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5 Mark Question

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2 questions · self-marked practice — reveal the answer and mark yourself.

Question 15 Marks
Simplify the following:
$4+\frac{1}{5}\Big[\big\{-10\times(25-\overline{13-3})\big\}\div(-5)\Big]$
Answer
$4+\frac{1}{5}\Big[\big\{-10\times(25-\overline{13-3})\big\}\div(-5)\Big]$
$=4+\frac{1}{5}\big[\{-10\times(25-10)\}\div(-5)\big]$
$=4+\frac{1}{5}\big[\{-10\times(15)\}\div(-5)\big]$
$=4+\frac{1}{5}\big[(-150)\div(-5)\big]$
$=4+\frac{1}{5}\big[30\big]$
$=4+6$
$=10$
$\therefore\ 4+\frac{1}{5}\Big[\big\{-10\times(25-\overline{13-3})\big\}\div(-5)\Big]=10$
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Question 25 Marks
Complete the following multiplication table:
Second number
First number
x
-4
-3
-2
-1
0
1
2
3
4
-4
 
 
 
 
 
 
 
 
 
-3
 
 
 
 
 
 
 
 
 
-2
 
 
 
 
 
 
 
 
 
-1
 
 
 
 
 
 
 
 
 
0
 
 
 
 
 
 
 
 
 
1
 
 
 
 
 
 
 
 
 
2
 
 
 
 
 
 
 
 
 
3
 
 
 
 
 
 
 
 
 
4
 
 
 
 
 
 
 
 
 
ls the multiplication table symmetrical about the diagonal joining the upper left corner to the lower right corner?
Answer
Second number
First number
x
-4
-3
-2
-1
0
1
2
3
4
-4
16
12
8
4
0
-4
-8
-12
-16
-3
12
9
6
3
0
-3
-6
-9
-12
-2
8
6
4
2
0
-2
-4
-6
-8
-1
4
3
2
1
0
-1
-2
-3
-4
0
0
0
0
0
0
0
0
0
0
1
-4
-3
-2
-1
0
1
2
3
4
2
-8
-6
-4
-2
0
2
4
6
8
3
-12
-9
-6
-3
0
3
6
9
12
4
-16
-12
-8
-4
0
4
8
12
16
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