Maths (commerce) Solve the Following Question.(2 Marks)

$
\begin{aligned}
& f(x)=\frac{x^2-9}{x-3}+a, \text { for } x>3 \\
& =5, \text { for } x=3 \\
& =2 x^2+3 x+b, \text { for } x<3
\end{aligned}
$
is continuous at $x=3$

$f(x)=x^2+a$, for $x \geq 0$ $=2 \sqrt{x^2+1}+b$, for $x<0$ and $f(1)=2$, is continuous at $x=0$