Question types

Algebra of Matrices question types

313 questions across 5 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

313
Questions
5
Question groups
5
Question types
Sample Questions

Algebra of Matrices questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 1MCQ1 Mark
If $\text{A}=\begin{bmatrix}\text{n}&0&0\\0&\text{n}&0\\0&0&\text{n}\end{bmatrix}$ and $\text{B}=\begin{bmatrix}\text{a}_1&\text{a}_2&\text{a}_3\\\text{b}_1&\text{b}_2&\text{b}_3\\\text{c}_1&\text{c}_2&\text{c}_3\end{bmatrix},$ then $AB$ is equal to:
  • A
    $B$
  • $n^B$
  • C
    $B^n$
  • D
    $A + B$

Answer: B.

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Q 2MCQ1 Mark
If $A$ is a square matrix, then $AA$ is a:
  • A
    Skew$-$symmetric matrix.
  • B
    Symmetric matrix.
  • C
    Diagonal matrix.
  • None of these.

Answer: D.

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Q 3MCQ1 Mark
If $\text{A}=\begin{bmatrix}2&-1&3\\-4&5&1\end{bmatrix}$ and $\text{B}=\begin{bmatrix}2&3\\4&-2\\1&5\end{bmatrix},$ then:
  • A
    Only $AB$ is defined.
  • B
    Only $BA$ is defined.
  • $AB$ and $BA$ both are defined.
  • D
    $AB$ and $BA$ both are not defined.

Answer: C.

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Q 4MCQ1 Mark
If $A$ is a square matrix such that $A^2 = A$, then $(I + A)^3 - 7A$ is equal to:
  • A
    $A$
  • B
    $I - A$
  • $I$
  • D
    $3A$

Answer: C.

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Q 5MCQ1 Mark
If $S = [S_{ij}]$ is a scalar matrix such that $S_{ij} = k$ and $A$ is a square matrix of the same order, then $AS = SA = ?$
  • A
    $A^k$
  • B
    $k + A$
  • $kA$
  • D
    $kS$

Answer: C.

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In a certain city there are 30 colleges. Each college has 15 peons, 6 clerks, 1 typist and 1 section officer. Express the given information as a column matrix. Using scalar multiplication, find the total number of posts of each kind in all the colleges.
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If $\text{P}=\begin{bmatrix}\text{x}&0&0\\0&\text{y}&0\\0&0&\text{z}\end{bmatrix}$ and $\text{Q}=\begin{bmatrix}\text{a}&0&0\\0&\text{b}&0\\0&0&\text{c}\end{bmatrix},$ prove that $\text{PQ}=\begin{bmatrix}\text{xa}&0&0\\0&\text{y}\text{b}&0\\0&0&\text{zc}\end{bmatrix}=\text{QP}$
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