Question types

Probability question types

18 questions across 5 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

18
Questions
5
Question groups
5
Question types
Sample Questions

Probability questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

A two-digit number is to be formed from the digits 2,3,5 without repetition of the digits. Complete the following activity to find the probability that the number so formed is an odd number :
Let S be the sample space.
$\therefore S=\{23,25,32, ⬜, 52,53\}$$\quad$$\quad$$\therefore n(S)$ = ⬜
Now condition of event A is that number so formed is an odd number.
$\therefore A=\{23,25,⬜, 53\}$$\quad$$\quad$ $\therefore n(A)=4$
$\therefore P(A)=\frac{⬜}{n(S)}$$\quad$$\quad$...(Formula)
$\therefore P(A)=\frac{⬜}{6}$
$\therefore P(A)=\frac{⬜}{3}$
View full solution
A card is drawn at random from a pack of well-shuffled 52 playing cards. Complete the following activity to find the probability that the card drawn is
(i) an ace(Event A)(ii) a spade (Event B).
S is the sample space.
$\therefore n(S)=52$
(i) Event A: The card drawn is an ace.
$\therefore n(A)$ = ⬜
$P(A)$ = ⬜$\quad$$\quad$...(Formula)
$\therefore P(A)=\frac{⬜}{52}$$\quad$$\quad$$\therefore P(A)=\frac{⬜}{13}$
(ii) Event B: The card drawn is a spade.
$\therefore n(B)$ = ⬜
$P(B)=\frac{n(B)}{n(S)}$
$\therefore P(B)=\frac{⬜}{4}$
View full solution
A committee of two members is to be formed from three boys and two girls. Find the probability of the following events :
Event A : At least one girl must be a member of the committee.
Event B : Committee must be of one boy and one girl.
View full solution
Q 103 Marks Question3 Marks
A two digit number is to be formed from the digits 2, 3, 5 without repetition of the digits. Complete the following activity to find the probability that the number so formed is an odd number.
Activity :
Let S be the sample space.
$\therefore S=\{23,25,32,$ ⬜, $52,53\} $
$\therefore n(S)=$ ⬜
Event A : The number so formed is an odd number.
$\therefore A=\{23,25, $ ⬜, $53\} $
$\therefore n(A)=4 $
$\therefore P(A)=\frac{⬜}{n(S)} ...... ..(\text {Formula}) $
$\therefore P(A)=\frac{⬜}{6} $
$\therefore P(A)=\frac{⬜}{3} .$
View full solution
Q 113 Marks Question3 Marks
Two-digit numbers are formed from the digits 0, 1, 2, 3. Repetition of the digits are allowed. Complete the following activity to find the probability that the number so formed is a prime number:
The sample space
$S$ = {______}$\quad$$\quad$$\therefore n(S)$=⬜
Let A be the event that the number so formed is a prime number.
$A=$ {______}$\quad$$\quad$$\therefore n(A)$=⬜
$P(A)=\frac{n(A)}{n(S)}$$\quad$$\quad$$\therefore P(A)$=$[-]$=$[-]$
View full solution

Generate a Probability paper free

Pick question groups from the list above, set marks and difficulty, and export a branded PDF with step-by-step answer keys. First 3 chapters free — no signup.

Download App