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5 questions · self-marked practice — reveal the answer and mark yourself.

Question 13 Marks
Anita was driving at a speed of 85.6 km per hour. The road had a speed limit of 55 km per hour. By how much should she reduce her speed to be within the speed limit?
Answer
Speed at which Anita is driving = 85.6 km per hr.
Speed limit = 55 km per hr.
∴ Anita should reduce her speed by 85.6 km per hr – 55 km per hr.
$\begin{aligned} & \begin{array}{r}85.6 \\ -55.0 \\ \hline 30.6\end{array} \\ & =30.6 km \text { per } hr \text {. } \\ & \end{aligned}$
= 30.6 km per hr.
∴ Anita should reduce her speed by 30.6 km per hour to be within the speed limit.
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Question 23 Marks
Ayesha bought 1.80 m of cloth for her salwaar and 2.25 for her kurta. If the cloth costs Rs 120 per metre, how much must she pay the shopkeeper?
Answer
Total length of cloth bought = 1.80 m + 2.25 m
= 4.05 m
$\begin{array}{r}1.80 \\ +2.25 \\ \hline 4.05\end{array}$
Cost of 1 m of cloth = Rs 120
∴ Cost of 4.05 m of cloth = 4.05 x 120
$=\frac{405}{100} \times 120=\frac{405 \times 120}{100 \times 1}=\frac{48600}{100}=₹ 486$
∴ Amount to be paid to the shopkeeper is Rs 486.
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Question 33 Marks
Subtract:
i. 85.96 – 2.345
ii. 632.24 – 97.45
iii. 200.005 – 17.186
Answer
i. 85.96 – 2.345
$\begin{array}{r}85.960 \\ -\quad 2.345 \\ \hline 8 3 . 6 1 5 \end{array}$

ii. 632.24 – 97.45
$\begin{array}{r}632.24 \\ -\quad 97.45 \\ \hline 5 3 4 . 7 9 \end{array}$

iii. 200.005 – 17.186
$\begin{array}{r}200.005 \\ -\quad 17.186 \\ \hline 1 8 2 . 8 1 9 \end{array}$

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Question 43 Marks
Solve :
i. 905.5 + 27.197
ii. 39 + 700.65
iii. 40 + 27.7 + 2.451
Answer
i. 905.5 + 27.197
$\begin{array}{r}905.500 \\ +\quad 27.197 \\ \hline 9 3 2 . 6 9 7 \end{array}$

ii. 39 + 700.65
$\begin{array}{r}39.00 \\ +700.65 \\ \hline 7 3 9 . 6 5 \end{array}$

iii. 40 + 27.7 + 2.451
$\begin{array}{r}40.000 \\ 27.700 \\ +\quad 2.451 \\ \hline 7 0 . 1 5 1 \end{array}$

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