    $1.1\%$
  • B
    $0.1\%$
  • ✓
    $0.01\%$
  • D
    $1\%$
Answer
Correct option: C.
$0.01\%$
We have, $\frac{25\%\text{ of } 50\%\text{ of }100\%}{25\times50}$
$=\frac{25}{100}\times\frac{50}{100}\times\frac{100}{100}\times\frac{1}{25\times50}$
$=\frac{125000}{1250\times100\times100\times100}=\frac{1}{10000}=0.0001$
In percentage, $0.0001 \times 100% = 0.01%$
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MCQ 91 Mark
The sum which will earn a simple interest of $Rs. 126$ in $2$ years at $14\%$ per annum is:
  • A
    $Rs. 39$
  • B
    $Rs. 395$
  • ✓
    $Rs. 450$
  • D
    $Rs. 540$
Answer
Correct option: C.
$Rs. 450$
Given, $I = Rs. 126, R = 14\%$ and $T = 2$year
$\therefore\text{I}=\frac{\text{P}\times\text{R}\times\text{T}}{100}\Rightarrow126=\frac{\text{P}\times14\times2}{100}$
$\Rightarrow126\times100=\text{P}\times14\times2$
$\Rightarrow\text{P}=\frac{12600}{14\times2}\Rightarrow\text{P}=\text{Rs. }450$
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MCQ 101 Mark
$0.07$ is equal to:
  • A
    $70\%$
  • ✓
    $7\%$
  • C
    $0.7\%$
  • D
    $0.07\%$
Answer
Correct option: B.
$7\%$
We have, $0.07$
In percentage, $0.07=\frac{7}{100}\times\frac{100}{100}=\frac{7}{100}\times100\%=7\%$
Note: To convert any number into per cent, we multiply that number by $100$ along with the symbol $‘ \%’$
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MCQ 111 Mark
A cricket bat was purchased for $Rs\ 800$ and was sold for $Rs\ 1600$. Then, profit earned is:
  • ✓
    $100\%$
  • B
    $64\%$
  • C
    $50\%$
  • D
    $60\%$
Answer
Correct option: A.
$100\%$
Given, cost of criket balt $= Rs. 800$
and selling price of criket bat $= Rs. 1600$
$\therefore$ Profit $= SP - CP = Rs.(1600 - 800) = Rs. 800$
We know that.
$\text{Profit}\%=\frac{\text{Profit}}{\text{CP}}\times100\% = \frac{800}{800}\times100\%=100\%$
Hence. profit earned is $100\%$.
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MCQ 121 Mark
$225\%$ is equal to:
  • ✓
    $9 : 4$
  • B
    $4 : 9$
  • C
    $3 : 2$
  • D
    $2 : 3$
Answer
Correct option: A.
$9 : 4$
We have, $225\%$
In percentage, $225\times\frac{1}{100}=\frac{225}{100}=\frac{9}{4}$
$\therefore$ Required ratio $= 9 : 4$
Note: The sign of percentage $( \%)$ is removed dividing the number by $100$.
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MCQ 131 Mark
$20\%$ of $700m$ is:
  • A
    $560m.$
  • B
    $70m.$
  • C
    $210m.$
  • ✓
    $140m.$
Answer
Correct option: D.
$140m.$
We have, $20\%$ of $700\text{m}=\frac{20}{100}\times700=20\times7=140\text{m}$
Hence, $20\%$ of $700\ m$ is $140\ m$.
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MCQ 141 Mark
Interest on $Rs. 12000$ for $1$ month at the rate of $10\%$ per annum is:
  • A
    $Rs. 1200$
  • B
    $Rs. 600$
  • ✓
    $Rs. 100$
  • D
    $Rs. 12100$
Answer
Correct option: C.
$Rs. 100$
Given, $P = Rs. 12000,$
$R = 10\%$
$T = 1$ month $=\frac{1}{12}\text{yr}$
$\therefore\text{I}=\frac{\text{P}\times\text{R}\times\text{T}}{100}=\frac{12000\times10\times1}{100\times12}=\text{Rs. }100$
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MCQ 151 Mark
The ratio of Fatima’s income to her savings is $4 : 1$. The percentage of money saved by her is:
  • ✓
    $20\%$
  • B
    $25\%$
  • C
    $40\%$
  • D
    $80\%$
Answer
Correct option: A.
$20\%$
Given, ratio of income to savings $= 4 : 1$
Let income $= 4x$ and savings $= x.$
$\therefore$ Percentage of money saved by her $=\frac{\text{Savings}}{(\text{Income+Savimgs)}}\times100\%$
$=-\frac{\text{x}}{4\text{x}+\text{x}}\times100=\frac{\text{x}}{5\text{x}}\times100\%$
$=\frac{1}{5}\times100\%=20\%$
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MCQ 161 Mark
On selling an article for $Rs. 329,$ a dealer lost $6\%$. The cost price of the article is
  • A
    $Rs. 310.37$
  • B
    $Rs. 348.74$
  • C
    $Rs. 335$
  • ✓
    $Rs. 350$
Answer
Correct option: D.
$Rs. 350$
Given, $SP = Rs. = 329$ and loss$ \% = 6 \%$
We know that,
$\text{Loss}\%=\frac{\text{Loss}}{\text{CP}}\times100$
$\Rightarrow6=\frac{\text{CP}-\text{SP}}{\text{CP}}\times100$
$[\therefore\text{Loss}=\text{CP}-\text{SP}]$
$\Rightarrow6\text{CP}=100(\text{CP-SP})$
$\Rightarrow\frac{6}{100}\text {CP} = \text{CP}-\text{SP}$
$\Rightarrow\text{CP}-\frac{6}{100}\text{CP}=329$
$[\therefore\text{SP}=\text{Rs. 329, }\text{givne}]$
$\Rightarrow\frac{94}{100}\text{CP}=329$
$\Rightarrow\text{CP}=\frac{329\times100}{94}$
$\therefore\text{CP} = \text{Rs. }350$
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MCQ 171 Mark
What percent of $Rs. 4500$ is $Rs. 9000$?
Ratio Decimal Per cent
$\frac{3}{10}=\frac{30}{100}$ $0.30$ $30\%$
$\frac{1}{2}=\frac{50}{100}$ $0.50$ $50\%$
$\frac{3}{4}=\frac{75}{100}$ $0.75$ $75\%$
  • ✓
    $200$
  • B
    $\frac{1}{2}$
  • C
    $2$
  • D
    $50$
Answer
Correct option: A.
$200$
Let the percentage be $X \%$
$\Rightarrow\text{X}\% \text { of }4500 = 9000$
$\Rightarrow\frac{\text{x}}{100}\times4500=9000$
$\Rightarrow45\text{x}=9000$
$\Rightarrow\text{X}\%=\frac{9000}{45}$
$\Rightarrow200 $
Hence, option $A$ is the correct one.
$\Rightarrow $ Option $A$ is correct as $200 = 200$
$\Rightarrow $ Option $B$ is incorrect as $\frac{1}{2}\neq200$
$\Rightarrow $ Option $D$ is incorrect as $50\neq200$
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MCQ 181 Mark
In a scout camp, $40\%$ of the scouts were from Gujarat State and $20\%$ of these were from Ahmedabad. The percentage of scouts in the camp from Ahmedabad is:
  • A
    $25$
  • ✓
    $32.5$
  • C
    $8$
  • D
    $50$
Answer
Correct option: B.
$32.5$
Let the scouts in scout camp $= 100$
Then, scouts from Gujarat $= 40\%$ of $100=\frac{40}{100}\times100 = 40$
and secouts from Ahmedabad $= 20\%$ of $40=\frac{20}{100}\times40=8$
$\therefore$ Percentageofscouts from Ahmedbade $\frac{\text{Scouts from Ahmedbad}}{\text{Total Scouts}}\times100\%$
$=\frac{8}{100}\times100\%=8\%$
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MCQ 191 Mark
The ratio $3 : 8$ is equal to:
  • A
    $3.75\%$
  • ✓
    $37.5\%$
  • C
    $0.375\%$
  • D
    $267\%$
Answer
Correct option: B.
$37.5\%$
Given, ratio $= 3 : 8$
In percentage, $\frac{3}{8}\times100\%=37.5\%$
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MCQ 201 Mark
Gayatri’s income is $Rs. 160000$ per year. She pays $15\%$ of this as house rent and $10\%$ of the remainder on her child’s education. The money left with her is:
  • A
    $Rs. 136000$
  • B
    $Rs. 120000$
  • ✓
    $Rs. 122400$
  • D
    $Rs. 14000$
Answer
Correct option: C.
$Rs. 122400$
Money paid as house rent $= 15\%$ of $160000=\frac{15}{100}\times160000=\text{Rs. }24000$
Remaining amount $= 160000 - 24000 = Rs 136000$
Money spent on child’s education $= 10\%$ of $136000=\frac{10}{100}\times136000=\text{Rs. }13600$
Money left with her $= 136000 - 13600= Rs 122400$
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MCQ 211 Mark
Rajni and Mohini deposited $Rs. 3000$ and $Rs. 4000$ in a company at the rate of $10\%$ per annum for $3$yr and ${2\frac{1}{2}}\text { year}$, respectively. The difference of the amounts received by them will be:
  • A
    $Rs. 100$
  • B
    $Rs. 1000$
  • ✓
    $Rs. 900$
  • D
    $Rs. 1100$
Answer
Correct option: C.
$Rs. 900$
For Rajni, $P = Rs. 3000.$
$R = 10\% $Per annum
$T = 3$ year
$\therefore\text{I}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$=\frac{3000\times10\times3}{100}=\text{Rs. }900$
$A = P + I = 3000 + 900 = Rs. 3900$
For Mohini, $P = Rs. 4000.$
$R = 10\%$ per annum
$\text{T}=2\frac{1}{2}\text{yr}=\frac{5}{2}\text{ year}$
$\therefore\text{I}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$=\frac{4000\times10\times5}{100\times2}=\text{Rs. }1000$
and $A = P + I = 4000 + 1000 = Rs. 5000$
Difference in amounts $= 5000 - 3900 = Rs. 1100$
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MCQ 221 Mark
A bicycle is purchased for $Rs. 1800$ and is sold at a profit of $12\%$. Its selling price is:
  • A
    $Rs. 1584$
  • ✓
    $Rs. 2016$
  • C
    $Rs. 1788$
  • D
    $Rs. 1812$
Answer
Correct option: B.
$Rs. 2016$
Given, cost price of bicycle $= ?\ 1800$ and profit $=12\%$
As we know,
$\text{Profit}\%=\frac{\text{Profit}}{\text{CP}}\times100$
$\Rightarrow12=\frac{\text{Profit}}{1800}\times100$
$\Rightarrow\text{Profit}=12\times18=\text{Rs.}216$
$\therefore$ $SP = CP +$ Profit $= 1800 + 216 = 2016.$
Hence, the seling price for bicycle is $Rs. 2016.$
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