Download App

Maths 3 Mark Question

Decimals · Maharashtra Board STD 7 (MSBSHSE - Semi English Medium). 15 questions.

Questions

3 Mark Question

Take a timed test

15 questions · self-marked practice — reveal the answer and mark yourself.

Question 13 Marks
Each bag of cement weighs 48.5kg. How many such bags will weigh 223 kg?
Answer
Total weight of all the bags = 2231kg
Weight of each bag = 48.5kg
Number of bags $=\frac{\text{Totalweight}}{\text{Weight of each bag}}$
$=\Big(\frac{2231}{48.5}\Big)\text{kg}$
$=\Big(\frac{2231\times10}{48.5\times10}\Big)=\frac{22310}{485}=46$
Hence, 46 bags of cement will weigh 2231kg
View full question & answer→
Question 23 Marks
A tin holds 16.5 litres of oil. How many such tins will be required to hold 478.5 litres of oil?
Answer
Oil in one tin = 16.5 litres Total oil = 478.5 litres $\therefore$ Number of tins required $=\frac{478.5}{16.5}=\frac{478.5\times10}{16.5\times10}$ $=\frac{4785}{165}=29\text{ tins}$
View full question & answer→
Question 33 Marks
The total of 24 chairs is Rs. 9255.60. Find the cost of each chair.
Answer
Cost of 24 chairs = Rs. 9255.60
$\therefore$ Cost of one chair $=\text{Rs. }\Big(\frac{9255.60}{24}\Big)$
$=\text{Rs. }\Big(\frac{9255.60\times10}{24\times10}\Big)$
$=\text{Rs. }\Big(\frac{92556}{240}\Big)$
$=\text{Rs. }385.65$

Hence, the cost of one chair is Rs. 385.65
View full question & answer→
Question 43 Marks
How many pieces of plywood, each of 0.45cm thick, are required to make a pile 2.43m high?
Answer
Thickness of the pile of plywoods = 2.43m = 2.43 × 100cm = 243cm
Thickness of one piece of plywood = 0.45 cm
$\therefore$ Required number of pieces of plywood $=\frac{243}{0.45}=\frac{243\times100}{0.45\times100}$
$=\frac{24300}{45}=540$

Hence, the required number of pieces of plywood is 540
View full question & answer→
Question 53 Marks
A car covers a distance of 22.8km in 2.4 litres of petrol. How much distance will it cover in 1 litre of petrol?
Answer
Distance covered by the car with 2.4 litres of petrol = 22.8km
$\therefore$ Distance covered with 1 litre of petrol $=\Big(\frac{22.8}{2.4}\Big)\text{km}$
$=\Big(\frac{228}{24}\Big)\text{km}=\Big(\frac{228\div12}{24\div12}\Big)\text{km}$
$=\Big(\frac{19}{2}\Big)=9\frac{1}{2}\text{km}$
Hence, the distance covered by the car with 1 litre of petrol is $9\frac{1}{2}\text{km}$
View full question & answer→
Question 63 Marks
Find the product 0.68 × 6.5 × 0.04
Answer
First, we will find the product 68 × 65 × 4
Now, 68 × 65 × 4 = 4420 × 4 = 17680
Sum of decimal places in the given decimals = (2 + 1 + 2) = 5
So, the product have five decimal places
0.68 × 6.5 × 0.04 = 0.17680 = 0.1768
View full question & answer→
Question 73 Marks
The product of two decimals is 261.36. If one of them is 17.6, find the other.
Answer
Product of two decimals = 261.36 One decimal = 17.6 Second decimal = 261.36 ÷ 17.6 $=\frac{261.36}{17.6}=\frac{261.36\times10}{17.6\times10}$ $=\frac{2613.6}{176}=14.85$
View full question & answer→
Question 83 Marks
If 69 buckets of equal capacity can be filled with 586.5 litres of water, what is the capacity of eacch bucket?
Answer
Capacity of 69 buckets of water = 586.5 litres
$\therefore$ Capacity of one such bucket $=\Big(\frac{585.5}{69}\Big)\text{ liters}=8.5\text{ liters}$

Hence, the capacity of each water bucket is 8.5 litres.
View full question & answer→
Question 93 Marks
How many pieces of plywood, each 0.35cm thick, are required to make a pile 1.89m high?
Answer
Total thickness = 1.89m = 189cm Thickness of one piece = 0.3 5cm Number of pieces = 189 ÷ 0.35 $=\frac{189}{0.35}=\frac{189\times100}{0.35\times100}$ $=\frac{18900}{35}=540\text{ pieces}$
View full question & answer→
Question 103 Marks
Each side of a polygon is 3.8cm in length and its perimeter is 22.8cm. How many sides does the polygon have?
Answer
Let the number of sides of the polygon be n
Length of each side of the polygon = 3.8cm
$\therefore$ Perimeter of the polygon = (3.8 × n)cm
But it is given that its perimeter is 22.8cm
$\therefore$ (3.8 × n)cm = 22.8cm
$\Rightarrow\text{n}=\Big(\frac{22.8}{3.8}\Big)=\frac{228}{38}=6$
Hence, the given polygon has six sides.
View full question & answer→
Question 113 Marks
The product of two decimals is 1.824. If one of them is 0.64, find the other.
Answer
Product of the given decimals = 1.824
One decimal = 0.64
The other decimal = 1.824 ÷ 0.64
$=\frac{1.824}{0.64}=\Big(\frac{1.824\times100}{0.64\times100}\Big)$
$=\frac{182.4}{64}=2.85$
Hence, the other decimal is 2.85
View full question & answer→
Question 123 Marks
Mr. Soni bought some bags of cement, each weighing 49.8kg. If the total weight of all the bags is 1792.8kg, how many bags did he buy?
Answer
Total weight of cement = 1792.8kg Cement in one bag = 49.8kg Number of bags = 1792.8 ÷ 49.8 $=\frac{1792.8}{49.8}=\frac{1792.8\times10}{49.8\times10}$ $=\frac{17928}{498}=36\text{ bags}$
View full question & answer→
Question 133 Marks
Monica cuts 46m of cloth into pieces of 1.15m each. How many pieces does she get?
Answer
Number of pieces in 1.15m = 1
$\therefore$ Number of pieces in $46\text{m}=\frac{46}{1.15}$
$=\frac{46\times100}{1.15\times100}$
$=\frac{4600}{115}=40\text{ pieces}$
View full question & answer→
Question 143 Marks
The weight of 37 bags of sugar is 3644.5kg. If all the bags weigh equally, what is the weight of each bag?
Answer
Weight of 37 bags of sugar = 3644.5kg $\therefore$ Weight of 1 bag of suga $=\Big(\frac{3644.5}{37}\Big)=98.5\text{kg}$
Hence, each bag of sugar weighs 98.5 kg.
View full question & answer→
Question 153 Marks
1.8m of cloth is required for a shirt. How many such shirts can be made from a piece of cloth 45m long?
Answer
Length of cloth for one shirt = 1.8m Total length of piece of cloth = 45m Number of shirts will be = 45 ÷ 1.8 $=\frac{45}{1.8}=\frac{45\times10}{1.8\times10}$ $=\frac{450}{18}=25\text{ shirts}$
View full question & answer→
Generate Paper FreeAll Decimals topics