Questions

2 Mark Question

🎯

Test yourself on this topic

15 questions · timed · auto-graded

Question 12 Marks
When planting a forest, the number of jambhul trees planted was greater than the number of ashoka trees by 60. If there are altogether 200 trees of these two types, how many jambhul trees were planted ?
Answer
Let the number of jambhul trees planted be $x$.
$\therefore$ Number of ashoka trees $=x-60$
According to the given condition, $x+x-60=200$
$
\begin{aligned}
& \therefore 2 x=200+60 \\
& \therefore 2 x=260 \\
& \therefore x=\frac{260}{2}=130
\end{aligned}
$
$\therefore 130$ jambhul trees were planted.
View full question & answer
Question 22 Marks
Multiply : (4x + 5y) × (9x + 7y)
Answer
(4x + 5y) × (9x + 7y)
= 4x × (9x + 7y) + 5y × (9x + 7y)
= (4x × 9x) + (4x × 7y) + (5y × 9x) + (5y × 7y)
= 36x² + 28xy + 45xy + 35y²
= 36x² + 73xy + 35y²
View full question & answer
Question 62 Marks
Subtract the second expression from the first. : (4x + 16z); (19y – 14z + 16x)
Answer
(4x + 16z) – (19y— 14z + 16x)
= 4x + 16z – 19y + 14z – 16x
= (4x – 16x) – 19y + (16z + 14z)
= -12x – 19y + 30z
View full question & answer
Question 72 Marks
Subtract the second expression from the first. : (6x² + 7xy + 16y²); (16x² – 17xy)
Answer
(6x² + 7xy + 16y²) – (16x² – 17xy)
= 6x² + 7xy + 16y² – 16x² + 17xy
= (6x² – 16x²) + (7xy + 17xy) + 16y²
= -10x² + 24xy + 16y²
View full question & answer
Question 82 Marks
Subtract the second expression from the first. : (14x² + 8xy + 3y²); (26x² – 8xy – 17y²)
Answer
(14x² + 8xy + 3y²) – (26x² – 8xy – 17y²)
= 14x² + 8xy + 3y² – 26x² + 8xy + 17y²
= (14x² – 26x²) + (8xy + 8xy) + (3y² + 17y²)
= -12x² + 16xy + 20y²
View full question & answer
Question 92 Marks
Subtract the second expression from the first. : (5x + 4y + 7z); (x + 2y + 3z)
Answer
(5x + 4y + 7z) – (x + 2y + 3z)
= 5x + 4y + 7z – x – 2y – 3z
= (5x – x) + (4y – 2y) + (7z – 3z)
= 4x + 2y + 4z
View full question & answer
Question 102 Marks
Subtract the second expression from the first. : (4xy – 9z); (3xy – 16z)
Answer
(4xy – 9z) – (3xy – 16z)
= 4xy – 9z – 3xy + 16z
= (4xy – 3xy) + (16z – 9z)
= xy + 7z
View full question & answer
Question 122 Marks
Find the square root : 4096
Answer

Image

∴ 4096 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2
∴ √4096 = 2 x 2 x 2 x 2 x 2 x 2 = 64

View full question & answer
2 Mark Question - Maths STD 7 Questions - Vidyadip