Question 13 Marks
Hema bought two pairs of jeans for $Rs. 1450$ each. She sold one of them at a gain of $8\%$ and the other at a loss of $4\%$. Find her gain or loss percent in the whole transaction.
Answer$CP$ of first jeans $= Rs. 1,450$
Profit $= 8\%$ of $CP$ $=\frac{8}{100}\times1450=\times1450=\text{Rs. }116$
$SP$ of first jeans $= Rs. 1,450 + Rs. 116 = Rs. 1,566$
$CP$ of second jeans $= Rs. 1,450$ Loss $= 4\%$ of $CP =\frac{4}{100}\times1450=\text{Rs. }58$
$SP$ of second jeans $= Rs. 1450 - Rs. 58 = Rs. 1,392$
Total $CP$ of two jeans $= CP$ of first jeans $+\ CP$ of second jeans $= Rs. 1,450 + Rs. 1,450 = Rs. 2,900$
Total $SP$ of two jeans $= SP$ of first jeans $+\ SP$ of second jeans $= Rs. 1,566 + Rs. 1,392 = Rs. 2,958$
Here, Total $SP$ of two jeans $ > $ Total $CP$ of two jeans Gain $=$ Total $SP$ of two jeans $-$ Total $CP$ of two jeans $= Rs. 2,958 - Rs. 2,900 = Rs. 58$
$\therefore$ Gain $\% =\frac{\text{gain}}{\text{total CP of two jeans}}\times100\%=\frac{58}{2900}\times100=2\%$
View full question & answer→Question 23 Marks
A radio is sold for $Rs. 3120$ at a loss of $4\%.$ What will be the gain or loss percent if it is sold for $Rs. 3445?$
AnswerLet the original price be $x$
$SP = Rs. 3120$
Now, $SP = CP\ -$ loss
$\Rightarrow3120=\text{x}-\frac{4}{100}$
$\Rightarrow3120=\text{x}-\frac{\text{x}}{100}$
$\Rightarrow3120=\frac{\text{24x}}{100}$
$\Rightarrow\frac{3120\times25}{100}=\text{x}$
$\Rightarrow\text{x}=3250$
So, the cost price is $Rs. 3250$
If it is sold for $Rs.3445,$ then its a gain because $SP > CP.$
Now, gain $= SP - CP = Rs. (3445 - 3250) = Rs. 195$
$\therefore$ Gain percentage $=\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{195}{3250}\times100\Big)\%=6\%$ Hence, gain percent $= 6\%$
View full question & answer→Question 33 Marks
A jeweller allows a discount of $16\%$ to his customers and still gains $20\%$. Find the marked price of a ring which costs the jeweller $Rs. 1190.$
AnswerCost price of the refrigerator $= Rs. 1190$
Gain percentage $= 20\%.$
$\therefore$ Selling price $=\Big\{\frac{(100+\text{gain}\%)}{100}\times\text{CP}\Big\}$
$=\Big\{\frac{100+20}{100}\times1190\Big\}$
$=\frac{120}{100}\times1190\ \text{Rs. }1428$
Let the marked price be $Rs. x$
Discount $= 16\%$ of $Rs. x=\frac{16\text{x}}{100}$
$S.P = MP\ - $ Discount
$\Rightarrow1428=\text{x}-\frac{16\text{x}}{100}$
$\Rightarrow1428=\frac{100\text{x}-16\text{x}}{100}$
$\Rightarrow142800=84\text{x}$
$\Rightarrow\text{x}=\frac{142800}{84}=\text{x}$
$\Rightarrow\text{x}=1700$
Therefore, the marked price of the ring is $Rs. 1700$
View full question & answer→Question 43 Marks
A dealer gets $Rs. 56$ less if instead of selling a chair at a gain of $15\%$, it is sold at a gain of $8\%.$ Find the cost price of the chair.
AnswerLet $Rs. x$ be the $CP$
Gain$_1 \text { percentage }=\left(\frac{\operatorname{gain}_1}{CP} \times 100\right) \% $
$\Rightarrow 15=\frac{\operatorname{gain}_1}{ x } \times 100$
$\Rightarrow \text { Gain }_1=\text { Rs. } \frac{15 x}{100}$
Again, gain $_2$ percentage $=\left(\frac{\text { gain }_1}{ CP } \times 100\right) \%$
$\Rightarrow 8=\frac{\text { gain }_2}{x} \times 100$
$\Rightarrow \text { Gain }_2=\text { Rs. } \frac{8 x}{100}$
According to the question, we have:
$\text { Gain }_1-\text { gain }_2=56$
$\Rightarrow \frac{15 x}{100}-\frac{8 x}{100}=56$
$\Rightarrow \frac{7 x}{100}=56$
$\Rightarrow 7 x=5600$
$\Rightarrow x=800$
Hence, the $CP$ of the chair is $Rs.800$
View full question & answer→Question 53 Marks
Oranges are bought at $6$ for $Rs. 20$ and sold at $4$ for $Rs. 18.$ Find the gain or loss percent.
Answer$CM$ of $6$ and $4 = 12$
Let the number of oranges bought be $12\ CP$ of $6$ oranges $= Rs. 20$
So, $CP$ of $1$ orange $=\frac{20}{6}=\text{Rs. }\frac{10}{3}$
$CP$ of $12$ orange $=12\times\frac{10}{3}=\text{Rs. }40$
$SP$ of $4$ oranges $=\text{Rs. }18$
$SP$ of $1$ orange $=\frac{18}{4}=\text{Rs. }\frac{9}{2}$
$SP$ of $12$ oranges $=12\times\frac{9}{2}=\text{Rs. }54$
Here, $SP$ of $12$ oranges $> CP$ of $12$
oranges Profit $= SP - CP = Rs. 54 - Rs. 40 = Rs. 14$
$\therefore$ Profit $\% =\frac{\text{profit}}{\text{CP}}\times100\%=\frac{14}{40}\times100\%=35\%$
View full question & answer→Question 63 Marks
Wasim bought two cricket bats for $Rs. 840$ and $Rs. 360$ respectively. He sells the first bat at a gain of $15\%$ and the second one at a loss of $5\%.$ Find his gain or loss percent in the whole transaction.
Answer$CP$ of the first bat $= Rs. 840$
Profit$\%$ on the first bat $= 15\%$
$\therefore$ Profit $= 15\%$ of $\text{Rs. }840=\frac{15}{100}\times840=\text{Rs. }126$
$SP$ of the first bat $= Rs. 840 + Rs. 126 = Rs. 966$
$CP$ of the second bat $= Rs. 360$
Loss $= 5\%$ of $=\text{Rs. }360=\frac{5}{100}\times360=\text{Rs.}18$
$SP$ of the second bat $= Rs. 360 - Rs. 18 = Rs. 342$
Total $CP$ of two bats $= CP$ of first bat $+\ CP$ of second bat $= Rs. 840 + Rs. 360 = Rs. 1,200$
Total $SP$ of two bats $= SP$ of first bat $+\ SP$ of second bat $= Rs. 966 + Rs. 342 = Rs. 1,308$
Here, Total $SP$ of two bats $ > $ Total $CP$ of two bats Gain $=$ Total $SP$ of two bats $-$ Total $CP$ of two bats $= Rs. 1,308 - Rs. 1,200 = Rs. 108$
$\therefore$ Gain% in the whole transaction $=\frac{\text{gain}}{\text{total CP of two bats}}\times100\%=\frac{108}{1200}\times100=9\%$
View full question & answer→Question 73 Marks
A dealer purchased a fan for $Rs. 1080.$ After allowing a discount of $25\%$ on its marked price, he gains $25\%.$ Find the marked price of the fan.
AnswerCost price of the fan $= Rs. 1080$
Gain percentage $= 25\%$
$\therefore$ Selling price $=\Big\{\frac{(100+\text{gain}\%)}{100}\times\text{CP}\Big\}$
$=\Big\{\frac{100+25}{100}\times1080\Big\}$
$=\frac{125}{100}\times1080\ \text{Rs. }1350$
Let the marked price be $Rs. x$
Discount $= 25\%$ of $Rs. x$
$=\frac{25\text{x}}{100}$
$SP = MP\ -$ discount
$\Rightarrow1350=\text{X}-\frac{25\text{X}}{100}$
$\Rightarrow1350=\frac{100\text{x}-25\text{x}}{100}$
$\Rightarrow1350=75\text{x}$
$\Rightarrow\text{x}=\frac{13500}{75}$
$\Rightarrow\text{x}=1800$
Therefore, the marked price of the fan is $Rs. 1800$
View full question & answer→Question 83 Marks
How much percent above the cost price should a shopkeeper mark his goods so that after allowing a discount of $10\%$ on the marked price, he gains $8\%?$
AnswerLet $Rs. 100$ be the cost price.
Gain required $= 8\%$
Therefore, the selling price $= Rs. 108$
Let $Rs. x$ be the marked price
Then, discount $= 10\%$ of $Rs. x$
$=\frac{10}{100}\times\text{x}=\frac{\text{x}}{10}$
Selling price $= MP\ -$ Discount
$\Rightarrow117=\text{x}-\frac{\text{x}}{10}$
$\Rightarrow117=\frac{9\text{x}}{10}$
$\Rightarrow9\text{x}=1080$
$\Rightarrow\text{x}=\frac{1080}{9}$
$\Rightarrow\text{x}=120$
$\therefore$ Marked price $= Rs. 120$
Hence, the marked price is $20\%$ above the cost price.
View full question & answer→Question 93 Marks
By selling a bouquet for $Rs. 322,$ a florist gains $15\%.$ At what price should he sell it to gain $25\%?$
Answer$SP$ of the bouquet $= Rs. 322$
Gain percentage $= 15\%$
$CP$ of the bouquet $=\Big(\frac{100}{100+\text{gain}\%}\Big)\times\text{SP}$
$=\text{Rs. }\Big(\frac{100}{100+150}\Big)\times322$
$=\text{Rs. }\frac{100}{115}\times322$
$=\text{Rs. }280$
Now, $CP = Rs. 128$ and desired gain percentage $= 25\%$
$\therefore$ Desired SP $=\Big(\frac{100}{100+\text{gain}\%}\Big)\times\text{CP}$
$=\text{Rs. }\frac{125}{100}\times280$
$=\text{Rs. }350$
Hence, the selling price to obtain the desired gain must be $Rs. 350.$
View full question & answer→Question 103 Marks
If the selling price of $16$ water bottles is equal to the cost price of $17$ water bottles, find the gain percent earned by the dealer.
AnswerLet $Rs. x$ be the $SP$ of each bottle and $Rs. y$ be the $CP$ of each bottle.
$SP$ of $16$ bottles $= CP$ of $17$ bottles.
$\Rightarrow 16x = 17y$
$\Rightarrow\frac{\text{x}}{\text{y}}=\frac{17}{16}$
Gain per bottle $= SP - CP = Rs. x - y$
$\therefore$ Gain percentage $=\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{\text{x}-\text{y}}{\text{y}}\times100\Big)\%$
$=\Big\{\big(\frac{\text{x}}{\text{y}}-1\big)\times100\Big\}\%$
$=\Big\{\big(\frac{17}{16}-1\big)\times100\Big\}\%$
$=\Big(\frac{1}{16}\times100\Big)\%$
$=6\frac{1}{4}\%$
View full question & answer→Question 113 Marks
After allowing a discount of $10\%$ on the marked price, a trader still makes a gain of $17\%.$ By what percent is the marked price above the cost price$?$
AnswerLet $Rs. 100$ be the cost price.
Gain required $= 17\%$
$\therefore$ Selling price $= Rs. 117$
Let the marked price be $Rs. x$
Then, discount $= 10\%$ of $Rs. x$
$=\frac{10}{100}\times\text{x}=\frac{\text{x}}{10}$
Selling price $= MP\ -$ Discount
$\Rightarrow117=\text{x}-\frac{\text{x}}{10}$
$\Rightarrow117=\frac{9\text{x}}{10}$
$\Rightarrow9\text{x}=1170$
$\Rightarrow\text{x}=\frac{1170}{9}$
$\Rightarrow\text{x}=130$
$\therefore$ Marked price $= Rs. 130$
Hence, the marked price is $30\%$ above the cost price.
View full question & answer→Question 123 Marks
A vendor purchased bananas at $Rs. 40$ per dozen and sold them at $10$ for $Rs. 36.$ Find his gain or loss percent.
Answer$LCM$ of $12$ and $10 = 60$
Let the number of banana bought be $60.$
$ CP$ of $12$ banana $= Rs. 40$
$\therefore CP$ of $1$ banana $=\frac{40}{12}=\text{Rs. }\frac{10}{3}$
$\Rightarrow CP$ of $60$ bananas $=60\times\frac{10}{3}=\text{Rs. }200$
$SP$ of $10$ bananas $=\text{Rs. }36$
$\therefore SP$ of $10$ bananas $=\frac{36}{10}=\text{Rs. }\frac{18}{5}$
$\Rightarrow SP$ of $60$ bananas $=60\times\frac{18}{5}=\text{Rs. }216$
Here, $SP$ of $60$ bananas $> CP$ of $60$ bananas.
Profit $= SP - CP = Rs. 216 - Rs. 200 = Rs. 16$
$\therefore$ Profit $\% =\frac{\text{profit}}{\text{CP}}\times100\%=\frac{14}{40}\times100\%=8\%$
View full question & answer→Question 133 Marks
Coffee costing $Rs. 250/kg$ was mixed with chicory costing $Rs. 75/kg$ in the ratio $5 : 2$ for a certain blend. If the mixture was sold at $Rs. 230/kg,$ find the gain or loss percent.
AnswerLet $5kg$ of coffee be mixed with $2kg$ of chicory.
$CP$ of the mixture $= Rs. (250 × 5 + 75 × 2) = Rs. (1250 + 150) = Rs. 1400$
$SP$ of the mixture $= Rs. (7 × 230) = Rs. 1610$
Since $SP > CP,$ there is a gain.
Now, gain $= Rs. (1610 - 1400) = Rs. 210$
Gain precentage $=\Big(\frac{\text{gain}}{\text{total CP}}\times100\Big)\%$
$=\Big(\frac{210}{1400}\times100\Big)\%$
$=15\%$
View full question & answer→Question 143 Marks
By selling $130$ cassettes, a man gains an amount equal to the selling price of $5$ cassettes. Find the gain percent.
AnswerIt is given that, Gain $= SP$ of $5$ cassettes $...(1)$
Gain $= SP$ of $130$ cassettes $-\ CP$ of $130$ cassettes
$\Rightarrow SP$ of $5$ cassettes $=\ SP$ of $130$ cassettes $-\ CP$ of $130$ cassettes $[$From$(1)]$
$\Rightarrow CP$ of $130$ cassettes $=\ SP$ of $125$ cassettes $...(2)$
Let the $CP$ of $1$ cassette be $Rs. x$
$\therefore CP$ of $125$ cassettes $= Rs. 125x$
$CP$ of $130$ cassettes $= Rs. 130x$
$SP$ of $125$ cassettes $= CP$ of $130$ cassettes $[$From $(2)]$
$\Rightarrow SP$ of $125$ cassettes $= Rs. 130x$
Now, gain $\% =\frac{\text{SP}-\text{CP}}{\text{CP}}\times100\%=\frac{(130\text{x}-125\text{x})}{125\text{x}}\times100\%$
$=\frac{5\text{x}}{125\text{x}}\times100\%=4\%$
Thus, the gain percent is $4\%$
View full question & answer→Question 153 Marks
A dealer bought a refrigerator for $Rs. 11515.$ After allowing a discount of $16\%$ on its marked price, he gains $20\%.$ Find the marked price of the refrigerator.
AnswerCost price of the refrigerator $= Rs. 11515$
Gain percentage $= 20\%.$
$\therefore$ Selling price $=\Big\{\frac{(100+\text{gain}\%)}{100}\times\text{CP}\Big\}$
$=\Big\{\frac{100+20}{100}\times11515\Big\}$
$=\frac{120}{100}\times11515=\text{Rs. }13818$
Let the marked price be $Rs. x$
Discount $= 16\%$ of $Rs. x =\frac{16\text{x}}{100}$
$S.P = MP\ -$ Discount
$\Rightarrow13818=\text{x}-\frac{16\text{x}}{100}$
$\Rightarrow13818=\frac{100\text{x}-16\text{x}}{100}$
$\Rightarrow1381800=84\text{x}$
$\Rightarrow\text{x}=\frac{1381800}{84}$
$\Rightarrow\text{x}=16450$
Therefore, the marked price of the refrigerator is $Rs. 16450$
View full question & answer→Question 163 Marks
A man purchased some eggs at $3$ for $Rs. 16$ and sold them at $5$ for $Rs. 36.$ Thus, he gained $Rs. 168$ in all. How many eggs did he purchase$?$
AnswerLet the number of eggs purchased be $x$
$CP$ of $3$ eggs $= Rs. 16$
$\therefore CP$ of $1$ egg $=\text{Rs. }\frac{16}{3}$
$\Rightarrow CP$ of $x$ eggs $=\text{Rs. }\frac{16}{3}\text{x}$ $SP$ of $5$ eggs $=\text{Rs. }36$
$\therefore SP$ of $1$ egg $=\text{Rs. }\frac{36}{5}$ $\Rightarrow SP$ of $x$ eggs $=\text{Rs. }\frac{36}{5}\text{x}$
Gain $= SP - CP = Rs. 168$
$\therefore\frac{36}{5}\text{x}-\frac{16}{3}\text{x}=168$
$\Rightarrow\frac{28}{15}\text{x}=168$
$\Rightarrow\text{x}=\frac{168\times15}{28}$
$\Rightarrow\text{x}=90$ Hence, the man purchased $90$ eggs.
View full question & answer→Question 173 Marks
A dealer marks his goods at $35\%$ above the cost price and allows a discount of $20\%$ on the marked price. Find the gain or loss percent.
AnswerLet $Rs. 100$ be the $CP$
Then, marked price $= Rs. 135$
Discount $= 20\%$ of $MP =\frac{20}{100}\times135=27$
Selling price $=$ marked price $-$ discount $= 135 - 27 = Rs. 108$
Now, gain $= SP - CP = 108 - 100 = Rs. 8$
$\therefore$ Gain percentage $=\frac{\text{gain}}{\text{CP}}\times100$
$=\frac{8}{100}\times100=8\%$
View full question & answer→Question 183 Marks
The marked price of a $TV$ is $Rs. 18500.$ A dealer allows two successive discounts of $20\%$ and $5\%.$ For how much is the $TV$ available$?$
AnswerMarked price of the $TV = Rs. 18500$
First discount $= 20\%$
Now, $20\%$ of $18500$
$=\frac{20}{100}\times18500=\text{ Rs. }3700$
Price after the first discount $= Rs. (18500 - 3700)= Rs. 14800$
Second discount $= 5\%$ of $14800$
$=\frac{5}{100}\times14800=740$
Price after the second discount $= (14800 - 740) = Rs. 14060$
The $TV$ is available for $Rs. 14060$
View full question & answer→Question 193 Marks
A cellphone was marked at $40\%$ above the cost price and a discount of $30\%$ was given on its marked price. Find the gain or loss percent made by the shopkeeper.
AnswerLet $Rs. 100$ be the $CP$
Then, marked price $= Rs. 140$
Discount $= 30\%$ of $MP =\frac{30}{100}\times140=42$
Selling Price $=$ marked price $-$ discount $= 140 - 42 = Rs. 98$
Now, loss $= CP - SP = 100 - 98 = Rs. 2$
$\therefore$ Loss percentage $=\frac{\text{loss}\times100}{\text{CP}}$
$=\frac{2\times100}{100}=2\%$
Therefore, the shopkeeper had a loss of $2\%.$
View full question & answer→Question 203 Marks
A dealer gets $Rs. 940$ more if instead of selling a table at a loss of $10\%,$ it is sold at a gain of $10\%.$ Find the cost price of the table.
AnswerLet the cost price be $Rs. x.$
Loss $= 10\%$ of $\text{Rs. }\text{x}=\frac{10}{100}\text{x}=\text{Rs. }\frac{\text{x}}{10}$
$SP$ in case of loss $= CP\ -$ Loss $=\text{x}-\frac{\text{x}}{10}=\text{Rs. }\frac{9\text{x}}{10}$
Gain $= 10\%$ of $\text{Rs. }\text{x}=\frac{10}{100}\text{x}=\text{Rs.}\frac{\text{x}}{10}$
$SP$ in case of profit $= CP\ +$ Profit $=\text{x}+\frac{\text{x}}{10}=\text{Rs. }\frac{11\text{x}}{10}$
It is given that dealer gets $Rs. 940$ more if sold at a profit of $10\%$ instead of loss of $10\%.$
$\therefore$ SP in case of profit $-\ SP$ in case of loss $= Rs. 940$
$\Rightarrow\frac{11\text{x}}{10}-\frac{9\text{x}}{10}=940$
$\Rightarrow\frac{2\text{x}}{10}=940$
$\Rightarrow\text{x}=4700$
Hence, the cost price of the table is $Rs. 4,700$
View full question & answer→Question 213 Marks
Sonu buys $40\ kg$ of wheat at $Rs. 12.50/kg$ and $30\ kg$ of wheat at $Rs. 14/kg.$ At what rate $/kg$ should he sell the mixture to gain $5\%$ on the whole$?$
Answer$40\ kg$ of wheat is bought for $Rs. 12.50/kg$
$\therefore CP$ of $40\ kg$ of wheat $= 40 \times 12.50 = Rs. 500$
$30\ kg$ of wheat is bought for $Rs. 14/kg$
$\therefore CP$ of $30\ kg$ of wheat $= 30 \times 14 = Rs. 420$
Total $CP = Rs. 500 + Rs. 420 = Rs. 920$
Profit $= 5\%$ of $ CP\ \text{Rs.}920=\frac{5}{100}\times920=46$
Let the $SP$ be $Rs. x$ Profit $= SP - CP$
$\Rightarrow x - 920 = 46$
$\Rightarrow x = Rs. 966$
$SP$ of $70\ kg$ wheat $= Rs. 966$
$\therefore SP$ of $1\ kg$ wheat $=\frac{966}{70}=13.80$
Thus, the selling price of the mixture is $Rs. 13.80/kg.$
View full question & answer→Question 223 Marks
Manjit bought an iron safe for $Rs. 12160$ and paid $Rs. 340$ for its transportation. Then, he sold it for $Rs. 12875.$ Find his gain percent.
Answer$CP$ of the iron safe $= Rs. 12,160$
Money spent on transportation $= Rs. 340$
Total $CP = Rs. 12,160 + Rs. 340 = Rs. 12,500$
$SP$ of the iron safe $= Rs. 12,875$
Profit $= SP - CP = Rs. 12,875 - Rs. 12,500 = Rs. 375$
$\therefore$ Profit $\% =\frac{\text{Profit}}{\text{CP}}\times100\%=\frac{375}{12500}\times100\%=3\%$
View full question & answer→Question 233 Marks
A man bought apples at $10$ for $Rs. 75$ and sold them at $Rs. 75$ per dozen. Find his loss percent.
Answer$LCM$ of $10$ and $12 = 60$
Let the number of apples bought be $60$
$CP$ of $10$ oranges $=\text{Rs. }75$
$\therefore CP$ of $1$ orange $=\text{Rs. }\frac{75}{10}$
$⇒ CP$ of $60$ orange $=60\times\frac{75}{10}=\text{Rs. }450$
$SP$ of $12$ oranges $=\text{Rs. }75$
$\therefore SP$ of $1$ orange $=\text{Rs. }\frac{75}{12}$
$⇒ SP$ of $60$ oranges $=60\times\frac{75}{12}=\text{Rs. }375$
Here, $CP$ of $60$ oranges $> SP$ of $60$ oranges.
Loss $= CP - SP = Rs. 450 - Rs. 375 = Rs. 75$
$\therefore$ Loss % $=\frac{\text{loss}}{\text{CP}}\times100\%=\frac{75}{450}\times100\%=16\frac{2}{3}\%$
View full question & answer→Question 243 Marks
By selling an umbrella for $Rs. 336,$ a shopkeeper loses $4\%.$ At what price must he sell it to gain $4\%$
AnswerLet the $CP$ of the umbrella be $Rs. x$
$SP$ of the umbrella $= Rs. 336$
Loss $= 4\%$ of $Rs. x =\text{Rs. }\frac{4}{100}\text{x}$
$CP\ -$ Loss $= SP$
$\Rightarrow\text{x}-\frac{\text{x}}{100}\text{x}=336$
$\Rightarrow\frac{96}{100}\text{x}=336$
$\Rightarrow\text{x}=\text{Rs. }350$
$\therefore CP $ of the umbrella $= Rs. 350$
Now, for gain of $4\%, SP = CP\ +$ Gain
$\Rightarrow\text{SP}=350+\frac{4}{100}\times350$
$\Rightarrow\text{SP}=350+14$
$\Rightarrow\text{SP}=364$
Hence, in order to gain $4\%$, the umbrella should be sold for $Rs. 364$
View full question & answer→Question 253 Marks
The cost price of $12$ candles is equal to the selling price of $15$ candles. Find the loss percent.
AnswerLet $Rs. x$ be the $CP$ of one candle and $Rs. y$ be the $SP$ of one candle.
Now, $CP$ of $12$ candles $= SP$ of $15$ candles.
$\Rightarrow 12\text{x} = 15\text{y}$
$\Rightarrow\frac{\text{x}}{\text{y}}=\frac{17}{16}$
Loss $= CP - SP = Rs. x - y$
$\therefore$ Loss percentage $=\Big(\frac{\text{loss}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{\text{x}-\text{y}}{\text{x}}\times100\Big)\%$
$=\Big\{\big(1-\frac{\text{y}}{\text{x}}\big)\times100\Big\}\%$
$=\Big\{\big(1-\frac{12}{15}\big)\times100\Big\}\%$
$=\Big(\frac{3}{15}\times100\Big)\%$
$=20\%$
View full question & answer→