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Maths M.C.Q. [1 Marks Each]

Fractions and Decimals · Jharkhand Board (JAC) STD 7 (Jharkhand - English Medium). 20 questions.

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M.C.Q. [1 Marks Each]

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20 questions · auto-graded multiple-choice test.

MCQ 11 Mark
$\frac{5}{7}\div6$ is equal to:
  • A
    $\frac{30}{7}$
  • ✓
    $\frac{5}{42}$
  • C
    $\frac{30}{42}$
  • D
    $\frac{6}{7}$
Answer
Correct option: B.
$\frac{5}{42}$
Given, $\frac{5}{7}+6=\frac{5}{7}\times\frac{1}{6}=\frac{5}{42}$
$\big[\because\text{reciprocal of 6 or}\frac{6}{1}=\frac{1}{6}\big]$
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MCQ 21 Mark
The picture  interprets
  • A
    $\frac{1}{4}\div3$
  • ✓
    $3\times\frac{1}{4}$
  • C
    $\frac{3}{4}\times3$
  • D
    $3\div\frac{1}{4}$
Answer
Correct option: B.
$3\times\frac{1}{4}$


This interprest $\frac{1}{4}\text{th}$ part of a circle.
$\therefore$$=3\times\frac{1}{4}$
Hence, the whole pictrue represents $3\times\frac{1}{4}\text{i.e.}\frac{3}{4}\text{th}$ part.

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MCQ 31 Mark
$\frac{4}{5}$ of $5kg$ apples were used on Monday. The next day $\frac{1}{3}$ of what was left was used. Weight (in kg) of apples left now is:
  • A
    $\frac{8}{15}$
  • B
    $\frac{40}{3}$
  • ✓
    $\frac{40}{5}$
  • D
    $\frac{8}{3}$
Answer
Correct option: C.
$\frac{40}{5}$
Apples used on monady $=\frac{4}{5}\ \text{of}\ 5=\frac{4}{5}\times5=4\text{kg}$
Remaining apples $= 5 - 4 = 1kg$
Apples used next day $=\frac{1}{3}$ of remaining apples
$=\frac{1}{3}\times1\text{kg}=\frac{1}{3}\text{kg}$
So, weight of aplles left now
= Total apples-Apples use monday-Apples used next day
$=\big(-4-\frac{1}{3}\big)$
$=\frac{15-12-1}{3}$ $\big[\text{taking LCM}\big]$
$=\frac{2}{3}\text{kg}$
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MCQ 41 Mark
The product of $7$ and $6\frac{3}{4}$ is:
  • A
    $42\frac{1}{4}$
  • ✓
    $47\frac{1}{4}$
  • C
    $42\frac{3}{4}$
  • D
    $47\frac{3}{4}$
Answer
Correct option: B.
$47\frac{1}{4}$
Given, $7\times6\frac{3}{4}$
$\because\ 6\frac{3}{4}=\frac{(6\times4+3)}{4}=\frac{24+3}{4}=\frac{27}{4}$
$\therefore7\times6\frac{3}{4}=7\times\frac{27}{4}=\frac{189}{4}=47\frac{1}{4}$
Hence, the product of 7 and $6\frac{3}{4}\ \text{is}\ 47\frac{1}{4}$
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MCQ 51 Mark
$\frac{2}{5}\times5\frac{1}{5}$ is equal to:
  • A
    $\frac{26}{25}$
  • ✓
    $\frac{52}{25}$
  • C
    $\frac{2}{5}$
  • D
    $6$
Answer
Correct option: B.
$\frac{52}{25}$

Given, $\frac{2}{5}\times5\frac{1}{5}$
$\because5\frac{1}{5}=\frac{(5\times5)+1}{5}$
$=\frac{25+1}{5}=\frac{26}{5}$
$\therefore\frac{2}{5}\times5\frac{1}{5}\times\frac{26}{5}=\frac{52}{25}$

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MCQ 61 Mark
$5\frac{1}{6}\div\frac{9}{2}$ is equal to:
  • A
    $\frac{31}{6}$
  • B
    $\frac{1}{27}$
  • C
    $5\frac{1}{27}$
  • ✓
    $\frac{27}{31}$
Answer
Correct option: D.
$\frac{27}{31}$
Given, $5\frac{1}{6}+\frac{9}{2}$
$\because5\frac{1}{6}=\frac{(5\times6)+1}{6}=\frac{30+1}{6}=\frac{31}{6}$
$\big[\because\text{reciprocal of}\ \frac{9}{2}=\frac{2}{9}\big]$
$\therefore5\frac{1}{6}+\frac{9}{2}=\frac{31}{6}\times\frac{2}{9}=\frac{31}{27}$
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MCQ 71 Mark
The product of $3$ and $4\frac{2}{5}$ is:
  • A
    $17\frac{2}{5}$
  • B
    $\frac{24}{5}$
  • ✓
    $13\frac{1}{5}$
  • D
    $5\frac{1}{13}$
Answer
Correct option: C.
$13\frac{1}{5}$
Given, $3\times4\frac{2}{5}$
$\because4\frac{2}{5}=\frac{(4\times5)+2}{5}=\frac{22}{5}$
$\therefore3\times4\frac{2}{5}=3\times\frac{22}{5}=\frac{66}{5}=13\frac{1}{5}$
Hence, the product of 3 and $4\frac{2}{5}\ \text{is}\ 13\frac{1}{5}$
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MCQ 81 Mark
Which of the following represents $\frac{1}{3}$ of $\frac{1}{6}$?
  • A
    $\frac{1}{3}+\frac{1}{6}$
  • B
    $\frac{1}{3}-\frac{1}{6}$
  • ✓
    $\frac{1}{3}\times\frac{1}{6}$
  • D
    $\frac{1}{3}\div\frac{1}{6}$
Answer
Correct option: C.
$\frac{1}{3}\times\frac{1}{6}$
We have, $\frac{1}{3}\ \text{of}\ \frac{1}{6}=\frac{1}{3}\times\frac{1}{6}$
Note of represents multiplication$(\times )$.
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MCQ 91 Mark
$3\frac{3}{4}\div\frac{3}{4}$ is equal to:
  • A
    $3$
  • B
    $4$
  • ✓
    $5$
  • D
    $\frac{45}{16}$
Answer
Correct option: C.
$5$
Given, $3\frac{3}{4}\div\frac{3}{4}$
$\because\ 3\frac{3}{4}=\frac{(3\times4)+3}{4}=\frac{12+3}{4}=\frac{15}{4}$
$\therefore3\frac{3}{4}\div\frac{3}{4}=\frac{15}{4}\times\frac{4}{3}=5$
$\bigg[\because\text{reciprocal of} \frac{3}{4}=\frac{4}{3}\bigg]$
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MCQ 101 Mark
$2\frac{2}{3}\div5$ is equal to:
  • ✓
    $\frac{8}{15}$
  • B
    $\frac{40}{3}$
  • C
    $\frac{40}{5}$
  • D
    $\frac{8}{3}$
Answer
Correct option: A.
$\frac{8}{15}$
Given, $2\frac{2}{3}+5=\frac{(2\times3)+2}{3}+5$
$=\frac{6+2}{3}+5=\frac{8}{3}\times\frac{1}{5}$ $\big[\because\text{reciprocal of}\ 5=\frac{1}{5}\big]$
$=\frac{8}{15}$
Hence, $2\frac{2}{3}+5$ is equal to $\frac{8}{15}$
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MCQ 111 Mark
The product of $\frac{11}{13}$ and 4 is:
  • ✓
    $3\frac{5}{13}$
  • B
    $5\frac{3}{13}$
  • C
    $13\frac{3}{5}$
  • D
    $13\frac{5}{3}$
Answer
Correct option: A.
$3\frac{5}{13}$
We have, $\frac{11}{13}\times4$
$\therefore\frac{11}{13}\times4=\frac{44}{13}=3\frac{5}{13}$
Hence, the product of $\frac{11}{13}\ \text{and}\ 4\ \text{is}\ 3\ \frac{5}{13}$
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MCQ 121 Mark
$\frac{3}{7}\ \text{of}\ \frac{2}{5}$ is equal to:
  • A
    $\frac{5}{12}$
  • B
    $\frac{5}{35}$
  • C
    $\frac{1}{35}$
  • ✓
    $\frac{6}{35}$
Answer
Correct option: D.
$\frac{6}{35}$
Given, $\frac{3}{7}\ \text{of}\ \frac{2}{5}=\frac{3}{7}\times\frac{2}{5}=\frac{6}{35}$
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MCQ 131 Mark
$\frac{1}{5}\div\frac{4}{5}$ equal to:
  • A
    $\frac{4}{5}$
  • B
    $\frac{1}{5}$
  • C
    $\frac{5}{4}$
  • ✓
    $\frac{1}{4}$
Answer
Correct option: D.
$\frac{1}{4}$
Given, $\frac{1}{5}+\frac{4}{5}=\frac{1}{5}\times\frac{5}{4}$ $\big[\because\text{reciprocal of}\frac{4}{5}=\frac{5}{4}\big]$
$=\frac{1}{4}$
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MCQ 141 Mark
Reciprocal of the fraction $\frac{2}{3}$ is:
  • A
    $2$
  • B
    $3$
  • C
    $\frac{2}{3}$
  • ✓
    $\frac{3}{2}$
Answer
Correct option: D.
$\frac{3}{2}$
The reciprocal of a non-zero frcation is obtained by interchanging its numerator and denominator.
Hence, the reciprocal of $\frac{2}{3}\text{is}\frac{3}{2}$
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MCQ 151 Mark
A ribbon of length $5\frac{1}{4}\text{m}$ is cut into small pieces each of length $\frac{3}{4}\text{m}$ Number of pieces will be:
  • A
    $5$
  • B
    $6$
  • ✓
    $7$
  • D
    $8$
Answer
Correct option: C.
$7$
Number of pieces
$=\frac{\text{Total length of ribbon}}{\text{Length of one piece}}=\frac{\big(5\frac{1}{4}\big)}{\big(\frac{3}{4}\big)}$
$=\Bigg(\frac{\frac{(5\times4)+1}{4}}{\frac{3}{4}}\Bigg)=\bigg(\frac{\frac{21}{4}}{\frac{3}{4}}\bigg)$
$=\frac{21}{4}\times\frac{4}{3}=7$
$\big[\because\text{reciprocal of}\ \frac{3}{4}=\frac{4}{3}\big]$
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MCQ 161 Mark
Pictorial representation of $3\times\frac{2}{3}$ is:






 
  • A
  • B
  • C
  • ✓
Answer
Correct option: D.



$3\times\frac{2}{3}$ means $3$ times the two-third part of anything.
$\therefore$ Option $(b)$ is correct.
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MCQ 171 Mark
One packet of biscuits requires $2\frac{1}{2}$ cups of flour and $1\frac{2}{3}$cups of sugar. Estimated total quantity of both ingredients used in $10$ such packets of biscuits will be.
  • A
    Less than $30$ cups.
  • B
    Between $30$ cups and $40$ cups.
  • ✓
    Between $40$ cups and $50$ cups.
  • D
    Above $50$ cups.
Answer
Correct option: C.
Between $40$ cups and $50$ cups.
Total quantity of both ingredients in one packet of biscuits
= Quantity of flour + Quantity of sugar
$=2\frac{1}{2}\ \text{cups}+1\frac{2}{3}\text{cups}$
$=\frac{(2\times2)+1}{2}+\frac{(1\times3)+2}{3}$
$-\frac{4+1}{2}+\frac{3+2}{3}$
$=\frac{5}{2}+\frac{5}{3}$
$=\frac{5\times3+2\times5}{6}$ $\big[\because\ \text{LCM of 2 and 3 = 6}\big]$
$=\frac{15+10}{6}$
$=\frac{25}{6}$
$\therefore$ Total quantity of both ingredients used in $10$ packets
$= 10 \times$  Total quantity of ingredients in one packet
$=10\times\frac{25}{6}=\frac{250}{6}$
Since, $\frac{250}{6}$ lies between $40$ and $50$.
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MCQ 181 Mark
The ascending arrangement of $\frac{2}{3},\frac{6}{7},\frac{13}{21}$ is:
  • A
    $\frac{6}{7},\frac{2}{3},\frac{13}{21}$
  • ✓
    $\frac{13}{21},\frac{2}{3},\frac{6}{7}$
  • C
    $\frac{6}{7},\frac{13}{21},\frac{2}{3}$
  • D
    $\frac{2}{3},\frac{6}{7},\frac{13}{21}$
Answer
Correct option: B.
$\frac{13}{21},\frac{2}{3},\frac{6}{7}$
Given, $\frac{2}{3},\frac{6}{7},\frac{13}{21}$
$LCM$ of $(3, 7, 21) = 21$
$\therefore\frac{2}{3}=\frac{2}{3}\times\frac{7}{7}=\frac{14}{21}$
$\frac{6}{7}=\frac{6}{7}\times\frac{3}{3}=\frac{18}{21}$
and $\frac{13}{21}=\frac{13}{21}$
Now, compare $\frac{14}{21},\frac{18}{21}\text{and}\frac{13}{21}$
$\text{So},\frac{13}{21}<\frac{14}{21}<\frac{18}{21}$
Hence, $\frac{13}{21}<\frac{2}{2}<\frac{96}{7}$ (ascending order)
Note with same denominators, fraction with larger numerator is greater.
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MCQ 191 Mark
The product of $0.03 \times 0.9$ is:
  • A
    $2.7$
  • B
    $0.27$
  • ✓
    $0.027$
  • D
    $0.0027$
Answer
Correct option: C.
$0.027$
Given, $0.03 \times 0.9$
Here, $3 \times 9 = 27$
Sum of the decimal places to the right of the decimal point is $0.03$ and $0.09$ is $3$
So, $0.03 \times 0.9 = 0.027$
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MCQ 201 Mark
On dividing $7\ \text{by}\ \frac{2}{5}$, the result is:
  • A
    $\frac{14}{2}$
  • B
    $\frac{35}{4}$
  • C
    $\frac{14}{5}$
  • ✓
    $\frac{35}{2}$
Answer
Correct option: D.
$\frac{35}{2}$
Given, $7+\frac{2}{5}=7\times\frac{5}{2}=\frac{35}{2}$
$\big[\because\text{reciprocal of}\ \frac{2}{5}=\frac{5}{2}\big]$
Hence, on dividing $7\ \text{by}\ \frac{2}{5},\text{we get}\frac{35}{2}$
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