MCQ

MCQ 11 Mark

With the angles given below, in which case the construction of triangle is possible?

A
$30^\circ , 60^\circ , 70^\circ$
✓
$50^\circ , 70^\circ , 60^\circ$
C
$40^\circ , 80^\circ , 65^\circ$
D
$72^\circ , 28^\circ , 90^\circ $

Answer

Correct option: B.

$50^\circ , 70^\circ , 60^\circ$

$\therefore$ Sum of three angles of a triangle is $180^\circ .$

View full question & answer→

MCQ 21 Mark

In an isosceles $\triangle\text{ABC}$, the bisectors of $\angle\text{A}$ and $\angle\text{C}$ meet at a point $O.$ If $\angle\text{A} = 40^\circ ,$ then $\angle\text{BOC} = ?$

✓
$110^\circ$
B
$70^\circ$
C
$130^\circ$
D
$150^\circ$

Answer

Correct option: A.

$110^\circ$

In an isosceles $\triangle\text{ABC} , \angle\text{B} = \angle\text{C}$ and bisector of $\angle\text{B}$ and $\angle\text{C}$ meet at $O$ and $\angle\text{A} = 40^\circ $

$\therefore\angle\text{B}=\angle\text{C}=\frac{\Big(180^\circ-40^\circ\Big)}{2}$
$=\frac{140^\circ}{2}=70^\circ$
$\therefore\frac{1}{2}\angle\text{B}=\frac{1}{2}\angle\text{C}=\frac{70^\circ}{2}=35^\circ$
Now in $\triangle\text{OBC}$
$\angle\text{BOC}+\angle\text{OBC}+\angle\text{OCB}=180^\circ$
$\angle\text{BOC}+\frac{1}{2}\angle\text{B}+\frac{1}{2}\angle\text{C}=180^\circ$
$\Rightarrow\angle\text{BOC}+35^\circ+35^\circ=180^\circ$
$\Rightarrow\angle\text{BOC}=180^\circ-70^\circ=110^\circ$

View full question & answer→

MCQ 31 Mark

How many parts does a triangle have?

A
$2$
B
$3$
✓
$6$
D
$9$

Answer

Correct option: C.

$6$

$\therefore$ It has three sides and three angles i.e. six.

View full question & answer→

MCQ 41 Mark

The side of a triangle are in the ratio $3 : 2 : 5$ and its perimeter is $30\ cm.$ The length of the longest side is:

A
$20\ cm$
✓
$15\ cm$
C
$10\ cm$
D
$12\ cm$

Answer

Correct option: B.

$15\ cm$

Side of a triangle are in the ratio $3:2:5$ and perimeter $= 30 m$
Length of longest side $=\frac{30\times5}{3+2+5}$
$=\frac{30\times5}{10} \ cm $
$= 15\ cm (b)$
Side of a triangle are in the ratio $3:2:5$ and perimeter $= 30 m$
Length of longest side $=\frac{30\times5}{3+2+5} \ cm$
$=\frac{30\times5}{10} \ cm $
$= 15\ cm$

View full question & answer→

MCQ 51 Mark

Two angles of a triangle measure $30^\circ$ and $25^\circ$ respectively. The measure of the third angle is:

A
$35^\circ$
B
$45^\circ$
C
$65^\circ$
✓
$125^\circ$

Answer

Correct option: D.

$125^\circ$

Two angles of a triangle are $30^\circ$ and $25^\circ$ But sum of three angles of a triangle $- 180^\circ$
Third angle $= 180^\circ - (30 + 25^\circ )$
$= 180^\circ - 55^\circ $
$= 125^\circ$

View full question & answer→

MCQ 61 Mark

Each angle of an equilateral triangle measures:

A
$30^\circ$
B
$45^\circ$
✓
$60^\circ$
D
$80^\circ $

Answer

Correct option: C.

$60^\circ$

Each angles of an equilateral triangle $= 60^\circ$
As each angle of an equilateral triangle are equal
Each angle $ =\frac{180^\circ}{3} = 60^\circ$

View full question & answer→

MCQ 71 Mark

In the adjoining figure, the point $P$ lies:

A
In the interior of $\triangle\text{ABC}.$
B
In the exterior of $\triangle\text{ABC}.$
✓
On $\triangle\text{ABC}.$
D
Outside $\triangle\text{ABC}.$

Answer

Correct option: C.

On $\triangle\text{ABC}.$

In the figure, $P$ lies on $AB.$ Its lies on the $\triangle\text{ABC}.$

View full question & answer→

MCQ 81 Mark

A triangle having sides of different lengths is called:

A
An isosceles triangle
B
An equilateral triangle
✓
A scalene triangle
D
A right triangle

Answer

Correct option: C.

A scalene triangle

$\therefore$ A scalene triangle has different sides.

View full question & answer→

MCQ 91 Mark

One of the base angles of an isosceles triangle is $70^\circ$ The vertical angle is:

A
$60^\circ$
B
$80^\circ$
✓
$40^\circ$
D
$35^\circ$

Answer

Correct option: C.

$40^\circ$

$\therefore$ Sum of three angles is $180^\circ$ and sum of two equal angles $= 70^\circ + 70^\circ = 140^\circ ,$
then third angle will be $180^\circ - 140^\circ = 40^\circ .$

View full question & answer→

MCQ 101 Mark

The two angles of a triangle are complementary. The third angle is:

A
$60^\circ$
B
$45^\circ$
C
$36^\circ$
✓
$90^\circ $

Answer

Correct option: D.

$90^\circ $

$\therefore$ A triangle has $180^\circ$ and if two angles are complementary i.e. sum of two angles is $90^\circ ,$ then third angle will be $180^\circ - 90^\circ = 90^\circ .$

View full question & answer→

Maths MCQ

Take a timed test