MCQ 11 Mark
Mark against the correct answer in the following: A tree $6m$ tall casts a $4m$ long shadow. At the same time a flag pole casts a $50m$ long shadow. How long is the flag pole$?$
- A
$50m$
- ✓
$75m$
- C
$33\frac{1}{3}\text{m}$
- D
Answer$4m$ long shadow is of a tree of height $= 6m$
$1m$ long shadow of flagpole will of height $=\frac{6}{4}\text{m}$
$50m$ long shadow, the height of pole $6$ will be $=\frac{6}{4}\times50=75\text{m}$
View full question & answer→MCQ 21 Mark
Mark against the correct answer in the following:
A garrison of $500$ men had provisions for $27$ days. After $3$ days, a reinforcement of $300$ men arrived. The remaining food will now last for how many days$?$
AnswerCorrect option: A. $15$ days
$27$ days $-\ 3$ days $= 24$ days
Men $= 500 + 300 = 800$
For $500$ men, provision is sufficient $= 24$ days
For $1$ man, provision will be $= 24 \times 500 ($less man, more days$)$
and for $500 + 300 = 800$ men provision
will be sufficient $=\frac{24\times500}{800}=15\text{ days}$
$($more men, less days$)$
View full question & answer→MCQ 31 Mark
Mark against the correct answer in the following: If $4.5\ m$ of a uniform rod weighs $17.1\ kg,$ what is the weight of $12\ m$ of such a rod$?$
- A
$51.2\ kg$
- B
$53\ kg$
- ✓
$45.6\ kg$
- D
$56\ kg$
AnswerCorrect option: C. $45.6\ kg$
Weight of $4.5m$ rod $= 17.1\ kg$
Wight of $1\ m$ rod $=\frac{17.1}{4.5}\text{kg}$
And wight of $12\ m$ rod
$=\frac{17.1\times12}{4.5}=\frac{171\times12\times100}{100\times45}\text{kg}$
$=\frac{19\times12}{5}=\frac{228}{5}=45.6\text{kg}$
View full question & answer→MCQ 41 Mark
Mark against the correct answer in the following: $6$ dozen eggs are bought for $Rs.108.$ How much will $108$ eggs cost$?$
- A
$Rs. 171$
- ✓
$Rs. 162$
- C
$Rs. 153$
- D
$Rs. 180$
AnswerCorrect option: B. $Rs. 162$
Cost of $72$ eggs $= Rs.108$
Cost of $1$ egg $=\text{Rs. }\frac{108}{72}$
Cost of $108$ eggs $=\text{Rs. }\frac{108\times108}{72}=\text{Rs. }162$
View full question & answer→MCQ 51 Mark
Mark against the correct answer in the following: In a race, Raghu covers $5\ km$ in $20$ minutes, how much distance will he cover in $50$ minutes $?$
- A
$10.5\ km$
- B
$12\ km$
- ✓
$12.5\ km$
- D
$13.5\ km$
AnswerCorrect option: C. $12.5\ km$
In $20$ minutes, Raghu covers $= 5\ km$
in $1$ minutes, he will cover $=\frac{5}{10}\text{km}$
and in $50$ minutes, he will cover
$=\frac{5}{10}\times50$
$=\frac{25}{2}=12.5\text{km}$
View full question & answer→MCQ 61 Mark
Mark against the correct answer in the following: If $\frac{4}{5}$ of a cistern is filled in $1$ minute, how much more time will be required to fill the rest of it?
- A
$20$ seconds
- ✓
$15$ seconds
- C
$12$ seconds
- D
$10$ seconds
AnswerCorrect option: B. $15$ seconds
Total cistern $= 1$
Filled in $1$ minute $=\frac{4}{5}$
Unfilled $=1-\frac{4}{5}=\frac{1}{5}$
$\frac{4}{5}$ cistern is filled in $= 1$ minutes $= 60$ seconds
$1$ full cistern can be filled in $=\frac{60\times5}{4}=75$ seconds
More time $= 75 - 60 = 15$ seconds
View full question & answer→MCQ 71 Mark
Mark against the correct answer in the following: $10$ men can finish the construction of a wall in $8$ days. How many men are added to finish the work in half a day $?$
AnswerA wall is constructed in $8$ days by $= 10$ men
It will be constructed in $1$ day by $= 10 × 8$ men $($less time, more men$) 10 × 8$
And it will be constructed in $\frac{1}{2}=\frac{10\times8}{\frac{1}{2}}$
$=\frac{10\times8\times2}{1}=160\text{ men}$
More men required $= 160 - 10 = 150$
View full question & answer→MCQ 81 Mark
Mark against the correct answer in the following:
In a map, $1\ cm$ represents $8\ km.$ How much distance will be represented by $80.5\ cm?$
- A
$640\ km$
- B
$642\ km$
- ✓
$644 \ km$
- D
$648 \ km$
AnswerCorrect option: C. $644 \ km$
$644\ km$
$1\ cm$ represents $8\ km.$
$\therefore 80.5\ cm$ represents $8 \times 80.5 = 644\ km.$
View full question & answer→MCQ 91 Mark
Mark against the correct answer in the following: In a map, $0.8\ cm$ represents $8.8\ km.$ How much distance will be represented by $80.5\ cm?$
- A
$805\ km$
- B
$855.5\ km$
- C
$644\ km$
- ✓
AnswerNone of these $0.8\ cm$ represent the map $= 8.8\ km$
$1\ cm$ will represent on the map $=\frac{8.8}{0.8}\text{km}$
$\therefore 80.5\ cm$ will represent on the map
$=\frac{8.8\times80.5}{0.8}=\frac{88\times805\times10}{10\times8\times10}$
$=\frac{8855}{10}=885.5\text{km}$
View full question & answer→MCQ 101 Mark
Mark against the correct answer in the following: $45$ cows can graze a field in $12$ days. How many cows will graze the same field in $9$ days?
AnswerCorrect option: A. $60$ days
Number of cows that graze the field in $12$ days $= 45$
Number of cows that graze the field in $1$ day $= 45 \times 12$
$\therefore$ Number of cows that graze the field in $9$ days $=\frac{45\times12}{9}=60$
View full question & answer→MCQ 111 Mark
Mark against the correct answer in the following: A garrison of $500$ men had provisions for $24$ days. However, a reinforcement of $300$ men arrived. The food will now last for:
AnswerCorrect option: D. $15$ days
No. of men in the beginning $= 500$
More men arrived $= 300$
No. of total men $= 500 + 300 = 800$
For $500$ men, provision are for $= 24$ days
For $1$ man, provision will be $= 24 \times 500$ days $($less men, more days$)$
and for $800$ men, provision will be $=\frac{24}{800}\times500\text{ days}$
$($more men less days$)$
$= 15$ days
View full question & answer→MCQ 121 Mark
Mark against the correct answer in the following: If $16$ men can reap a field in $30$ days. In how many days will $20$ men reap the same field?
AnswerCorrect option: B. $24 \text{ days}$
$16$ men can reap a field in $= 30$ days
$1$ man will reap the field in $= 30 \times 16$ days
and $20$ men will reap the field in $=\frac{30\times16}{20}=24\text{ days}$
View full question & answer→MCQ 131 Mark
Mark against the correct answer in the following: If $16$ men can reap a field in $30$ days, in how many days will $20$ men reap the same field$?$
AnswerCorrect option: A. $24 \text{ days}$
$16$ men can reap the field in $30$ days.
$1$ man can reap the field in $30 \times 16$ days. $[$Less men, more days$]$
$\therefore 20$ men can reap the field in $\frac{30\times16}{20}=24\text{ days} [$More men, less days$]$
View full question & answer→MCQ 141 Mark
Mark against the correct answer in the following: $8$ men can finish a piece of work in $40$ days. If $2$ more men join them, the work will be completed in
- A
$30$ days
- ✓
$32$ days
- C
$36$ days
- D
$25$ days
AnswerCorrect option: B. $32$ days
$8$ men can finish the work in $= 40$ days
$1$ man will finish it in $= 40 \times 8$ days $($less men, more days$)$
$8 + 2 = 10$ men will finish it in $=\frac{40\times8}{10}\text{ days}$
$($more men, less days$)$
$= 32$ days.
View full question & answer→MCQ 151 Mark
Mark against the correct answer in the following: $12$ workers take $4$ hours to complete a job. How long would it take $15$ workers to complete the job$?$
- A
$2$ hrs $40$ min
- ✓
$3$ hrs $12$ min
- C
$3$ hrs $24$ min
- D
$3$ hrs $30$ min
AnswerCorrect option: B. $3$ hrs $12$ min
$12$ workers take to complete the work $= 4$ hrs.
$1$ worker will take $= 4 × 12$ hrs. $($less worker, more time$)$
$15$ workers will take $=\frac{4\times12}{15}$ hrs. $($more workers, less time$)$
$=\frac{16}{5}\text{ hr}=3\text{ hrs. }12\text{ min} $
View full question & answer→MCQ 161 Mark
Mark against the correct answer in the following: $10$ pipes of the same diameter can fill a tank in $24$ minutes. If $2$ pipes go out of order, how long will the remaining pipe take to fill the tank$ ?$
AnswerCorrect option: C. $30$ min
$10$ pipe can fill tank in $= 24$ minutes
$1$ pipe will fill it in $= 24 × 10$ minutes $($less pipe, more time$)$
and $10 - 2 = 8$ pipes will fill the tank in
$=\frac{24\times10}{8}=30$ minutes.
View full question & answer→MCQ 171 Mark
Mark against the correct answer in the following: If $21$ cows eat as much as $15$ buffaloes, how many cows will eat as much as $35$ buffaloes$?$
AnswerNumber of cows that eat as much as $15$ buffaloes $= 21$
Number of cows that eat as much as $1$ buffalo $=\frac{21}{15}$
$\therefore$ Number of cows that eat as much as $35$ buffaloes $=\frac{21}{15}\times35=49$
View full question & answer→MCQ 181 Mark
Mark against the correct answer in the following: A rope makes $140$ rounds of the circumference of a cylinder, the radius of whose base is $14\ cm.$ How many times can it go round a cylinder with radius $20\ cm ?$
AnswerNo. of rounds of rope $= 140$
Radius of base of cylinder $= 14\ cm$
Radius of second cylinder of cylinder $= 20\ cm$
If radius is $14\ cm,$ then rounds of rope are $= 140$
If radius is $1\ cm,$ then round $= 140 × 14 ($less radius more rounds$)$
and if radius is $20\ cm,$ then rounds will
be $=\frac{140\times14}{20}=98 ($more radius less rounds$)$
View full question & answer→MCQ 191 Mark
Mark against the correct answer in the following: If $21$ cows eat as much as $15$ buffaloes, how many cows will eat as much as $35$ buffaloes$?$
Answer$15$ buffaloes can eat as much as $= 21$ cows
$1$ buffalo will eat as much as $=\frac{21}{15}\text{ cows}$
$35$ buffaloes will eat as much as
$=\frac{21\times35}{15}\text{cm}=49\text{ cows}$
View full question & answer→MCQ 201 Mark
Mark against the correct answer in the following: A worker makes a toy every $\frac{2}{3}$ hour. If he works for $7\frac{1}{3}$ hours, then how many toys will he make $?$
AnswerA worker makes toy in $\frac{2}{3}\text{hr}=1$
He will make toys in $1$ hr $=1\times\frac{3}{2}$
and will make toys in $\frac{22}{3}\text{ hrs}=1\times\frac{3}{2}\times\frac{22}{3}$
$= 11 ($more time more toys$)$
View full question & answer→MCQ 211 Mark
Mark against the correct answer in the following: $6$ dozen eggs are bought for $Rs. 108.$ How much will $132$ eggs cost$ ?$
- A
$Rs. 204$
- B
$Rs. 264$
- C
$Rs. 184$
- ✓
$Rs. 198$
AnswerCorrect option: D. $Rs. 198$
$6$ dozen or $6 \times 12 = 72$ eggs
Cost of $72$ eggs is $= Rs. 108$
Cost of $1$ egg will be $\text{Rs. }\frac{108}{72}$
and cost of $132$ eggs will be $108$
$\text{Rs. }\frac{108}{72}\times132=\text{Rs. }198$
View full question & answer→MCQ 221 Mark
10 men can finish the construction of a wall in 8 days. How many men are added to finish
the work in half a day?
MCQ 231 Mark
A worker makes a toy every $\frac{2}{3}$ hour. If he works for $7 \frac{1}{3}$ hours, then how many toys will he make?
View full question & answer→MCQ 241 Mark
А rоpe makes 140 rounds of the circumference of a cylinder, the radius of whose base is
14 cm. How many times can it go round a cylinder with radius 20 cm?
MCQ 251 Mark
Agarrison of 500 men had provisions for 27 days. After 3 days, a reinforcement of 300 men
arrived. The remaining food will now last for how many days?
- ✓
- B
- C
$17 \frac{1}{2}$ days
- D
View full question & answer→MCQ 261 Mark
12 workers take 4 hours to complete a job. How long would it take 15 workers to complete
the job?
MCQ 271 Mark
6 dozen eggs are bought for Rs 108. How much will 132 eggs cost?
MCQ 281 Mark
10 pipes of the same diameter can fill a tank in 24 minutes. If 2 pipes go out of order, how long will the remaining pipe take to fill the tank?
MCQ 291 Mark
If 16 men can reap a field in 30 days, in how many days will 20 men reap the same field?
- A
$10 \frac{2}{3}$ days
- ✓
- C
- D
$37 \frac{1}{2}$ days
View full question & answer→MCQ 301 Mark
8 men can finish a piece of work in 40 days. If 2 more men join them, the work will be completed in
MCQ 311 Mark
A tree, 6 m tall, casts a 4-m-long shadow. At the same time a flag pole casts a 50-m-long shadow. How long is the flag pole?
MCQ 321 Mark
If 21 cows eat as much as 15 buffaloes, how many cows will eat as much as 35 buffalocs?
MCQ 331 Mark
If $\frac{4}{5}$ of a cistern is filled in 1 minute, how much more time will be required to fill the rest of it?
View full question & answer→MCQ 341 Mark
A garrison of 500 men had provisions for 24 days. However, a reinforcement of 300 men arrived. The food will now last for
- A
- B
$17 \frac{1}{2}$ days
- C
- ✓
View full question & answer→MCQ 351 Mark
In a race, Raghu covers 5 km in 20 minutes, how much distance will he cover in 50 minutes?
MCQ 361 Mark
In a map, 0.8 cm represents 8.8 km. How much distance will be represented by 80.5 cm?
MCQ 371 Mark
If 4.5 m of a uniform rod weighs 17.1 kg, what is the weight of 12 m of such a rod?