Question 11 Mark
Choose the correct alternative answer for the following question.
When we see at a higher level, from the horizontal line,angle formed is.......
A. angle of elevation.
B. angle of depression.
C. 0
D. straight angle.
AnswerWhen we see at a higher level, from the horizontal line, the angle formed is known as angle of elevation.
View full question & answer→Question 21 Mark
Choose the correct alternative answer for the following question.
1 $+ tan^2\theta = ?$
A. $cot^2\theta$
B. $cosec^2\theta$
C. $sec^2\theta$
D.$ tan^2\theta$
AnswerWe know that,
$1 + tan^2\theta = sec^2\theta$
View full question & answer→Question 31 Mark
Choose the correct alternative answer for the following question.
cosec45° = ?
A. $\frac{1}{\sqrt{2}}$
B. $\sqrt{2}$
C. $\frac{\sqrt{3}}{2}$
D. $\frac{2}{\sqrt{3}}$
View full question & answer→Question 41 Mark
Choose the correct alternative answer for the following question.
sinθ cosecθ = ?
A. 1
B. 0
C. $\frac{1}{2}$
D. $\sqrt{2}$
AnswerWe know,
$\operatorname{cosec} \theta=\frac{1}{\sin \theta}$
⇒ sinθ cosecθ = 1
View full question & answer→MCQ 51 Mark
If $\sin \theta= 1$, then find $\cot \theta=$ _____
- ✓
$0$
- B
- C
$\sqrt{3}$
- D
$\frac{1}{\sqrt{3}}$
View full question & answer→MCQ 61 Mark
If $\sin \theta+\cos \theta= a$, and $\sin \theta-\cos \theta= b$, then $=$ ______
- A
$a^2+b^2=1$
- B
$a^2-b^2=1$
- ✓
$a^2+b^2=2$
- D
$a^2-b^2=2$
AnswerCorrect option: C. $a^2+b^2=2$
$a^2+b^2=2$
View full question & answer→MCQ 71 Mark
If $(\sec \theta-1)(\sec \theta+1)=\frac{1}{3}$, then $\cos \theta=$ _____
- A
$\frac{1}{2}$
- B
$\frac{1}{\sqrt{2}}$
- ✓
$\frac{\sqrt{3}}{2}$
- D
$\frac{\sqrt{2}}{3}$
AnswerCorrect option: C. $\frac{\sqrt{3}}{2}$
$\frac{\sqrt{3}}{2}$
View full question & answer→MCQ 81 Mark
In the adjoining figure, if $\angle B=90^{\circ}, \angle C=30^{\circ}$, $A C=12 m$. then $A B=$ _______- A
$12 \sqrt{3} m$
- B
$6 \sqrt{3} m$
- C
- D
View full question & answer→MCQ 91 Mark
If $\operatorname{cosec} \theta=\frac{2}{\sqrt{3}}$, then $\theta=$ _____
View full question & answer→MCQ 101 Mark
If $\cot \theta=\frac{3}{4}$, then $\tan \theta=$ ______
- ✓
$\frac{4}{3}$
- B
$\frac{9}{16}$
- C
$\frac{16}{9}$
- D
$\frac{5}{4}$
AnswerCorrect option: A. $\frac{4}{3}$
$\frac{4}{3}$
View full question & answer→MCQ 111 Mark
If $\tan \theta=1$, then $\sec \theta=$ ________
AnswerCorrect option: B. $\sqrt{2}$
$\sqrt{2}$
View full question & answer→MCQ 121 Mark
If $\sin \theta=\frac{24}{25}$, then $\cos \theta=$ ______
- A
$\frac{\sqrt{24}}{5}$
- B
$\frac{25}{24}$
- C
$\frac{25}{7}$
- ✓
$\frac{7}{25}$
AnswerCorrect option: D. $\frac{7}{25}$
$\frac{7}{25}$
View full question & answer→MCQ 131 Mark
If $\operatorname{cosec} \theta=\frac{61}{60}, \sec \theta=\frac{61}{11}$, then $\cot \theta=$ _______
- A
$\frac{61^2}{660}$
- B
$\frac{60}{11}$
- ✓
$\frac{11}{60}$
- D
AnswerCorrect option: C. $\frac{11}{60}$
$\frac{11}{60}$
View full question & answer→MCQ 141 Mark
If $\sin \theta=\frac{4}{5}$ and $\cos \theta=\frac{3}{5}$, then $\tan \theta=$
- ✓
$\frac{4}{3}$
- B
$\frac{3}{4}$
- C
$\frac{12}{25}$
- D
AnswerCorrect option: A. $\frac{4}{3}$
$\frac{4}{3}$
View full question & answer→MCQ 151 Mark
When we see at a higher level, from the horizontal line,angle formed is.......
AnswerWhen we see at a higher level, from the horizontal line, the angle formed is known as angle of elevation.
View full question & answer→MCQ 161 Mark
AnswerWe know that,
1 + tan2θ = sec2θ
View full question & answer→MCQ 171 Mark
View full question & answer→MCQ 181 Mark
AnswerWe know,
$\begin{array}{l}
\operatorname{cosec} \theta=\frac{1}{\sin \theta} \\
\Rightarrow \sin \theta \operatorname{cosec} \theta=1
\end{array}$
View full question & answer→MCQ 191 Mark
If $\tan \theta=1$, then $\sec \theta=$ ________
AnswerCorrect option: B. $\sqrt{2}$
$\sqrt{2}$
View full question & answer→MCQ 201 Mark
If $\sin \theta=\frac{4}{5}$ and $\cos \theta=\frac{3}{5}$, then $\tan \theta=$
- ✓
$\frac{4}{3}$
- B
$\frac{3}{4}$
- C
$\frac{12}{25}$
- D
AnswerCorrect option: A. $\frac{4}{3}$
$\frac{4}{3}$
View full question & answer→MCQ 211 Mark
If $\sin \theta=\frac{24}{25}$, then $\cos \theta=$ ______
- A
$\frac{\sqrt{24}}{5}$
- B
$\frac{25}{24}$
- C
$\frac{25}{7}$
- ✓
$\frac{7}{25}$
AnswerCorrect option: D. $\frac{7}{25}$
$\frac{7}{25}$
View full question & answer→MCQ 221 Mark
If $\sin \theta+\cos \theta= a$, and $\sin \theta-\cos \theta= b$, then $=$ ______
- A
$a^2+b^2=1$
- B
$a^2-b^2=1$
- ✓
$a^2+b^2=2$
- D
$a^2-b^2=2$
AnswerCorrect option: C. $a^2+b^2=2$
$a^2+b^2=2$
View full question & answer→MCQ 231 Mark
If $\sin \theta= 1$, then find $\cot \theta=$ _____
- ✓
$0$
- B
- C
$\sqrt{3}$
- D
$\frac{1}{\sqrt{3}}$
View full question & answer→MCQ 241 Mark
If $(\sec \theta-1)(\sec \theta+1)=\frac{1}{3}$, then $\cos \theta=$ _____
- A
$\frac{1}{2}$
- B
$\frac{1}{\sqrt{2}}$
- ✓
$\frac{\sqrt{3}}{2}$
- D
$\frac{\sqrt{2}}{3}$
AnswerCorrect option: C. $\frac{\sqrt{3}}{2}$
$\frac{\sqrt{3}}{2}$
View full question & answer→MCQ 251 Mark
If $\operatorname{cosec} \theta=\frac{61}{60}, \sec \theta=\frac{61}{11}$, then $\cot \theta=$ _______
- A
$\frac{61^2}{660}$
- B
$\frac{60}{11}$
- ✓
$\frac{11}{60}$
- D
AnswerCorrect option: C. $\frac{11}{60}$
$\frac{11}{60}$
View full question & answer→MCQ 261 Mark
If $\operatorname{cosec} \theta=\frac{2}{\sqrt{3}}$, then $\theta=$ _____
View full question & answer→MCQ 271 Mark
If $\cot \theta=\frac{3}{4}$, then $\tan \theta=$ ______
- ✓
$\frac{4}{3}$
- B
$\frac{9}{16}$
- C
$\frac{16}{9}$
- D
$\frac{5}{4}$
AnswerCorrect option: A. $\frac{4}{3}$
$\frac{4}{3}$
View full question & answer→MCQ 281 Mark
In the adjoining figure, if $\angle B=90^{\circ}, \angle C=30^{\circ}$, $A C=12 m$. then $A B=$ _______- A
$12 \sqrt{3} m$
- B
$6 \sqrt{3} m$
- C
- D
View full question & answer→