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Maths 1 Marks Question

Data Handling II (Central Values) · Jharkhand Board (JAC) STD 7 (Jharkhand - English Medium). 17 questions.

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17 questions · self-marked practice — reveal the answer and mark yourself.

Question 11 Mark
The rainfall (in mm) in a city on $7$ days of a certain week was recorded as follows:
Day
Mon
Tue
Wed
Thu
Fri
Sat
Sun
Rainfall (in mm)
$0.0$
$12.2$
$2.1$
$0.0$
$20.5$
$5.3$
$1.0$
Find the range of the rainfall from the above data.
Answer
The range of the rainfall = Maximum rainfall - Minimum rainfall $= 20.5 - 0.0 = 20.5$mm.
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Question 21 Mark
The rainfall (in mm) in a city on $7$ days of a certain week was recorded as follows:
Day
Mon
Tue
Wed
Thu
Fri
Sat
Sun
Rainfall (in mm)
$0.0$
$12.2$
$2.1$
$0.0$
$20.5$
$5.3$
$1.0$
Find the mean rainfall for the week.
Answer
The mean rainfall $= (0.0 + 12.2 + 2.1 + 0.0 + 20.5 + 5.3 + 1.0) ÷ 7 = 41.1 ÷ 7 = 5.87$mm.
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Question 31 Mark
The rainfall (in mm) in a city on $7$ days of a certain week was recorded as follows:
Day
Mon
Tue
Wed
Thu
Fri
Sat
Sun
Rainfall (in mm)
$0.0$
$12.2$
$2.1$
$0.0$
$20.5$
$5.3$
$1.0$
On how many days was the rainfall less than the mean rainfall.
Answer
Clearly, there are $5$ days (Mon, Wed, Thu, Sat and Sun), when the rainfall was less than the mean, i.e., $5.87$mm.
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Question 41 Mark
The marks (out of $100$) obtained by a group of students in science test are $85, 76, 90, 84, 39, 48, 56, 95, 81$ and $75$. Find the: Highest and the lowest marks obtained by the students.
Answer
In order to find the highest and lowest marks, let us arrange the marks in ascending order as follows:
$39, 48, 56, 75, 76, 81, 84, 85, 90, 95$ Clearly, the highest mark is $95$ and the lowest is $39$
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Question 51 Mark
The marks (out of $100$) obtained by a group of students in science test are $85, 76, 90, 84, 39, 48, 56, 95, 81$ and $75$. Find the Range of marks obtained.
Answer
In order to find the highest and lowest marks, let us arrange the marks in ascending order as follows: $39, 48, 56, 75, 76, 81, 84, 85, 90, 95$ The range of the marks obtained is: $(95 - 39) = 56.$
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