2 Marks Questions

Question 12 Marks

The percentages of marks obtained by a student in six unit tests are given below:

Unit test	$I$	$II$	$III$	$IV$	$V$	$VI$
Percentage of marks obtained	$53$	$72$	$28$	$46$	$67$	$59$

A unit test is selected at random. What is the probability that the student gets more than 60% marks in the test?

Answer

Number of tests in which he gets more than $60\%$ marks $= 2$
Total numbers of tests $= 6$
$\therefore$ Required probability $=\frac{\text{Number of tests in which he gets more than $60\%$ marks}}{\text{Total number of trials}}$
$=\frac{2}{6}=\frac{1}{3}$

View full question & answer→

Question 22 Marks

The marks obtained by $90$ students of a school in mathematics out of $100$ are given as under:

Marks	$0 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$	$60 - 70$	$70$ and above
Number of students	$7$	$8$	$12$	$25$	$19$	$10$	$9$

From these students, a student is chosen at random. What is the probability that the chosen student:
$i. $Gets $20\%$ or less marks?
$ii$. Gets $60\%$ or more marks?

Answer

Total number of patients $= 90$
$i.$ Probability that the chosen student gets $20\%$ or less marks $=\frac{7}{90}$
$ii.$ Probability that the chosen student gets $60\%$ or more marks $=\frac{10+9}{90}=\frac{19}{90}$

View full question & answer→

Question 32 Marks

On a particular day, at a crossing in a city, the various types of $240$ vehicles going past during a time interval were observed, as under:

Types of vehicle	Two-wheelers	Three-wheelers	Four-wheelers
Frequency	$84$	$68$	$88$

Out of these vehicles, one is chosen at random. What is the probability that the chosen vehicle is a two-wheeler?

Answer

Total number of vehicles going past the crossing $= 240$
Number of two-wheelers $= 84$
Let E be the event that the selected vehicle is a two-wheeler. Then, required probability $= P(E) =\frac{84}{240}=0.35$

View full question & answer→

Question 42 Marks

$12$ Packets of salt, each marked 2kg, actually contained the following weights (in kg) of salt:
$1.950, 2.020, 2.060, 1.980, 2.030, 1.970, 2.040, 1.990, 1.985, 2.025, 2.000, 1.980.$
Out of these packets, one packet is chosen at random.
What is the probability that the chosen packet contains more than $2\ kg$ of salt?

Answer

Total number of salt packets $= 12$
Number of packets containing more than 2kg of salt $= 5$
Therefore,
Probability that the chosen packet contains more than $2\ kg$ of salt $=\frac{\text{No. of packets containing more than $2\ kg$ of salt}}{\text{Total number of salt packets}}$
$=\frac{5}{12}$

View full question & answer→

Maths 2 Marks Questions

Take a timed test