Question 12 Marks
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. ($\pi=3.14$)
Activity :
$r=10$ cm, $\theta=90^{\circ}$, $\pi=3.14.$
$A(P-AXB) = \frac{\theta}{360} \times ⬜$
$= \frac{⬜}{360} \times 3.14 \times 10^{2}$
$= \frac{1}{4} \times ⬜$
$A(P-AXB) = ⬜$ sq.cm.
View full question & answer→Activity :
$r=10$ cm, $\theta=90^{\circ}$, $\pi=3.14.$
$A(P-AXB) = \frac{\theta}{360} \times ⬜$
$= \frac{⬜}{360} \times 3.14 \times 10^{2}$
$= \frac{1}{4} \times ⬜$
$A(P-AXB) = ⬜$ sq.cm.