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3 Mark Question

Question 513 Marks
Define:
Factor
Answer
Factor:A factor of a number is an e×act divisor of that number.
For e×ample, 4 e×actly divide 32. Therefore, 4 is a factor of 32.
Examples of factors are:
2 and 3 are factors of 6 because 2 × 3 = 6
2 and 4 are factors of 8 because 2 × 4 = 8
3 and 4 are factors of 12 because 3 × 4 = 12
3 and 5 are factors of 15 because 3 × 5 = 15
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Question 523 Marks
A rectangular courtyard is 20m 16cm long and 15m 60cm broad. It is to be paved with square stones of the same size. Find the least possible number of such stones.
Answer
Length of the rectangular courtyard = 20m 16cm = 2,016cm
Breadth of the rectangular courtyard = 15m 60cm = 1,560cm
Least possible side of the square stones used to pave the rectangular courtyard = HCF of (2,016 and 1,560)
Prime factorization of 2,016 =2 × 2 × 2 × 2 × 2 × 3 × 3 × 7
Prime factorization of 1,560 = 2 × 2 × 2 × 3 × 5 × 13 HCF of (2,016, 1,560) = 2 × 2 × 2 × 3= 24
Least possible side of square stones used to pave the rectangular courtyard is 24 cm. Number of square stones used to pave the rectangular courtyard
= Area of rectangular courtyard Area of square stone = 2016cm × 1560cm (24cm) 2 = 5460 Thus, the least number of square stones used to pave the rectangular courtyard is 5,460.
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Question 533 Marks
The length, breadth and height of a room are 8m 25cm, 6m 75cm and 4m 50cm, respectively. Determine the longest rod which can measure the three dimensions if the room exactly.
Answer
Length of the room = 8m 25cm = 825cm
Breadth of the room = 6m 75cm = 675cm
Height of the room = 4m 50cm = 450cm
The longest rod will be given by the HCF of 825, 675 and 450.
Prime factorization of 825 = 3 × 5 × 5 × 11
Prime factorization of 675 = 3 × 3 × 3 × 5 × 5
Prime factorization of 450 = 2 × 3 × 3 × 5 × 5 Therefore, HCF of 825, 675 and 450 = 3 × 5 × 5 = 75
Thus, the required length of the longest rod is 75cm.
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Question 543 Marks
Find the greatest number of four digits which is exactly divisible by each of $8,12,18$ and 30 .
Answer
$8=1 \times 2 \times 2 \times 2=2^3$
$12=1 \times 2 \times 2 \times 3=2^2 \times 3^1 \\
18=1 \times 2 \times 3 \times 3=2^1 \times 3^2 \\
30=1 \times 2 \times 3 \times 5=2^1 \times 3^1 \times 5^1$
LCM of $8,12,18$, and $30=2^3 \times 3^2 \times 5^1=360$
Largest 4-digit number is 9999
Now, if we divide 9999 by 360 , we will get 27.78 as quotient.
The integer just less than 27.78 is 27
$\therefore$ Required number $=360 \times 27=9720$
Hence, the greatest number of four digits which is exactly divisible by each of $8,12,18$ and 30 is 9720 .
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3 Mark Question - Page 2 - Maths STD 6 Questions - Vidyadip