Question 13 MarksIn the following figure, XY || seg AC. If $2AX=3BX$ and $XY=9$. Complete the activity to find the value of AC.Activity :$2AX=3BX$ (Given) $\therefore \frac{AX}{BX} = \frac{3}{⬜}$$\frac{AX+BX}{BX} = \frac{3+2}{2}$ .......... (by componendo)$\frac{⬜}{BX} = \frac{5}{2}$ .......... (I)Now $\Delta BCA \sim \Delta BYX$ .......... ($⬜$ test of similarity)$\therefore$ $\frac{BA}{BX} = \frac{AC}{XY}$ .......... (corresponding sides of similar triangles)$\frac{⬜}{⬜} = \frac{AC}{9}$ .......... (from I)$\therefore$ $AC =⬜$View full question & answer→