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Maths 5 Mark Question

Data Handling IV (Probability) · Maharashtra Board STD 7 (MSBSHSE - Semi English Medium). 1 questions.

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Question 15 Marks
A die is thrown 100 times and outcomes are noted as given below:
Outcome:
1
2
3
4
5
6
Frequency:
21
9
14
23
18
15
If a die is thrown at random, find the probability of getting a/ an:
  1. 3
  2. 5
  3. 4
  4. Even number
  5. Odd number
  6. Number less than 3
Answer
Total number of trials = 100
Number of times “1” comes up = 21
Number of times “2” comes up = 9
Number of times “3” comes up = 14
Number of times “4” comes up = 23
Number of times “5” comes up = 18
Number of times “6” comes up = 15
  1. Probability of getting 3 $=\frac{\text{Frequency of 3}}{\text{Total No. of trails}}=\frac{14}{100}=0.14$
  2. Probability of getting 5 $=\frac{\text{Frequency of 5}}{\text{Total No. of trails}}=\frac{18}{100}=0.18$
  3. Probability of getting 4 $=\frac{\text{Frequency of 4}}{\text{Total No. of trails}}=\frac{23}{100}=0.23$
  4. Frequency of getting an even no. = Frequency of 2 + Frequency of 4 + Frequency of 6 = 9 + 23 + 15 = 47
Probability of getting an even no. $=\frac{\text{Frequency of even number}}{\text{Total No. of trails}}=\frac{47}{100}=0.47$
  1. Frequency of getting an odd no. = Frequency of 1 + Frequency of 3 + Frequency of 5 = 21 + 14 + 18 = 53
Probability of getting an odd no. $=\frac{\text{Frequency of odd number}}{\text{Total No. of trails}}=\frac{53}{100}=0.53$
  1. Frequency of getting a no. less than 3 = Frequency of 1 + Frequency of 2 = 21 + 9 = 30
Probability of getting a no. less than 3 $=\frac{\text{Frequency of number less than 3}}{\text{Total No. of trails}}=\frac{30}{100}=0.30$
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