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Maths 1 Mark Question

Ratio-Proportion · Maharashtra Board STD 6 (MSBSHSE - English Medium). 15 questions.

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1 Mark Question

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15 questions · self-marked practice — reveal the answer and mark yourself.

Question 11 Mark
Find the ratio of the first quantity to the second.
125 cm, 1 metre
Answer
$125 cm , 1$ metre1 metre $=100 cm$Required Ratio $=\frac{125}{100}=\frac{125 \div 25}{100 \div 25}=\frac{5}{4}$
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Question 21 Mark
Find the ratio of the first quantity to the second.
750 grams, $\frac{1}{2} kg$
Answer
$\begin{aligned} & \text 750 \text { grams, } \frac{1}{2} kg \\ & \frac{1}{2} kg =\frac{1000}{2} \text { grams }=500 \text { grams } \\ & \text { Required Ratio }=\frac{750}{500}=\frac{750 \div 10}{500 \div 10}=\frac{75}{50} \\ & =\frac{75}{50}=\frac{75 \div 25}{50 \div 25}=\frac{3}{2}\end{aligned}$
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Question 41 Mark
Find the ratio of the first quantity to the second.
1 litre, 250 ml
Answer
1 litre, $250 ml$1 litre $=1000 ml$Required Ratio $=\frac{1000}{250}=\frac{1000 \div 10}{250 \div 10}=\frac{100}{25}$ $=\frac{100}{25}=\frac{100 \div 25}{25 \div 25}=\frac{4}{1}$
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Question 51 Mark
Find the ratio of the first quantity to the second.
99 kg, 44000 grams
Answer
$\begin{aligned} & \text 99 kg =99 \times 1000 \text { grams }=99000 \text { grams } \\ & \text { Required Ratio }=\frac{99000}{44000}=\frac{99000 \div 1000}{44000 \div 1000}=\frac{99}{44} \\ & =\frac{99}{44}=\frac{99 \div 11}{44 \div 11}=\frac{9}{4}\end{aligned}$
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Question 61 Mark
Find the ratio of the first quantity to the second.
30 litres, 24 litres
Answer
Required Ratio $=\frac{30}{24}=\frac{30 \div 6}{24 \div 6}=\frac{5}{4}$
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Question 71 Mark
Find the ratio of the first quantity to the second.
15 minutes, 1 hour
Answer
1 hour $=60$ minutesRequired Ratio $=\frac{15}{60}=\frac{15 \div 15}{60 \div 15}=\frac{1}{4}$
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Question 81 Mark
Find the ratio of the first quantity to the second.
Rs 40, Rs 120
Answer
Required Ratio $=\frac{40}{120}=\frac{40 \div 40}{120 \div 40}=\frac{1}{3}$
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Question 91 Mark
Find the ratio of the first quantity to the second.
25 beads, 40 beads
Answer
Required Ratio $=\frac{40}{120}=\frac{40 \div 40}{120 \div 40}=\frac{1}{3}$
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Question 101 Mark
In each example below, find the ratio of the first number to the second:
121, 99
Answer
$\begin{aligned} & \text121,99 \\ & \frac{121}{99}=\frac{121 \div 11}{99 \div 11}=\frac{11}{9} \\ & =11: 9\end{aligned}$
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Question 111 Mark
In each example below, find the ratio of the first number to the second:
35, 65
Answer
$\begin{aligned} & \text35,65 \\ & \frac{35}{65}=\frac{35 \div 5}{65 \div 5}=\frac{7}{13} \\ & =7: 13\end{aligned}$
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Question 121 Mark
In each example below, find the ratio of the first number to the second:
84, 60
Answer
$\begin{aligned} & \text84,60 \\ & \frac{84}{60}=\frac{84 \div 12}{60 \div 12}=\frac{7}{5} \\ & =7: 5\end{aligned}$
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Question 131 Mark
In each example below, find the ratio of the first number to the second:
52, 65
Answer
52,65
$\begin{aligned}& \frac{52}{65}=\frac{52 \div 13}{65 \div 13}=\frac{4}{5} \\& =4: 5\end{aligned}$
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Question 141 Mark
In each example below, find the ratio of the first number to the second:
63,49
Answer
63,49
$\begin{aligned}& \frac{63}{49}=\frac{63 \div 7}{49 \div 7}=\frac{9}{7} \\& =9: 7\end{aligned}$
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Question 151 Mark
In each example below, find the ratio of the first number to the second:
24, 56
Answer
$\begin{aligned} & \text 24,56 \\ & \frac{24}{56}=\frac{24 \div 8}{56 \div 8}=\frac{3}{7} \\ & =3: 7\end{aligned}$
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