Question 12 Marks
Find the area of a square whose side is: 4.1cm
Answer
View full question & answer→Area of a square $=($ Side $\times$ Side $)$ Side of the square $=4.1 cm$ Area of the square $=(4.1 \times 4.1)=16.81 cm^2$
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33 questions · self-marked practice — reveal the answer and mark yourself.
Question 22 Marks
Find the area of a square whose side is:
$5\ cm$
$5\ cm$
Answer
View full question & answer→Area of a square $=($ Side $\times$ Side $)$
Side of the square $=5\ cm$
Area of the square $=5 \times 5=25 cm^2$
Side of the square $=5\ cm$
Area of the square $=5 \times 5=25 cm^2$
Question 32 Marks
Find the perimeter of the square whose side is given below:5m
Answer
View full question & answer→Perimeter of a square = 4 × (Length of one side)
Length of one side = 5m
Perimeter = 4 × 5 = 20m
Length of one side = 5m
Perimeter = 4 × 5 = 20m
Question 42 Marks
Split the following shape into rectangles and find the area. (The measures are given in centimeter.)
Answer
View full question & answer→This figure consists of two rectangles I and II
.
The area of rectangle I = (Length × Breadth)
$=10 \times 2$
$=20 cm^2$
Similarly, area of rectangle II = (Length × Breadth)
$=10 \times 32$
$=15 cm^2$
Thus, total area of this figure = (Area of rectangle I + Area of rectangle II)
$=20+15$
$=35 cm^2$
.
The area of rectangle I = (Length × Breadth)
$=10 \times 2$
$=20 cm^2$
Similarly, area of rectangle II = (Length × Breadth)
$=10 \times 32$
$=15 cm^2$
Thus, total area of this figure = (Area of rectangle I + Area of rectangle II)
$=20+15$
$=35 cm^2$
Question 52 Marks
Find the side of the square whose perimeter is:
40cm
40cm
Answer
View full question & answer→Side of a square = Perimeter 4
Perimeter = 40cm
Side of this square $=\frac{40}{4}$
$=4\text{cm}$
Perimeter = 40cm
Side of this square $=\frac{40}{4}$
$=4\text{cm}$
Question 62 Marks
Find the perimeter of the rectangle whose lengths and breadths are given below:
7.5cm, 4.5cm
7.5cm, 4.5cm
Answer
View full question & answer→Perimeter of a rectangle = 2 × (Length + Breadth)
Since, Length = 7.5cm, Breadth = 4.5cm
Therefore, Perimeter = 2 × (7.5 + 4.5)
= 2 × (12)
= 24cm
Since, Length = 7.5cm, Breadth = 4.5cm
Therefore, Perimeter = 2 × (7.5 + 4.5)
= 2 × (12)
= 24cm
Question 72 Marks
Find the side of the square whose perimeter is:
22cm
22cm
Answer
View full question & answer→Side of a square = Perimeter 4
Perimeter = 22cm
Side of this square $=\frac{22}{4}$
$=5.5\text{cm}$
Perimeter = 22cm
Side of this square $=\frac{22}{4}$
$=5.5\text{cm}$
Question 82 Marks
Find the perimeter of the rectangle whose lengths and breadths are given below:
5cm, 4cm
5cm, 4cm
Answer
View full question & answer→Perimeter of a rectangle = 2 × (Length + Breadth)
Since, Length = 5cm, Breadth = 4cm
Therefore, Perimeter = 2(5 + 4)
= 2 × (9)
= 18cm
Since, Length = 5cm, Breadth = 4cm
Therefore, Perimeter = 2(5 + 4)
= 2 × (9)
= 18cm
Question 92 Marks
Find the area of a rectangle, whose
Length $=4.5 cm$, breadth $=2 cm$
Length $=4.5 cm$, breadth $=2 cm$
Answer
View full question & answer→Area of a rectangle $=$ (Length $\times$ Breadth)
Length $=4.5 cm$, Breadth $=2 cm$
Area of rectangle $=4.5 \times 2$
$=9 cm^2$
Length $=4.5 cm$, Breadth $=2 cm$
Area of rectangle $=4.5 \times 2$
$=9 cm^2$
Question 102 Marks
The following figure is drawn on a squared paper. Count the number of square enclosed by figure and find its area, taking the area of square as $1cm^2$.
Answer
View full question & answer→There are 16 complete squares in the given shape.
Since, Area of one square $=1 cm^2$
Therefore, Area of this shape $=16 \times 1=16 cm^2$
Since, Area of one square $=1 cm^2$
Therefore, Area of this shape $=16 \times 1=16 cm^2$
Question 112 Marks
The following figure is drawn on a squared paper. Count the number of square enclosed by figure and find its area, taking the area of square as $1cm^2$.
Answer
View full question & answer→There are 20 complete and 8 half squares in the given shape. Since, Area of one square $=1 cm^2$ Therefore, Area of this shape $=(20+8 \times 12)=24 cm^2$
Question 122 Marks
Find the area of a square whose side is: 5.5cm
Answer
View full question & answer→Area of a square $=($ Side $\times$ Side $)$ Side of the square $=5.5 cm$ Area of the square $=(5.5 \times 5.5)=30.25 cm^2$
Question 132 Marks
Avneet buys 9 square paving slabs, each with a side of $\frac{1}{212}\text{m}.$ He lays them in the form of a square.
-
What is the perimeter of his arrangement?
-
Shari does not like his arrangement. She gets him to lay them out like a cross. What is the perimeter of her arrangement?
-
Which has greater perimeter?
-
Avneet wonders, If there is a way of getting an even greater perimeter. Can you find a way of doing this? (The paving slabs must meet along complete edges they cannot be broken)
Answer
So, length of the side of the square $=3\times\frac{1}{2}=\frac{3}{2}\text{m}$
The perimeter of the square arrangement $=4\times\frac{3}{2}=6\text{m}$
Also, this arrangement consists of other 4 sides that measure $\frac{1}{2}\text{m}$ each.
So, the perimeter of the cross arrangement$=\Big(1+\frac{1}{2}+1+1+\frac{1}{2}+1+1+\frac{1}{2}+1+1+\frac{1}{2}+1\Big)$
$=(8+2)=10\text{m}$
Thus, the perimeter of the cross arrangement is more than that of the square arrangement.
View full question & answer→- Length of the side of one slab $=\frac{1}{2}\text{m}$
So, length of the side of the square $=3\times\frac{1}{2}=\frac{3}{2}\text{m}$
The perimeter of the square arrangement $=4\times\frac{3}{2}=6\text{m}$
- The cross arrangement consists of 8 sides.
Also, this arrangement consists of other 4 sides that measure $\frac{1}{2}\text{m}$ each.
So, the perimeter of the cross arrangement$=\Big(1+\frac{1}{2}+1+1+\frac{1}{2}+1+1+\frac{1}{2}+1+1+\frac{1}{2}+1\Big)$
$=(8+2)=10\text{m}$
- Perimeter of the cross arrangement = 10m
Thus, the perimeter of the cross arrangement is more than that of the square arrangement.
- No, there is no way of arranging these slabs where the perimeter is more than 10m.
Question 142 Marks
Find the area of a square whose side is:
$2.6cm$
$2.6cm$
Answer
View full question & answer→Area of a square $=($ Side $\times$ Side $)$
Side of the square $=2.6 cm$
Area of the square $=(2.6 \times 2.6)$
$=6.76 cm^2$
Side of the square $=2.6 cm$
Area of the square $=(2.6 \times 2.6)$
$=6.76 cm^2$
Question 152 Marks
The side of a square is 70 cm . Find its area and perimeter.
Answer
View full question & answer→Side of the square $=70 cm$ Area of the square $=($ Side $\times$ Side $)=70 \times 70=4900 cm^2$ Perimeter of the square $=(4 \times$ Side) $=4 \times 70=280 cm$
Question 162 Marks
The following figure is drawn on a squared paper. Count the number of square enclosed by figure and find its area, taking the area of square as $1cm^2$. 
Answer
View full question & answer→There are 15 complete and 6 half squares in the given shape. Since, Area of one square = $1cm^2$ Therefore, Area of this shape = $(15 + 6 × 12)$ = $18cm^2$
Question 172 Marks
The area of a rectangle is $225 cm^2$ and its one side is 25 cm , find its other side.
Answer
View full question & answer→Area $=225 cm^2$
One of the sides $=25 cm$
Area of the rectangle $=$ Product of the lengths of its two side
Other side $=\frac{\text { Area }}{\text { Side }}$
$=\frac{225}{25}$
$9 cm$
One of the sides $=25 cm$
Area of the rectangle $=$ Product of the lengths of its two side
Other side $=\frac{\text { Area }}{\text { Side }}$
$=\frac{225}{25}$
$9 cm$
Question 182 Marks
Find the breadth of the rectangle whose perimeter is 360cm and whose length is:116cm
Answer
View full question & answer→Perimeter of a rectangle = 2(Length + Breadth)
Therefore, Breadth of the rectangle $=\frac{\text{Perimeter}}{2}-\text{Length}$
Perimeter = 360cm
Length = 116cm
Breadth $=\frac{360}{2}-116$
= 180 - 116
= 64cm
Therefore, Breadth of the rectangle $=\frac{\text{Perimeter}}{2}-\text{Length}$
Perimeter = 360cm
Length = 116cm
Breadth $=\frac{360}{2}-116$
= 180 - 116
= 64cm
Question 192 Marks
The following figure is drawn on a squared paper. Count the number of square enclosed by figure and find its area, taking the area of square as $1cm^2.$
Answer
View full question & answer→There are 36 complete squares in the given shape. Since, Area of one square $=1 cm^2$ Therefore, Area of 36 squares $=$ $36 \times 1=36 cm^2$
Question 202 Marks
Find the perimeter of a regular hexagon with each side measuring 8m.
Answer
View full question & answer→A regular hexagon is a closed polygon having six sides of equal lengths.
Side of the hexagon = 8m
Perimeter of the hexagon = 6(Side of the hexagon)
= 6 × 8
= 48m
Side of the hexagon = 8m
Perimeter of the hexagon = 6(Side of the hexagon)
= 6 × 8
= 48m
Question 212 Marks
Find the perimeter of the square whose side is given below:10cm
Answer
View full question & answer→Perimeter of a square = 4 × (Length of one side)
Length of one side = 10cm
Perimeter = 4 × 10
= 40cm
Length of one side = 10cm
Perimeter = 4 × 10
= 40cm
Question 222 Marks
Find the area of a rectangle, whose
Length $=8 cm$, breadth $=3 cm$
Length $=8 cm$, breadth $=3 cm$
Answer
View full question & answer→Area of a rectangle $=($ Length $\times$ Breadth $)$
Length $=8 cm$ Breadth $=3 cm$
Area of rectangle $=8 \times 3$
$=24 cm^2$
Length $=8 cm$ Breadth $=3 cm$
Area of rectangle $=8 \times 3$
$=24 cm^2$
Question 232 Marks
Find the breadth of the rectangle whose perimeter is 360cm and whose length is:102cm
Answer
View full question & answer→Perimeter of a rectangle = 2(Length + Breadth)Therefore, Breadth of the rectangle $=\frac{\text{Perimeter}}{2}-\text{Length}$
Perimeter = 360cm Length $=\frac{10}{2}$ Breadth $=\frac{360}{2}-140$ = 180 - 102 = 78cm
Perimeter = 360cm Length $=\frac{10}{2}$ Breadth $=\frac{360}{2}-140$ = 180 - 102 = 78cm
Question 242 Marks
Split the following shape into rectangles and find the area. (The measures are given in centimeter.)
Answer
View full question & answer→This figure consists of two squares I and III and one rectangle II.
Area of square $I=$ Area of square III $=($ Side $\times$ Side $)$
$=7 \times 7$
$=49 cm^2$
Similarly, area of rectangle II $=$ (Length $\times$ Breadth $)$
$=(21 \times 7)$
$=147 cm^2$
Thus, total areas of this figure $=$ (Area of square I + Area of rectangle II + Area of square III)
$=49+49+147$
$=245 cm^2$
Area of square $I=$ Area of square III $=($ Side $\times$ Side $)$
$=7 \times 7$
$=49 cm^2$
Similarly, area of rectangle II $=$ (Length $\times$ Breadth $)$
$=(21 \times 7)$
$=147 cm^2$
Thus, total areas of this figure $=$ (Area of square I + Area of rectangle II + Area of square III)
$=49+49+147$
$=245 cm^2$
Question 252 Marks
Find the area of a rectangle, whose
Length $=6 cm$, breadth $=3 cm$
Length $=6 cm$, breadth $=3 cm$
Answer
View full question & answer→Area of a rectangle $=($ Length $\times$ Breadth $)$
Length $=6 cm$, Breadth $=3 cm$
Area of rectangle $=6 \times 3$
$=18 cm^2$
Length $=6 cm$, Breadth $=3 cm$
Area of rectangle $=6 \times 3$
$=18 cm^2$
Question 262 Marks
The following figure is drawn on a squared paper. Count the number of square enclosed by figure and find its area, taking the area of square as $1cm^2$.
Answer
View full question & answer→There are 13 complete squares, 8 more than half squares and 7 less than half squares in the given shape.
Area of one square $=1 cm^2$
Area of this shape $=(13+8 \times 1)=21 cm^2$
Area of one square $=1 cm^2$
Area of this shape $=(13+8 \times 1)=21 cm^2$
Question 272 Marks
Find the perimeter of the square whose side is given below:115.5cm
Answer
View full question & answer→Perimeter of a square = 4 × (Length of one side)
Length of one side = 115.5cm
Perimeter = 4 × 115.5 = 462cm
Length of one side = 115.5cm
Perimeter = 4 × 115.5 = 462cm
Question 282 Marks
The area of a rectangle is $49 cm^2$ and its breadth is 2.8 cm . Find the length of the rectangle.
Answer
View full question & answer→Area $=49 cm^2$
Breadth $=2.8 cm$
Area of the rectangle $=($ Length $\times$ Breadth $)$
$\therefore$ Length $=\frac{\text { Area }}{\text { Breadth }}$
$=\frac{49}{2.8}=17.5 cm$
Breadth $=2.8 cm$
Area of the rectangle $=($ Length $\times$ Breadth $)$
$\therefore$ Length $=\frac{\text { Area }}{\text { Breadth }}$
$=\frac{49}{2.8}=17.5 cm$
Question 292 Marks
Find the perimeter of the following figure:
Answer
Perimeter of the figure = (AB + BC + CD + DE + EF + FG + GH + HA)
= 10 + 10 + 20 + 30 + 20 + 20 + 10 + 20
= 140m
View full question & answer→Perimeter of the figure = (AB + BC + CD + DE + EF + FG + GH + HA)
= 10 + 10 + 20 + 30 + 20 + 20 + 10 + 20
= 140m
Question 302 Marks
Split the following shape into rectangles and find the area. (The measures are given in centimeter) 
Answer
View full question & answer→This figure consists of two rectangles I and II.
Area of rectangle $I =$ (Length $\times$ Breadth $)$
$=5 \times 1$
$=5 cm^2$
Similarly, area of rectangle II $=$ (Length $\times$ Breadth $)$
$=4 \times 1$
$=4 cm^2$
Thus, total area of this figure $=($ Area of rectangle I + Area of rectangle II)
$=5+4$
$=9 cm^2$
Area of rectangle $I =$ (Length $\times$ Breadth $)$
$=5 \times 1$
$=5 cm^2$
Similarly, area of rectangle II $=$ (Length $\times$ Breadth $)$
$=4 \times 1$
$=4 cm^2$
Thus, total area of this figure $=($ Area of rectangle I + Area of rectangle II)
$=5+4$
$=9 cm^2$
Question 312 Marks
Find the perimeter of the rectangle whose lengths and breadths are given below:
7cm, 5cm
7cm, 5cm
Answer
View full question & answer→Perimeter of a rectangle = 2 × (Length + Breadth)
Since, Length = 7cm, Breadth = 5cm
Therefore, Perimeter = 2(7 + 5)
= 2(12)
= 24cm
Since, Length = 7cm, Breadth = 5cm
Therefore, Perimeter = 2(7 + 5)
= 2(12)
= 24cm
Question 322 Marks
The following figure is drawn on a squared paper. Count the number of square enclosed by figure and find its area, taking the area of square as $1cm^2$.
Answer
View full question & answer→There are 8 complete squares, 6 more than half squares and 4 less than half squares in the given shape.
Area of one square $=1 cm^2$
Area of this shape $=(8+6 \times 1)=14 cm^2$
Area of one square $=1 cm^2$
Area of this shape $=(8+6 \times 1)=14 cm^2$
Question 332 Marks
Find the breadth of the rectangle whose perimeter is 360cm and whose length is:140cm
Answer
View full question & answer→Perimeter of a rectangle = 2(Length + Breadth)Therefore, Breadth of the rectangle $=\frac{\text{Perimeter}}{2}-\text{Length}$
Perimeter = 360cm Length = 140cmBreadth $=\frac{360}{2}-140$
= 180 - 140 = 40cm
Perimeter = 360cm Length = 140cmBreadth $=\frac{360}{2}-140$
= 180 - 140 = 40cm