Maths (commerce) Solve the Following Question.(3 Marks)

\begin{aligned}
& f(x)=\frac{5^x-e^x}{2 x} \text { for } x \neq 0 \\
& =\frac{1}{2}(\log 5-1) \text { for } x=0 \text { at } x=0
\end{aligned}

\begin{aligned} \text { If } \mathrm{f}(\mathrm{x})=\frac{5^x+5^{-x}-2}{x^2}, \text { for } x \neq 0 \\
=\mathrm{k} \text { for } \mathrm{x}=0
\end{aligned}