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Maths 1 Marks Question

Statistics · Maharashtra Board STD 10 (MSBSHSE - Semi English Medium). 10 questions.

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Question 11 Mark
Which measure of central tendency is given by the x-coordinate of the point of intersection of the 'more than' ogive and 'less than' ogive?
Answer
Median is given by the x-coordinate of the point of intersection of the 'more than' ogive and 'less than' ogive.
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Question 21 Mark
Which measure of central tendency can be determine graphically?
Answer
Median can be determined graphically.
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Question 31 Mark
Find the mode of the following data:
3, 3, 7, 4, 5, 3, 5, 6, 8, 9, 5, 3, 5, 3, 6, 9, 7, 4
Answer
x
Tally marks
(f)
3
4
5
6
7
8
9
IIII
II
IIII
II
II
I
II
5
2
4
2
2
1
2
we see that 3 occurs in maximum times i.e. 5
$\therefore$ Mode = 3
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Question 41 Mark
Write the modal class for the following frequency distribution:
Class
10-15
15-20
20-25
25-30
30-35
35-40
Frequency
30
35
75
40
30
15
Answer
The modal class is 20-25 as it has the maximum frequency of 75 in the given distribution.
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Question 51 Mark
What is the value of the median of the data using the graph in the following figure of less than ogive and more than ogive?
Answer
Median = 4, because the coordinates of the point of intersection of two ogives at x-axis is 4.
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Question 61 Mark
Write the empirical relation between mean, mode and median.
Answer
The empirical relation is Mode = 3
Mode = 3 Median - 2 mean
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Question 71 Mark
Define Mean.
Answer
The mean of a set of observations is equal to their sum divided by the total number of observations. Mean is also called an average.
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Question 81 Mark
What is the algebraic sum of deviations of a frequency distribution about its mean?
Answer
The algebraic sum of deviation of a frequency distribution about its mean is zero.
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Question 91 Mark
Find the mode of the following data:
15, 8, 26, 25, 24, 15, 18, 20, 24, 15, 19, 15
Answer
x
Tally mark
(f)
8
15
18
19
20
24
25
26
I
IIII
I
I
I
II
I
I
1
4
1
1
1
2
1
1
Here we see that 15 occurs in maximum times i.e. 54
$\therefore$ Mode = 15
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Question 101 Mark
Find the mode of the following data:
3, 5, 7, 4, 5, 3, 5, 6, 8, 9, 5, 3, 5, 3, 6, 9, 7, 4
Answer
x
Tally mark
(f)
3
4
5
6
7
8
9
III
II
IIII
II
II
I
II
4
2
5
2
2
1
2
We see that 5 occurs in maximum times which is 5
$\therefore$ Mode = 5
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