Questions

MCQ

Take a timed test

8 questions · auto-graded multiple-choice test.

MCQ 11 Mark
Mark $(\checkmark)$ against the correct answer in the following: If $\frac{1}{3}\text{x}+5=8,$ then $\text{x}={}?$
  • A
    $3$
  • B
    $6$
  • $9$
  • D
    $12$
Answer
Correct option: C.
$9$
$\Rightarrow\frac{1}{3}\text{x}+5=8$
$\Rightarrow\frac{1}{3}\text{x}+5-5=8-5 [$Substracting $5$ from both sides$]$
$\Rightarrow\frac{1}{3}\text{x}\times3=3\times3 [$Multiplying both sides by $3]$
$\text{x}=9$
View full question & answer
MCQ 21 Mark
Mark $(\checkmark)$ against the correct answer in the following: if $\frac{\text{x}}{5}=1,$ then,
  • A
    $\text{x}=\frac{1}{5}$
  • $x = 5$
  • C
    $x = (5 + 1)$
  • D
    None of these
Answer
Correct option: B.
$x = 5$
$\frac{\text{x}}{5}=1$
$\Rightarrow\frac{\text{x}}{5}\times5=1\times5 [$Multiplying both the side by $5]$
$x = 5$
View full question & answer
MCQ 31 Mark
Mark $(\checkmark)$ against the correct answer in the following: The coefficient of $x$ in $-5xyz$ is:
  • A
    $-5$
  • B
    $5yz$
  • $-5yz$
  • D
    $yz$
Answer
Correct option: C.
$-5yz$
All the terms in the expression $-5xyz$ barring $x$ will be the coefficient of $x,$ i.e. $-5yz.$
View full question & answer
MCQ 41 Mark
Mark $(\checkmark)$ against the correct answer in the following: $\frac{1}{3}(\text{x}+7+\text{z})$ is $a:$
  • A
    Monomial
  • B
    Binomial
  • Trinomial
  • D
    Quadrinomial
Answer
Correct option: C.
Trinomial
Since it contains three variables, i.e. $x, y$ and $z,$ it is a trinomial.
View full question & answer
MCQ 51 Mark
Mark $(\checkmark)$ against the correct answer in the following:
If $x = 1, y = 2$ and $z = 3$ then $(x^2 + y^2 + z^2) = ?$
  • A
    $6$
  • B
    $12$
  • $14$
  • D
    $15$
Answer
Correct option: C.
$14$
Substituting $x = 1, y = 2$ and $z = 3$ in $(x^2 + y^2 + z^2):$
$\Rightarrow (1)^2 + (2)^2 + (3)^2$
$\Rightarrow 1 + 4 + 9 = 14$
View full question & answer
MCQ 61 Mark
Mark $(\checkmark)$ against the correct answer in the following: By how much does $I$ exceed $2x - 3y - 4?$
  • A
    $2x - 3y - 5$
  • B
    $2x - 3y - 3$
  • $5 - 2x + 3y$
  • D
    None of these
Answer
Correct option: C.
$5 - 2x + 3y$
$1$ exceeds $2x - 3y - 4.$
$\therefore 1 - (2x - 3y - 4) $
$= 1 - 2x + 3y + 4$
$= 5 - 2x + 3y$
$\therefore 1$ exceeds $2x - 3y - 4$ by $5 - 2x + 3y$
View full question & answer
MCQ 71 Mark
Mark $(\checkmark)$ against the correct answer in the following:
What must be added to $5x^3 - 2x^2 + 6x + 7$ to make the sum $x^3 + 3x^2 - x + 1$?
  • A
    $4x^3 - 5x^2 + 7x + 6$
  • $-4x^3 + 5x^2 - 7x - 6$
  • C
    $4x^3 + 5x^2 - 7x + 6$
  • D
    None of these
Answer
Correct option: B.
$-4x^3 + 5x^2 - 7x - 6$
In order to find what must be added, we subtract $(5x^3 - 2x^2 + 6x + 7)$ from $(x^3 + 3x^2 - x + 1)$
$\Rightarrow (x^3 + 3x^2 - x + 1) - ( 5x^3 - 2x^2 + 6x + 7)$
$\Rightarrow x^3 + 3x^2 - x + 1 - 5x^3 + 2x^2 - 6x - 7$
$\Rightarrow x^3 - 5x^3+ 3x^2+ 2x^2- x - 6x+ 1 - 7$
$\Rightarrow -4x^3+ 5x^2 - 7x - 6$
View full question & answer
MCQ 81 Mark
Mark $(\checkmark)$ against the correct answer in the following: $2x - [3y - {2x - (y - x)}] = ?$
  • $5x - 4y$
  • B
    $4y - 5x$
  • C
    $5y - 4x$
  • D
    $4x - 5y$
Answer
Correct option: A.
$5x - 4y$
$2x - [3y - {2x - (y - x)}]$
$= 2x - [3y - {2x - y + x}]$
$= 2x - [3y - {3x - y}]$
$= 2x - [3y - 3x + y]$
$= 2x - [4y - 3x]$
$= 2x - 4y + 3x$
$= 5x - 4y$
View full question & answer