Maths (commerce) Solve the Following Question.(3 Marks)

$\lim _{x \rightarrow 0}\left[\frac{\log (4-x)-\log (4+x)}{x}\right]$

$\lim _{x \rightarrow 0}\left[\frac{x\left(6^x-3^x\right)}{\left(2^x-1\right) \cdot \log (1+x)}\right]$

$\lim _{x \rightarrow 0} \frac{(1-x)^5-1}{(1-x)^3-1}$

$\lim _{x \rightarrow 0}\left[\frac{(49)^x-2(35)^x+(25)^x}{x^2}\right]$

$\lim _{x \rightarrow 2}\left[\frac{3^{\frac{x}{2}}-3}{3^x-9}\right]$

$\lim _{x \rightarrow 0}\left[\frac{3+x}{3-x}\right]^{\frac{1}{x}}$

$\lim _{x \rightarrow 0}\left[\frac{3^x+3^{-x}-2}{x^2}\right]$

$\lim _{z \rightarrow 4}\left[\frac{3-\sqrt{5+z}}{1-\sqrt{5-z}}\right]$

$\lim _{x \rightarrow 4}\left[\frac{x^2+x-20}{\sqrt{3 x+4}-4}\right]$

$\lim _{x \rightarrow 2}\left[\frac{x^2-4}{\sqrt{x+2}-\sqrt{3 x-2}}\right]$

$\lim _{v \rightarrow \sqrt{2}}\left[\frac{v^2+v \sqrt{2}-4}{v^2-3 v \sqrt{2}+4}\right]$

$\lim _{y \rightarrow \frac{1}{2}}\left[\frac{1-8 y^3}{y-4 y^3}\right]$

$\lim _{x \rightarrow-2}\left[\frac{x^7+x^5+160}{x^3+8}\right]$

$\lim _{y \rightarrow 1}\left[\frac{2 y-2}{\sqrt[3]{7+y}-2}\right]$

$\lim _{x \rightarrow 0}\left[\frac{\sqrt[3]{1+x}-\sqrt{1+x}}{x}\right]$

$\lim _{x \rightarrow 0}\left[\frac{(1-x)^8-1}{(1-x)^2-1}\right]$