Question 14 Marks
Draw the graph of the equation $x + 2y - 3 = 0$ From your graph, find the value of $y$ when,
$i. x = 5$
$ii. x = -5.$
Answer
View full question & answer→Given equation:$x + 2y - 3 = 0$
or, $x + 2y = 3$
When $y = 0, x + 0 = 3$
$ \Rightarrow x = 3 $
When $y = 1, x + 2 = 3 $
$\Rightarrow x = 3 - 2 = 1$
When $y = 2, x + 4 = 3$
$ \Rightarrow x = 3 - 4 = -1$
Thus, we have the following table:
Now plot the point $(3, 0), (1, 1)$ and $(-1, 2)$ on the graph paper.
Join the points and extend the line in both the directions.
The line segment is the required graph of the equation.
When $x = 5$$\text{y}=\frac{3-\text{x}}{2}$
$\Rightarrow\text{y}=\frac{3-5}{2}$
$\text{y}= -1$
Similarly, from the graph we can see that when $x = -5, y = 4$.
or, $x + 2y = 3$
When $y = 0, x + 0 = 3$
$ \Rightarrow x = 3 $
When $y = 1, x + 2 = 3 $
$\Rightarrow x = 3 - 2 = 1$
When $y = 2, x + 4 = 3$
$ \Rightarrow x = 3 - 4 = -1$
Thus, we have the following table:
|
$x$
|
$3$
|
$1$
|
$-1$
|
|
$y$
|
$0$
|
$1$
|
$2$
|
Join the points and extend the line in both the directions.
The line segment is the required graph of the equation.
When $x = 5$$\text{y}=\frac{3-\text{x}}{2}$
$\Rightarrow\text{y}=\frac{3-5}{2}$
$\text{y}= -1$
Similarly, from the graph we can see that when $x = -5, y = 4$.