Question 12 Marks
Find the probability distribution of number of heads in two tosses of a coin.
Answer
View full question & answer→Here the r.v. $X$ takes values $0,1,2$.
Also $S=\{ HH , HT , TH , TT \}$
$
\begin{aligned}
\therefore P(X=0) & =\frac{1}{4}, \\
P(X=1) & =\frac{2}{4}=\frac{1}{2} \\
P(X=2) & =\frac{1}{4},
\end{aligned}
$
$\therefore$ Probability distribution of $X$ is :
Also $S=\{ HH , HT , TH , TT \}$
$
\begin{aligned}
\therefore P(X=0) & =\frac{1}{4}, \\
P(X=1) & =\frac{2}{4}=\frac{1}{2} \\
P(X=2) & =\frac{1}{4},
\end{aligned}
$
$\therefore$ Probability distribution of $X$ is :
| $X$ | 0 | 1 | 2 |
| $P ( X =x)$ | $\frac{1}{4}$ | $\frac{1}{2}$ | $\frac{1}{4}$ |

