Maths 2 Mark Question

x = 4 is the root of 3x - 5 = 7
Now, substituting x = 4 in place of ‘x’ in the given equation:
3x - 5 = 7
3(4) - 5 = 7
12 - 5 = 7
7 = 7
Since, L.H.S. = R.H.S.
Hence, x = 4 is the root of 3x - 5 = 7

x = 8 is the root of 12x + 7 = 11
Now, substituting x = 8 in place of ‘x’ in the given equation:
12x + 7 = 11,
12(8) + 7 =11
4 + 7 = 11
11 = 11
Since, L.H.S. = R.H.S.
Hence, x = 8 is the root of 12x + 7 = 11

x = 3 is the root of 5 + 3x = 14
Now, substituting x = 3 in place of ‘x’ in the given equation:
5 + 3x = 14,
5 + 3(3) = 14
5 + 9 = 14
14 = 14
Since, L.H.S. = R.H.S.
Hence, x = 3 is the root of 5 + 3x = 14

y = 2 is the root of y - 3 = 2y - 5.
Now, substituting y = 2 in place of ‘y’ in the given equation:
y - 3 = 2y - 5,
2 – 3 = 2(2) - 5
-1 = 4 - 5
-1 = -1
Since, L.H.S. = R.H.S.
Hence, y = 2 is the root of y - 3 = 2y - 5.

x = 2 is the root of 3x - 2 = 8x - 12
Now, substituting x = 2 in place of ‘x’ in the given equation:
3x - 2 = 8x - 12,
3(2) - 2 = 8(2) - 12
6 - 2 = 16 - 12
4 = 4
Since, L.H.S. = R.H.S.
Hence, x = 2 is the root of 3x - 2 = 8x - 12