Maths 1 Mark Question

51 > 0 > -2 > -8 > -53

-135 from -250
= -250 - (-135)
= -250 + 135
= -115

0 + 0 = 0
So, the additive inverse of 0 is 0.

1056 + (-798) + (-38) + 44 + (-1)
= 1056 + 44 – (798 + 38 + 1)
= 1100 – 837
= -263

5 + a = 0
⇒ a = 0 - 5

(-36) × (72) + (-36) × 28
= (-2592) + (-1008)
= -2592 - 1008
= -3600

8

= -8 - (-68) + (-36)
= -8 + 68 - 36
= 68 - (8 + 36)
= 68 - 44
= 24

The smallest positive integer is 1.Solution:

-2768 from -287
= -287 - (-2768)
= -287 + 2768
= 2481

-92 from 0
= 0 - (-92)
= 0 + 92
= 92

(-5) + (-6)
= -5 - 6
= -11

(-51) + (-203) + 36 + (-28)
= -51 – 203 + 36 – 28
= -282 + 36
= -246

Spending rupees 500

Going 6m to the west

0

(-8) × (-63) × 9
= (-8) × (-567)
= 4536

-57 by 0
= -57 × 0
= 0

-27 < -13
Since 27 is greater than 13, -27 is smaller than -13.

-28 from -43
= -43 - (-28)
= -43 + 28
= -15

-4, -6
-4
Since 6 is greater than 4, -4 is greater than -6.

0 by -31
= 0 × (-31)
= 0

-1001 + 1001 = 0
So, the additive inverse of -1001 is 1001.

-3012 from 6250
= 6250 - (-3012)
= 6250 + 3012
= 9262

(-125) ÷ (-5) = 25Solution:
= 25 × -5 = -125

413 > 102 > -7 > -365 > -515

-18 by 13
= (-18) × 13
= -234

3002 + (-888)
= 3002 – 888
= 2114

An decrease of 8

-106 < -81 < -16 < -2 < 0 < 16 < 21

8 + (-16)
= 8 - 16
= -8

The successor of -99:
-99 + 1 = -98

-100 < -23 < -6 < -1 < 0 < 12

-3km

|7 - 4|
= |3| (The value of |3| is 3)
= 3

-746 by -8
= (-746) × (-8)
= 5968

The successor of 201:
201 + 1 = 202

57 + 57 = 0
So, the additive inverse of -57 is 57.

Four integers less than -6 (i.e. four negative integers that lie to the left of -6) are -7, -8, -9 and -10.
Four integers greater than -6 (i.e. four negative integers that lie to the right of -6 ) are -5, -4, -3 and -2.