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37 questions · self-marked practice — reveal the answer and mark yourself.

Question 12 Marks
Find six rational numbers between $\frac{-4}{8}\text{ and }\frac{3}{8}$
Answer
We know that:
- 4, -3, -2, -1, 0, 1, 2, 3
Therefore $\frac{-4}{8},\frac{-3}{8},\frac{-2}{8},\frac{-1}{8},\frac{0}{8},\frac{1}{8},\frac{2}{8},\frac{3}{8}$
Hence 6 rational numbers between $\frac{-4}{8}$ and $​​\frac{3}{8}$ are $\frac{-3}{8},\frac{-2}{8},\frac{-1}{8},\frac{0}{8},\frac{1}{8},\frac{2}{8}$
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Question 22 Marks
Find the value and express as a rational number in standard form:
$\frac{10}{3}\div\frac{-35}{12}$
Answer
$\frac{10}{3}\div\frac{-35}{12}$
$=​​\frac{10}{3}\times\frac{-12}{35}$
$=\frac{-40}{35}$
$=\frac{-8}{7}$
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Question 32 Marks
Multiply:
$\frac{5}{7}\text{ by }\Big(\frac{-3}{4}\Big)$
Answer
$\frac{5}{7}\text{ by }\frac{-3}{4}$
$=\frac{5}{7}\times​​\frac{-3}{4}=​​\frac{-15}{28}$
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Question 42 Marks
Find the value and express as a rational number in standard form:
$-6\div\frac{-8}{17}$
Answer
$-6\div\frac{-8}{17}$
$=-6\times​​\frac{-17}{8}$
$=\frac{102}{8}$
$=\frac{51}{4}$
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Question 52 Marks
Multiply:
$\frac{-5}{17}\text{ by }\frac{51}{-60}$
Answer
$\frac{-5}{17}\text{ by }\frac{51}{-60}$
$\frac{-5}{7}\times\frac{51}{-60}$
$=\frac{-255}{-1020}$
$=\frac{255}{1020}$
$=\frac{1}{4}$
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Question 62 Marks
Simplify the following and express the result as a rational number in standard form:
$\frac{-13}{9}\times\frac{27}{26}$
Answer
$\frac{-13}{9}\times\frac{27}{26}$
$\frac{-13}{9}\times\frac{27}{-26}$
$=\frac{3}{2}$
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Question 72 Marks
By what number should$\frac{-3}{4}$ so that the product may be $\frac{2}{3}?$
Answer
Let x be the number by which we should multiply $\frac{-3}{4}$ to get $\frac{2}{3}$
$\frac{-3}{4}\times\text{x}=\frac{2}{3}$
$\Rightarrow\text{x}=\frac{2}{3}\times\frac{4}{-3}=\frac{-8}{9}$
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Question 82 Marks
Divide:
$\frac{2}{3}\text{ by} \frac{-7}{12}$
Answer
$\frac{2}{3}\text{ by} \frac{-7}{12}$
$\frac{2}{3}\div \frac{-7}{12}$
$\frac{2}{3}\times\frac{-12}{7}$
$=\frac{-8}{7}$
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Question 92 Marks
Divide:
$5\text{ by }\frac{-5}{7}$
Answer
$5\text{ by }\frac{-5}{7}$
$5\div\frac{-5}{7}$
$=5\times\frac{-7}{5}$
$=-7$
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Question 102 Marks
Multiply:
$\frac{-6}{11}\text{ by }\frac{-55}{36}$
Answer
$\frac{-6}{11}\text{ by }\frac{-55}{36}$
$\frac{-6}{11}\times\frac{-55}{36}$
$=\frac{-6}{11}\times\frac{-5\times11}{6\times6}$
$=\frac{5}{6}$
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Question 112 Marks
Find the value and express as a rational number in standard form:
$\frac{40}{98}\div-20$
Answer
$\frac{40}{98}\div-20$
$=\frac{-2}{98}$
$=\frac{-1}{49}$
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Question 122 Marks
Subtract the first rational number from the second of the following:
$-\frac{2}{11},\frac{-9}{11}$
Answer
$\frac{-2}{11}+\frac{-9}{11}=\frac{-9}{11}+\frac{2}{11}$
$=\frac{-9+2}{11}$
$=-\frac{7}{11}$
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Question 132 Marks
Simplify the following and express the result as a rational number in standard form:
$\frac{-19}{36}\times{16}$
Answer
$\frac{-19}{36}\times{16}$
$=​​\frac{-304}{36}$
$=\frac{-76}{9}$
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Question 142 Marks
Divide:
$\frac{-3}{4}\text{ by }\frac{9}{-16}$
Answer
$\frac{-3}{4}\text{ by }\frac{9}{-16}$$\frac{-3}{4}\div\frac{9}{-16}$
$=\frac{-3}{4}\times\frac{-16}{9}$
$=\frac{-4}{-3}$
$=\frac{4}{3}$
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Question 152 Marks
Subtract the first rational number from the second of the following:
$\frac{11}{13},\frac{-4}{13}$
Answer
$\frac{11}{13},\frac{-4}{13}$
$\frac{-4}{13}-\frac{11}{13}=\frac{-4-11}{13}$
$=\frac{-15}{13}$
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Question 162 Marks
Divide:
$\frac{-3}{4}\text{ by} -6$
Answer
$\frac{-3}{4}\text{ by} -6$
$\frac{-3}{4}\div-6$
$\frac{-3}{4}\times\frac{-1}{6}$
$=\frac{1}{8}$
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Question 172 Marks
Divide:
$\frac{-7}{8}\text{ by }\frac{-21}{16}$
Answer
$\frac{-7}{8}\text{ by }\frac{-21}{16}$$\frac{-7}{8}\div\frac{-21}{16}$
$=\frac{-7}{8}\times\frac{-16}{21}$
$=\frac{2}{3}$
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Question 182 Marks
The product of two rational numbers is 15. If one of the numbers is -10, find the other.
Answer
Let the first rational number = x.
$\text{x}\times-10=15$
$\text{x}=\frac{15}{-10}$
$\text{x}=\frac{3}{-2}$
$\text{x}=\frac{-3}{2}$
Hence the number is $\text{x}=\frac{-3}{2}$
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Question 192 Marks
Simplify the following and express the result as a rational number in standard form:
$\frac{7}{6}\times\frac{-3}{28}$
Answer
$\frac{7}{6}\times\frac{-3}{28}$
$\frac{7}{6}\times\frac{-3}{28}$
$=\frac{-1}{8}$
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Question 202 Marks
Multiply:
$\frac{6}{7}\text{ by }\frac{-49}{36}$
Answer
$\frac{6}{7}\text{ by }\frac{-49}{36}$
$\frac{6}{7}\times\frac{-49}{36}$
$=\frac{-7}{6}$
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Question 212 Marks
Subtract the first rational number from the second of the following:
$\frac{3}{8},\frac{5}{8}$
Answer
$\frac{5}{8}-\frac{3}{8}=\frac{5-3}{8}$
$=\frac{2}{8}$
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Question 222 Marks
Divide:
$\frac{7}{-4}\text{ by }\frac{63}{64}$
Answer
$\frac{7}{-4}\text{ by }\frac{63}{64}$
$\frac{7}{-4}\div\frac{63}{64}$
$=\frac{7}{-4}\times\frac{64}{63}$
$=\frac{-16}{9}$
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Question 232 Marks
Divide:
$0\text{ by }\frac{-7}{5}$
Answer
$0\text{ by }\frac{-7}{5}$
$0\div\frac{-7}{5}$
$0\div\frac{-5}{7}$
$=0$
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Question 242 Marks
If 24 trousers of equal size can be prepared in 54 metres of cloth, what length of cloth is required for each trouser?
Answer
Legnth of cloth required for each trouser $=\frac{\text{Total legnth of cloth}}{\text{number of trousers}}$
$=\frac{54}{24}$
$=\frac{9}{4}\text{ meters}$
$\frac{9}{4}$ meters of cloth is reiquired to make each trouser.
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Question 252 Marks
Find 10 rational numbers between $\frac{7}{13}$ and $\frac{-4}{13}$
Answer
We know that
7, 6, 5, 4, 3, 2, 1, 0, -1, -2, -3, –4
Therefore $\frac{7}{13},\frac{6}{13},\frac{5}{13},\frac{4}{13},\frac{3}{13},\frac{2}{13},\frac{1}{13},\frac{0}{13},\frac{-1}{13},\frac{-2}{13},\frac{-3}{13},\frac{-4}{13}$
Hence the 10 rational numbers berween $\frac{7}{13}$and $\frac{-4}{13}$ are:
$\frac{-3}{13},\frac{-2}{13},\frac{-1}{13},\frac{0}{13},\frac{1}{13},\frac{2}{13},\frac{3}{13},\frac{4}{13},\frac{5}{13},\frac{6}{13},\frac{7}{13}$
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Question 262 Marks
Add the following rational numbers:
$\frac{-15}{4}\text{ and }\frac{7}{4}$
Answer
We have:
$\frac{-15}{4}+\frac{7}{4}$
$=\frac{-15+7}{4}$
$=\frac{-8}{4}$
$=-2$
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Question 272 Marks
Simplify the following and express the result as a rational number in standard form:
$\frac{-16}{21}\times\frac{14}{5}$
Answer
$\frac{-16}{21}\times\frac{14}{5}$
$=​​\frac{-224}{105}$
$=\frac{-35}{15}$
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Question 282 Marks
Add the following rational numbers:
$\frac{-8}{11}\text{ and }\frac{-4}{11}$
Answer
$\frac{-8}{11}+\frac{-4}{11}$
$=\frac{-8-4}{11}$
$=\frac{-12}{11}$
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Question 292 Marks
Multiply:
$\frac{-3}{17}\text{ by }\Big(\frac{-5}{-4}\Big)$
Answer
$\frac{-3}{17}\text{ by }\Big(\frac{-5}{-4}\Big)$
$=\frac{-3}{17}\times​​\frac{-5}{-4}$
$=​​\frac{15}{-68}$
$=\frac{-15}{68}$
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Question 302 Marks
Find the value and express as a rational number in standard form:
$\frac{2}{5}\div\frac{26}{15}$
Answer
$\frac{2}{5}\div\frac{26}{15}$
$=​​\frac{2}{5}\times\frac{15}{26}$
$=\frac{3}{13}$
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Question 312 Marks
By what number should $\frac{-33}{16}$ be divided to get $\frac{-11}{4}?$
Answer
$\frac{-33}{16}\div\text{x}=\frac{-11}{4}$
$\Rightarrow\text{x}=\frac{-33}{16}\div\frac{-11}{4}$
$\Rightarrow\text{x}=-\frac{33}{16}\times\frac{4}{-11}$
$\text{x}=​​\frac{3}{4}$
The number is $\text{x}=​​\frac{3}{4}$
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Question 322 Marks
Multiply:
$\frac{7}{11}\text{ by }\frac{5}{4}$
Answer
$\frac{7}{11}\times\frac{5}{4}$
$=\frac{7\times5}{11\times4}=​​\frac{35}{44}$
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Question 332 Marks
Add the following rational numbers:
$\frac{-5}{7}\text{ and }\frac{3}{7}$
Answer
$\frac{-5}{7}+\frac{3}{7}$
$=\frac{-5+3}{7}$
$=\frac{-2}{7}$
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Question 342 Marks
Subtract the first rational number from the second of the following:
$-\frac{7}{9},\frac{4}{9}$
Answer
$-\frac{7}{9}+\frac{4}{9}=\frac{4}{9}-\frac{-7}{9}$
$=\frac{4+7}{9}$
$=\frac{11}9{}$
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Question 352 Marks
Multiply:
$\frac{-8}{25}\text{ by }\frac{-5}{16}$
Answer
$\frac{-8}{25}\text{ by }\frac{-5}{16}$
$\frac{-8}{5\times5}\times\frac{-5}{8\times2}$
$=\frac{1}{10}$
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Question 362 Marks
The sum of the two numbers is $\frac{5}{9},$ r one of me numbers is $\frac{1}{3}$ find the other.
Answer
Required number $=\frac{5}{9}-\frac{1}{3}$
LCM of 3 and 9 is 9
$\frac{1}{3}=\frac{1\times3}{3\times3}=\frac{3}{9}$
Therefore required number $=\frac{5}{9}-\frac{3}9{}$
$=\frac{2}{9}$
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Question 372 Marks
Multiply:
$\frac{(-2)}{9}\text{ by }\Big(\frac{5}{11}\Big)$
Answer
$\frac{(-2)}{9}\text{ by }\Big(\frac{5}{11}\Big)$
$=\frac{-2}{9}\times​​\frac{5}{11}$
$=​​\frac{-10}{99}$
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