Question 12 Marks
Find the area of a triangle whose base and altitude are $5\ cm$ and $4\ cm$ respectively.
Answer
View full question & answer→Area of a triangle say having base $5\ cm$ and altitude $4\ cm$ is given by:
$\text{A}=\frac12(\text{Base}\times\text{Height}),$
where Base $= 5\ cm$; Height $= 4\ cm \text{A}=\frac12(5\times4)$
$\text{A} = (5 \times 2)$
$\text{A} = 10\text{cm}^2.$
$\text{A}=\frac12(\text{Base}\times\text{Height}),$
where Base $= 5\ cm$; Height $= 4\ cm \text{A}=\frac12(5\times4)$
$\text{A} = (5 \times 2)$
$\text{A} = 10\text{cm}^2.$