Questions

Solve the Following Question.(2 Marks)

Take a timed test

5 questions · self-marked practice — reveal the answer and mark yourself.

Question 12 Marks
Write the minimum value of $\text{f}(\text{x})=\text{x}+\frac{1}{\text{x}},\text{x}>0.$
Answer
Given, $\text{f}\text{(x)}=\text{x}+\frac{1}{\text{x}}$
$\therefore\ \text{f}'\text{(x)}=1-\frac{1}{\text{x}^2}$
For a local maxima or a local minima,
$\text{f}'\text{(x)}=0$
$\Rightarrow1-\frac{1}{\text{x}^2}=0$
$\Rightarrow\text{x}= +1,-1$
Now, $\text{f}''(\text{x})=\frac{2}{\text{x}^{3}}$
At x = 1, f''(x)
x = -1, f''(x) = -2 < 0
$\therefore $ x = -1 is point of local minima
$\therefore $ maximum value of = f(-1) = -2.
View full question & answer
Question 22 Marks
If f(x) attains a local minimum at x = c, then write the values of f' (c) and f'' (c).
Answer
If f(x) attains a local minimum at x = c, then the first order derivative of the function at the given point must be equal to zero, i.e.
f'(x) = 0 at x = c
⇒ f'(c) = 0
The second order derivative of the function at the given point must be greater than zero, i.e.
f''(c) > 0
View full question & answer
Question 32 Marks
Write sufficient condition for a point x = c to be an extreme point of the function f(x).
Answer
Let f(x) be a function.
f(x) will attain its extreme value at a point x = c if f'(c) = 0
The point x = c is known as point of local maxima if f''(x) < 0
View full question & answer
Question 42 Marks
Write the point where $\text{f}(\text{x})=\text{x}\log_{\text{e}}\text{x}$ attains minimum value.
Answer
Given, $\text{f}(\text{x})=\text{x}\log_{\text{e}}\text{x}$
$\Rightarrow\text{f}'(\text{x})=\log_{\text{e}}\text{x}+1$
For a local maxima or a minima, we must have $\text{f}(\text{x})=0$
$\Rightarrow\log_{\text{e}}\text{x}+1=0$
$\Rightarrow\log_{\text{e}}\text{x}=-1$
$\Rightarrow\text{x}=\frac{1}{\text{e}}$
$\Rightarrow\text{f}\Big(\frac{1}{\text{e}}\Big)=\frac{1}{\text{e}}\ \log_{\text{e}}\Big(\frac{1}{\text{e}}\Big)=-\frac{1}{\text{e}}$
Now, $\text{f}''(\text{x})=\frac{1}{\text{x}}$
At, $\text{x}=\frac{1}{\text{e}}$
$\text{f}''\Big(\frac{1}{\text{e}}\Big)=\frac{1}{\frac{1}{\text{e}}}=\text{e}>0$
So, $\Big(\frac{1}{\text{e}},-\frac{1}{\text{e}}\Big)$ is a point of local minimum.
View full question & answer
Question 52 Marks
Write necessary condition for a point x = c to be an extreme point of the function f(x).
Answer
We know that at the extreme points of a function f(x), the first order derivative of the function is equal to zero, i.e.
f'(x) = 0 at x = c
⇒ f'(c) = 0
View full question & answer