Question 13 Marks
In Figure, $AB\ ||\ CD$ and $AC\ ||\ BD$. Find the values of $x, y, z$.


Answer
View full question & answer→Since, $AC\ ||\ BD$ and $CD\ ||\ AB$,
$ABCD$ is a parallelogram Adjacent angles of parallelogram,
$\angle \text{CAD}+\angle \text{ACD}=180^\circ$
$=\angle \text{ACD}=180^\circ-65^\circ$
$=115^\circ$
Opposite angles of parallelogram,
$=\angle \text{CAD}=\angle \text{CDB}=65^\circ$
$=\angle \text{ACD}=\angle \text{DBA}=115^\circ$
$ABCD$ is a parallelogram Adjacent angles of parallelogram,
$\angle \text{CAD}+\angle \text{ACD}=180^\circ$
$=\angle \text{ACD}=180^\circ-65^\circ$
$=115^\circ$
Opposite angles of parallelogram,
$=\angle \text{CAD}=\angle \text{CDB}=65^\circ$
$=\angle \text{ACD}=\angle \text{DBA}=115^\circ$






























