1 Mark Question

Question 11 Mark

Write ‘T’ for true and ‘F’ for false for the following:
Simple interest on Rs. 1000 at 5% per annum for 73 days is Rs. 10.

Answer

True.Solution:
P = Rs. 1000
R = 5%
T = 73 days
$=\frac{73}{365}\text{ days}$
$\text{S.I.}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$=\frac{1000\times5\times73}{100\times365}$
$=\text{Rs. }10$

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Question 21 Mark

Fill in the blanks:
AT simple interest a sum becomes $\frac65$ of itself in $2\frac12\text{ years.}$ The rate of interest is (......)% per annum.

Answer

AT simple interest a sum becomes $\frac65$ of itself in $2\frac12\text{ years.}$ The rate of interest is 8% per annum.Solution:
Let the sum be Rs. x
Amount $=\text{Rs. }\frac65\text{x}$
$\text{S.I.}=\text{A}-\text{P}$ $=\frac{6}{5}\text{x}-\text{x}$ $=\text{Rs. }\frac{\text{x}}{5}$Let the rate of interest be R %
Time = 2.5 years
$\text{S.I.}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$ $\Rightarrow\frac{\text{x}}{5}=\frac{\text{x}\times\text{R}\times\text{2.5}}{100}$ $\Rightarrow\text{R}=\frac{100}{2.5\times5}$ $\Rightarrow8$

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Question 31 Mark

Write ‘T’ for true and ‘F’ for false for the following:
A sum doubles itself at simple interest at 10% per annum in 10 years.

Answer

True.Solution:
Let the sum be Rs. x
$\text{S.I.}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$\text{S.I.}=\frac{\text{x}\times10\times10}{100}$
$\text{S.I.}=\text{Rs. x}$
Amount = S.I. + P
= x + x
= Rs. 2x

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Question 41 Mark

Fill in the blanks:
$\text{R}=\frac{100\times\text{S.I.}}{(.......)\times\text{T}}$

Answer

$\text{R}=\frac{100\times\text{S.I.}}{(\text{P})\times\text{T}}$

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Question 51 Mark

Fill in the blanks:
AT (....)% per annum simple interest a sum doubles itself in 10 years.

Answer

AT 10% per annum simple interest a sum doubles itself in 10 years.Solution:
Let the amount be Rs. x Amount = Rs. 2x S.I. = A - P = 2x - x = Rs. x Let the rate of interest be R % Time = 10 years $\text{S.I.}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$ $\Rightarrow\text{x}=\frac{\text{x}\times\text{R}\times\text{T}}{100}$ $\Rightarrow\text{R}=\frac{100}{10}$ $\Rightarrow\text{R}=10\%$

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Question 61 Mark

Fill in the blanks:
$\text{P}=\frac{100\times(......)}{\text{R}\times\text{T}}$

Answer

$\text{P}=\frac{100\times\text{S.I.}}{\text{R}\times\text{T}}$

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Question 71 Mark

Write ‘T’ for true and ‘F’ for false for the following:
Simple interest on Rs. x for x years is Rs. x. Then, the rate of interest is x % per annum.

Answer

False.Solution:
$\text{S.I.}=\frac{\text{P}\times\text{R}\times\text{T}}{100}$
$\Rightarrow\text{x}=\frac{\text{x}\times\text{R}\times\text{x}}{100}$
$\Rightarrow\text{R}=\frac{100\times\text{x}}{\text{x}\times\text{x}}$
$\Rightarrow\text{R}=\frac{100}{\text{x}}\%$

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Question 81 Mark

Write ‘T’ for true and ‘F’ for false for the following:
$\text{Rate}=\frac{100\times\text{S.I.}}{\text{P}\times\text{T}}$

Answer

True.

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