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11 questions · timed · auto-graded

Question 22 Marks
Measure the length and breadth of the courts laid out for games such as kho-kho, kabaddi, tennis, badminton, etc. Find out their perimeters and areas.
Answer
SELF
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Question 32 Marks
Find the total surface area of the cuboids of length, breadth and height as given below : 8 m, 5 m, 3.5 m
Answer
Total surface area of cuboid = 2 (lb + bh + lh)
= 2 (8 × 5+ 5 × 3.5 + 8 × 3.5)
= 2(40 + 17.5 + 28)
= 2 × 85.5
= 171 sq. m.
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Question 42 Marks
Find the total surface area of the cuboids of length, breadth and height as given below : 2.5 m, 2 m, 2.4 m
Answer
Total surface area of cuboid = 2 (lb + bh + lh)
= 2(2.5 × 2 + 2 × 2.4 + 2.5 × 2.4)
= 2 (5 + 4.8 + 6)
= 2 × 15.8
= 31.6 sq. m.
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Question 52 Marks
Find the total surface area of the cuboids of length, breadth and height as given below : 5 cm, 3.5 cm, 1.4 cm
Answer
Total surface area of cuboid
= 2 (lb + bh + lh)
= 2 (5 × 3.5 + 3.5 × 1.4 + 5 × 1.4)
= 2(17.5 + 4.9 + 7)
= 2 × 29.4
= 58.8 sq. cm.
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Question 62 Marks
Find the total surface area of the cuboids of length, breadth and height as given below : 12 cm, 10 cm, 5 cm
Answer
Total surface area of cuboid
= 2 (lb + bh + lh)
= 2 (12 × 10 + 10 × 5 + 12 × 5)
= 2 (120 + 50 + 60)
= 2 × 230
= 460 sq. cm.
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Question 72 Marks
What is the value of a rectangular plot of land 75.5 m long and 30.5 m broad at the rate of Rs 1000 per square metre ?
Answer
Area of the rectangular plot = length × breadth
= 75.5 × 30.5
= 2302.75 sq. m.
Value of the plot = area of the plot × rate per square metre = 2302.75 × 1000
= Rs 230275
∴ The value of the plot is Rs 23,02,750.
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Question 82 Marks
What is the area of a triangle with base 4.8 cm and height 3.6 cm ?
Answer
Area of triangle $=\frac{1}{2} \times$ base $\times$ height
$
\begin{aligned}
& =\frac{1}{2} \times 4.8 \times 3.6 \\
& =\frac{1}{2} \times 17.28 \\
& =8.64 \text { sq. } cm .
\end{aligned}
$
$\therefore$ The area of the triangle is 8.64 sq. cm.
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Question 92 Marks
A page of a calendar is 45 cm long and 26 cm wide. What is its area ?
Answer
Area of page of a calendar = length × breadth
= 45 × 26
= 1170 sq. cm.
∴ The area of the page of the calendar is 1170 sq. cm.
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Question 102 Marks
If the length of a rectangle is 15 cm and breadth is 5 cm, find its area.
Answer
Area of a rectangle = length × breadth
= 15 × 5
= 75 sq. cm.
∴ The area of the rectangle is 75 sq. cm.
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Question 112 Marks
If the side of a square is 12 cm, find its area.
Answer
Area of a square = (side)² = (12)²
= 144 sq. cm.
∴ The area of the square is 144 sq. cm.
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2 Mark Question - Maths STD 7 Questions - Vidyadip