Question 512 Marks
Find the probability of the following, when one coin is tossed.
(i) getting head (ii) getting tail
(i) getting head (ii) getting tail
Answer
View full question & answer→Let ' $S$ ' be the sample space.
$\mathrm{S}=\{\mathrm{H}, \mathrm{T}\} \quad \mathrm{n}(\mathrm{S})=2$
(i) Let event $A$ be getting head
$\begin{array}{l}
A=\{H\} \
P(A)=\frac{n(A)}{n(S)}=\frac{1}{2}
\end{array}$
(ii) Let event $B$ be getting tail
$\begin{array}{l}
B=\{T\} \quad \therefore n(B)=1 \
P(B)=\frac{n(B)}{n(S)}=\frac{1}{2}
\end{array}$
$\mathrm{S}=\{\mathrm{H}, \mathrm{T}\} \quad \mathrm{n}(\mathrm{S})=2$
(i) Let event $A$ be getting head
$\begin{array}{l}
A=\{H\} \
P(A)=\frac{n(A)}{n(S)}=\frac{1}{2}
\end{array}$
(ii) Let event $B$ be getting tail
$\begin{array}{l}
B=\{T\} \quad \therefore n(B)=1 \
P(B)=\frac{n(B)}{n(S)}=\frac{1}{2}
\end{array}$