MCQ 11 Mark
If $|x−1| x - 1 > 5,$ then :
- A$\text{x}\in(-4,6)$
- B$\text{x}\in[-4,6]$
- ✓$\text{x}\in(-\infty,-4)\cup(6,\infty)$
- D$\text{x}\in(-\infty,-4)\cup[6,\infty)$
Answer
View full question & answer→Correct option: C.
$\text{x}\in(-\infty,-4)\cup(6,\infty)$
$|x−1| > 5$
$\Rightarrow x − 1 > 5$ or $x − 1 < −5$
$\Rightarrow x > 5 + 1$ or $x < −5 + 1$
$\Rightarrow x > 6$ or $x < −4$
$\Rightarrow\text{x}\in(-\infty,-4)\cup(6,\infty)$
$\Rightarrow x − 1 > 5$ or $x − 1 < −5$
$\Rightarrow x > 5 + 1$ or $x < −5 + 1$
$\Rightarrow x > 6$ or $x < −4$
$\Rightarrow\text{x}\in(-\infty,-4)\cup(6,\infty)$

