Question 15 Marks
A die is thrown at random. Find the probability of getting:
$i. 2.$
$ii.$ A number less than $3.$
$iii.$ A composite number.
$iv.$ A number not less than $4.$
$i. 2.$
$ii.$ A number less than $3.$
$iii.$ A composite number.
$iv.$ A number not less than $4.$
Answer
View full question & answer→A die is thrown, then. Possible outcomes $= 6$
$i.$ Now probability of getting $2=\frac{1}{6}$
$ii.$ Probability of a number less than $3 ($which are $1$ and $2) =\frac{2}{6}=\frac{1}{3}$
$iii.$ probability of a composite number $($a composite number is a number which is not a prime number which are $4, 6)=\frac{2}{6}=\frac{1}{3}$
$iv.$ probability of a number not less than $4 ($which are $5, 6) =\frac{2}{6}=\frac{1}{3}$
$i.$ Now probability of getting $2=\frac{1}{6}$
$ii.$ Probability of a number less than $3 ($which are $1$ and $2) =\frac{2}{6}=\frac{1}{3}$
$iii.$ probability of a composite number $($a composite number is a number which is not a prime number which are $4, 6)=\frac{2}{6}=\frac{1}{3}$
$iv.$ probability of a number not less than $4 ($which are $5, 6) =\frac{2}{6}=\frac{1}{3}$