2 Mark Question

Question 12 Marks

Find the simple interest, when:
Principal = Rs. 1200, Rate of Interest = 18% per annum, and Time = 4 month.

Answer

Principal (P) = Rs. 1200, Rate of interest (R) = 18% p.a., Time (T) = 4 month
$\text{T}=\frac{4}{12}=\frac{1}{3}\ \text{year}$ $\Big(\because 1\text{ month} =\frac{1}{12}\ \text{year}\Big)$
Simple interest $=\frac{\text{P}\ \times\ \text{R}\ \times\ \text{T}}{100}$
$=\frac{1200\ \times\ 18\ \times\ \frac{1}{3}}{100}$
$=\frac{1200\ \times\ 18\ \times\ 1}{100\ \times\ 3}$
$=\text{Rs. }720$

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Question 22 Marks

Find the simple interest, when:
Principal = Rs. 2000, Rate of Interest = 5% per annum, and Time = 5 years.

Answer

Principal (P) = Rs. 2000, Rate of interest (R) = 5% p.a., Time (T) = 5 years
Simple interest $=\frac{\text{P}\ \times\ \text{R}\ \times\ \text{T}}{100}$
$=\frac{2000\ \times\ 5\ \times\ 5}{100}$
$=\text{Rs. }500$

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Question 32 Marks

Find the simple interest, when:
Principal = Rs. 4500, Rate of Interest = 4% per annum, and Time = 6 month.

Answer

Principal (P) = Rs. 4500, Rate of interest (R) = 4% p.a., Time (T) = 6 month
$\text{T}=\frac{6}{12}=\frac{1}{2}\ \text{year}$ $\Big(\because 1\text{ month} =\frac{1}{12}\ \text{year}\Big)$
Simple interest $=\frac{\text{P}\ \times\ \text{R}\ \times\ \text{T}}{100}$
$=\frac{4500\ \times\ 4\ \times\ \frac{1}{2}}{100}$
$=\frac{4500\ \times\ 4\ \times\ 1}{100\ \times\ 2}$
$=\text{Rs. }90$

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Question 42 Marks

Find the simple interest, when:
Principal = Rs. 500, Rate of Interest = 12.5% per annum, and Time = 4 years.

Answer

Principal = Rs. 500, Rate of Interest = 12.5% per annum, and Time = 4 years.
Simple interest $=\frac{\text{P}\ \times\ \text{R}\ \times\ \text{T}}{100}$
$=\frac{500\ \times\ 12.5\ \times\ 4}{100}$
$=\text{Rs. }250$

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Question 52 Marks

Find the simple interest, when:
Principal = Rs. 1000, Rate of Interest = 10% per annum, and Time = 73 days.

Answer

Principal = Rs. 1000, Rate of Interest = 10% per annum, and Time = 73 days
$\text{T}=\frac{73}{365}\ \text{year}$ $\Big(\because 1\text{ day} =\frac{1}{365}\ \text{year}\Big)$
Simple interest $=\frac{\text{P}\ \times\ \text{R}\ \times\ \text{T}}{100}$
$=\frac{1000\ \times\ 10\ \times\ \frac{73}{365}}{100}$
$=\frac{1200\ \times\ 18\ \times\ 73}{100\ \times\ 365}$
$=\text{Rs. }20$

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