If $\theta$ is the angle between the vectors $2\hat{\text{i}}-2\hat{\text{j}}+4\hat{\text{k}}$ and $3\hat{\text{i}}+\hat{\text{j}}+2\hat{\text{k}},$ then $\sin\theta=$
- A$\frac{2}{3}$
- ✓$\frac{2}{\sqrt{7}}$
- C$\frac{\sqrt{2}}{7}$
- D$\sqrt{\frac{2}{7}}$
Answer: B.
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