MCQ 11 Mark
Tick $(\checkmark)$ the correct answer the following: What should be subtracted from $\frac{-5}{3}$ to get $\frac{5}{6}$?
- A
$\frac{5}{2}$
- B
$\frac{3}{2}$
- C
$\frac{5}{4}$
- ✓
$\frac{-5}{2}$
AnswerCorrect option: D. $\frac{-5}{2}$
Let $x$ be subtracted
$=\frac{-5}{3}-\text{x}=\frac{5}{6}$
$=\frac{-5}{3}-\frac{5}{6}=\text{x}$
$=\frac{-10-5}{6}$
$=\frac{-15}{6}$
$=\frac{-15\div3}{6\div3}$
$=\frac{-5}{2}$
Number to be subtracted $=\frac{-5}{2}$
View full question & answer→MCQ 21 Mark
Mark $(\checkmark)$ against the correct answer of the following: Reciprocal of $\frac{-7}{9}$ is:
- A
$\frac{9}{7}$
- ✓
$\frac{-9}{7}$
- C
$\frac{7}{9}$
- D
AnswerCorrect option: B. $\frac{-9}{7}$
Reciprocal of $\frac{-7}{9}=\frac{9}{-7}$
$\frac{9}{-7}=\frac{9\times-1}{-7\times-1}$
$\frac{9}{-7}=\frac{-9}{7}$
View full question & answer→MCQ 31 Mark
Mark $(\checkmark)$ against the correct answer of the following: $\Big(\frac{-5}{4}\Big)^{-1}=\ ?$
- A
$\frac{4}{5}$
- ✓
$\frac{-4}{5}$
- C
$\frac{5}{4}$
- D
$\frac{3}{5}$
AnswerCorrect option: B. $\frac{-4}{5}$
We have,
$\Big(\frac{-5}{4}\Big)^{-1}$
$=\frac{1}{\Big(\frac{-5}{4}\Big)}$
$=1\times\frac{4}{-5}$
$=\frac{4}{-5}$
$=\frac{4\times-1}{-5\times-1}$
$=\frac{-4}{5}$
View full question & answer→MCQ 41 Mark
Mark $(\checkmark)$ against the correct answer of the following: The product of two numbers is $\frac{-1}{4}$. If one of them is $\frac{-3}{10}$, then the other is$-$
- ✓
$\frac{5}{6}$
- B
$\frac{-5}{6}$
- C
$\frac{4}{3}$
- D
$\frac{-8}{5}$
AnswerCorrect option: A. $\frac{5}{6}$
Let the required number be $x$
Now,
$\frac{-3}{10}\times\text{x}=\frac{-1}{4}$
$\Rightarrow\text{x}=\frac{-1}{4}\div\Big(\frac{-3}{10}\Big)$
$\Rightarrow\text{x}=\frac{-1}{4}\times\frac{10}{-3}$
$\Rightarrow\text{x}=\frac{10}{12}$
$\Rightarrow\text{x}=\frac{5}{6}$
View full question & answer→MCQ 51 Mark
Tick $(\checkmark)$ the correct answer the following: What should be added to $\frac{7}{12}$ to get $\frac{-4}{15}$?
- A
$\frac{17}{20}$
- ✓
$\frac{-17}{20}$
- C
$\frac{7}{20}$
- D
$\frac{-7}{20}$
AnswerCorrect option: B. $\frac{-17}{20}$
$\frac{-4}{15}-\frac{7}{12}$
$=\frac{-16-35}{60}$
$=\frac{-51}{60}$
$=\frac{-51\div3}{60\div3}$
$=\frac{-17}{20}$
View full question & answer→MCQ 61 Mark
Tick $(\checkmark)$ the correct answer the following:Which of the following numbers is in standard form?
- A
$\frac{-12}{26}$
- ✓
$\frac{-49}{71}$
- C
$\frac{-9}{16}$
- D
$\frac{28}{-105}$
AnswerCorrect option: B. $\frac{-49}{71}$
We know that a number is called in standard form if the numerator and denominator has no common divisor except $1.$
$\frac{-9}{16}$ is in standard form.
View full question & answer→MCQ 71 Mark
Tick $(\checkmark)$ the correct answer the following: $\Big(\frac{-5}{16}+\frac{7}{12}\Big)=\ ?$
- A
$\frac{-7}{48}$
- B
$\frac{1}{24}$
- ✓
$\frac{13}{48}$
- D
$\frac{1}{3}$
AnswerCorrect option: C. $\frac{13}{48}$
$\because\frac{-5}{16}+\frac{7}{12}$
$=\frac{-5+28}{48}$
$=\frac{13}{48}$
View full question & answer→MCQ 81 Mark
Tick $(\checkmark)$ the correct answer the following: $\Big(\frac{2}{3}+\frac{-4}{5}+\frac{7}{15}+\frac{-11}{20}\Big)=\ ?$
- A
$\frac{-1}{5}$
- ✓
$\frac{-4}{15}$
- C
$\frac{-13}{60}$
- D
$\frac{-7}{30}$
AnswerCorrect option: B. $\frac{-4}{15}$
$\ce{LCM}$ of $3, 5, 15$ and $20 = 60$
$\therefore\frac{2}{3}+\frac{-4}{5}+\frac{7}{15}+\frac{-11}{20}$
$=\frac{40+(-48)+28+(-33)}{60}$
$=\frac{40-48+28-33}{60}$
$=\frac{68-81}{60}$
$=\frac{-13}{60}$
View full question & answer→MCQ 91 Mark
Tick $(\checkmark)$ the correct answer the following: $\Big(\frac{-5}{9}\div\frac{2}{3}\Big)=\ ?$
- A
$\frac{-5}{2}$
- ✓
$\frac{-5}{6}$
- C
$\frac{-10}{27}$
- D
$\frac{-6}{5}$
AnswerCorrect option: B. $\frac{-5}{6}$
$=\frac{-5}{9}\div\frac{2}{3}$
$=\frac{-5}{9}\times\frac{3}{2}$
$=\frac{-5\times3}{9\times2}$
$=\frac{-15}{18}$
$=\frac{-15\div3}{18\div3}$
$=\frac{-5}{6}$
View full question & answer→MCQ 101 Mark
Tick $(\checkmark)$ the correct answer the following: $\Big(\frac{-9}{16}\times\frac{8}{15}\Big)=\ ?$
- A
$\frac{-3}{10}$
- ✓
$\frac{-4}{15}$
- C
$\frac{-9}{25}$
- D
$\frac{-2}{5}$
AnswerCorrect option: B. $\frac{-4}{15}$
$=\frac{-9}{16}\times\frac{8}{15}$
$=\frac{-9\times8}{16\times15}$
$=\frac{-72}{240}$
$=\frac{-72\div24}{240\div24}$
$=\frac{-3}{10}$
View full question & answer→MCQ 111 Mark
Mark $(\checkmark)$ against the correct answer of the following: What should be added to $\frac{-3}{5}$ get $\frac{-1}{3}$?
- A
$\frac{4}{5}$
- B
$\frac{8}{15}$
- ✓
$\frac{4}{15}$
- D
$\frac{2}{5}$
AnswerCorrect option: C. $\frac{4}{15}$
Let the number added be $x$
Then,
$\frac{-3}{5}+\text{x}=\frac{-1}{3}$
$\Rightarrow\text{x}=\frac{1}{3}-\frac{-3}{5}$
$\Rightarrow\text{x}=\frac{-1\times5-(-3)\times3}{15}$
$\Rightarrow\text{x}=\frac{-5+9}{15}$
$\Rightarrow\text{x}=\frac{4}{15}$
View full question & answer→MCQ 121 Mark
Tick $(\checkmark)$ the correct answer the following: $\Big(3+\frac{5}{-7}\Big)=\ ?$
- A
$\frac{-16}{7}$
- ✓
$\frac{16}{7}$
- C
$\frac{-26}{7}$
- D
$\frac{-8}{7}$
AnswerCorrect option: B. $\frac{16}{7}$
$3+\frac{5}{-7}$
$=\frac{-21+5}{7}$
$=\frac{-16}{-7}$
$=\frac{16}{7}$
View full question & answer→MCQ 131 Mark
Tick $(\checkmark)$ the correct answer the following: The product of two numbers is $\frac{-16}{35}$. If one of the numbers is $\frac{-15}{14}$ then the other is$-$
- A
$\frac{-2}{5}$
- B
$\frac{8}{15}$
- ✓
$\frac{32}{75}$
- D
$\frac{-8}{3}$
AnswerCorrect option: C. $\frac{32}{75}$
Let $x$ be the required number
Then,
$\frac{-15}{14}\times\text{x}=\frac{-16}{35}$
$\Rightarrow\text{x}=\frac{-16}{35}\div\frac{-15}{14}$
$\Rightarrow\text{x}=\frac{-16}{35}\times\frac{14}{-15}$
$\Rightarrow\frac{-224}{-525}=\frac{224}{525}$
$=\frac{224\div7}{525\div7}$
$=\frac{32}{75}$
View full question & answer→MCQ 141 Mark
Mark $(\checkmark)$ against the correct answer of the following:$\frac{4}{3}\div\ ?=\frac{-5}{2}$
- A
$\frac{-8}{5}$
- B
$\frac{8}{5}$
- ✓
$\frac{-8}{15}$
- D
$\frac{8}{15}$
AnswerCorrect option: C. $\frac{-8}{15}$
We have,
$\frac{4}{3}\div\text{x}=\frac{-5}{2}$
$\Rightarrow\frac{4}{3}\times\frac{1}{\text{x}}=\frac{-5}{2}$
$\Rightarrow\frac{1}{\text{x}}=\frac{\Big(\frac{-5}{2}\Big)}{\Big(\frac{4}{3}\Big)}$
$\Rightarrow\frac{1}{\text{x}}=\Big(\frac{-5}{2}\Big)\times\Big(\frac{3}{4}\Big)$
$\Rightarrow\frac{1}{\text{x}}=\frac{-15}{8}$
$\Rightarrow\frac{1}{\text{x}}=\frac{8}{-15}$
$\Rightarrow\frac{1}{\text{x}}=\frac{8\times-1}{-15\times-1}$
$\Rightarrow\frac{1}{\text{x}}=\frac{-8}{15}$
View full question & answer→MCQ 151 Mark
Tick $(\checkmark)$ the correct answer the following: Reciprocal of $\frac{-3}{4}$ is:
- A
$\frac{4}{3}$
- B
$\frac{3}{4}$
- ✓
$\frac{-4}{3}$
- D
$0$
AnswerCorrect option: C. $\frac{-4}{3}$
Reciprocal of $\frac{-3}{4}$ is $\frac{-4}{3}$
View full question & answer→MCQ 161 Mark
Tick $(\checkmark)$ the correct answer the following: $\Big(\frac{8}{-15}+\frac{4}{-3}\Big)=\ ?$
- A
$\frac{28}{15}$
- ✓
$\frac{-28}{15}$
- C
$\frac{-4}{5}$
- D
$\frac{-4}{15}$
AnswerCorrect option: B. $\frac{-28}{15}$
$\frac{8}{-15}+\frac{4}{-3}$
$=\frac{8+20}{-15}$
$=\frac{28}{-15}$
$=\frac{-28}{15}$
View full question & answer→MCQ 171 Mark
Mark $(\checkmark)$ against the correct answer of the following: What should be subtracted from $\frac{-2}{3}$ to get $\frac{3}{4}$?
- A
$\frac{-11}{12}$
- B
$\frac{-13}{12}$
- C
$\frac{-5}{4}$
- ✓
$\frac{-17}{12}$
AnswerCorrect option: D. $\frac{-17}{12}$
Let the number be $x$
Now,
$\frac{-2}{3}-\text{x}=\frac{3}{4}$
$\Rightarrow-1\times\Big(\frac{2}{3}+\text{x}\Big)=\frac{3}{4}$
$\Rightarrow\frac{2}{3}+\text{x}=\frac{-3}{4}$
$\Rightarrow\text{x}=\frac{-3}{4}+\Big(\text{Additive inverse of }\frac{2}{3}\Big)$
$\Rightarrow\text{x}=\frac{-3}{4}-\Big(\frac{-2}{3}\Big)$
$\Rightarrow\text{x}=\frac{-3}{4}+\frac{2}{3}$
$\Rightarrow\text{x}=\frac{-3\times3}{4\times3}+\frac{2\times4}{3\times4}$
$\Rightarrow\text{x}=\frac{-9}{12}+\frac{-8}{12}$
$\Rightarrow\text{x}=\frac{-17}{12}$
View full question & answer→MCQ 181 Mark
Tick $(\checkmark)$ the correct answer the following: $\Big(\frac{-3}{7}\Big)^{-1}=\ ?$
- A
$\frac{7}{3}$
- ✓
$\frac{-7}{3}$
- C
$\frac{3}{7}$
- D
AnswerCorrect option: B. $\frac{-7}{3}$
$\Big(\frac{-3}{7}\Big)^{-1}=\frac{-7}{3}$
$\Big(\because\text{x}^{-1}=\frac{1}{\text{x}}\Big)$
View full question & answer→MCQ 191 Mark
Tick $(\checkmark)$ the correct answer the following: The product of two rational numbers is $\frac{-28}{81}$. If one of the numbers is $\frac{14}{27}$ then the other one is:
- ✓
$\frac{-2}{3}$
- B
$\frac{2}{3}$
- C
$\frac{3}{2}$
- D
$\frac{-3}{2}$
AnswerCorrect option: A. $\frac{-2}{3}$
Product of two numbers $=\frac{-28}{81}$
One numbers $=\frac{ 14}{27}$
$\therefore$ Other number $=\frac{-28}{81}\div\frac{ 14}{27}$
$=\frac{-28}{81}\times\frac{27}{14}$
$=\frac{-2}{3}$
View full question & answer→MCQ 201 Mark
Tick $(\checkmark)$ the correct answer the following: The sum of two numbers is $\frac{-4}{3}$. If one of the numbers is $-5,$ what is the other?
- A
$\frac{-11}{3}$
- ✓
$\frac{11}{3}$
- C
$\frac{-19}{3}$
- D
$\frac{19}{3}$
AnswerCorrect option: B. $\frac{11}{3}$
Sum of two numbers $=\frac{-4}{3}$
One number $= -5$
Second number $=\frac{-4}{3}-(-5)$
$=\frac{-4}{3}+\frac{5}{1}$
$=\frac{-4+15}{3}$
$=\frac{11}{3}$
View full question & answer→MCQ 211 Mark
Tick $(\checkmark)$ the correct answer the following: The sum of two rational numbers is $-3.$ If one of them is $\frac{-10}{3}$ then the other one is:
- A
$\frac{-13}{3}$
- B
$\frac{-19}{3}$
- ✓
$\frac{1}{3}$
- D
$\frac{13}{3}$
AnswerCorrect option: C. $\frac{1}{3}$
Sum $= -3$
One number $=\frac{-10}{3}$
$\therefore$ Second number $=-3-\Big(\frac{-10}{3}\Big)$
$=-3+\frac{10}{3}$
$=\frac{-9+10}{3}$
$=\frac{1}{3}$
View full question & answer→MCQ 221 Mark
Tick $(\checkmark)$ the correct answer the following: Additive inverse of $\frac{-5}{9}$ is:
- A
$\frac{-9}{5}$
- B
$0$
- ✓
$\frac{5}{9}$
- D
$\frac{9}{5}$
AnswerCorrect option: C. $\frac{5}{9}$
Additive inverse of $\frac{-5}{9}$ is $=\Big(\frac{5}{9}\Big)$
View full question & answer→MCQ 231 Mark
Tick $(\checkmark)$ the correct answer the following: What should be added to $\frac{-5}{7}$ to get $\frac{-2}{3}$?
- A
$\frac{-29}{21}$
- B
$\frac{29}{21}$
- ✓
$\frac{1}{21}$
- D
$\frac{-1}{21}$
AnswerCorrect option: C. $\frac{1}{21}$
$=\frac{-2}{3}-\Big(\frac{-5}{7}\Big)$
$=\frac{-2}{3}+\frac{5}{7}$
$=\frac{-14+15}{21}$
$=\frac{1}{21}$
View full question & answer→MCQ 241 Mark
Mark $(\checkmark)$ against the correct answer of the following: A rational number between $\frac{-2}{3}$ and $\frac{1}{2}$ is:
- A
$\frac{-1}{6}$
- ✓
$\frac{-1}{12}$
- C
$\frac{-5}{6}$
- D
$\frac{5}{6}$
AnswerCorrect option: B. $\frac{-1}{12}$
A rational number between $\frac{-2}{3}$ and $\frac{1}{2}=\frac{1}{2}\times\Big(\frac{-2}{3}+\frac{1}{2}\Big)$
$=\frac{1}{2}\times\Big(\frac{-2\times2}{3\times2}+\frac{1\times3}{2\times3}\Big)$
$=\frac{1}{2}\times\Big(\frac{-4}{6}+\frac{3}{6}\Big)$
$=\frac{1}{2}\times\Big(\frac{-4+3}{6}\Big)$
$=\frac{-1}{12}$
View full question & answer→MCQ 251 Mark
Tick $(\checkmark)$ the correct answer the following: $\frac{4}{9}\div\ ?=\frac{-8}{15}$
- A
$\frac{-32}{45}$
- B
$\frac{-8}{5}$
- C
$\frac{-9}{10}$
- ✓
$\frac{-5}{6}$
AnswerCorrect option: D. $\frac{-5}{6}$
Let $x$ is required rational
$\therefore\frac{4}{9}\div\text{x}=\frac{-8}{15}$
$\Rightarrow\frac{4}{9}\times\frac{1}{\text{x}}=\frac{-8}{15}$
$\Rightarrow\frac{1}{\text{x}}=\frac{-8}{15}\times\frac{9}{4}$
$=\frac{-72}{60}$
$=\frac{-72\div12}{60\div12}$
$=\frac{-6}{5}$
$\therefore\text{x}=\frac{-5}{6}$
View full question & answer→MCQ 261 Mark
Tick $(\checkmark)$ the correct answer the following: $\Big(\frac{7}{-26}+\frac{16}{39}\Big)=\ ?$
- ✓
$\frac{11}{78}$
- B
$\frac{-11}{78}$
- C
$\frac{11}{39}$
- D
$\frac{-11}{39}$
AnswerCorrect option: A. $\frac{11}{78}$
$\frac{7}{-26}+\frac{16}{39}$
$=\frac{-21+32}{78}$
$=\frac{11}{78}$
View full question & answer→MCQ 271 Mark
Tick $(\checkmark)$ the correct answer the following: $\Big(\frac{31}{-4}+\frac{-5}{8}\Big)=\ ?$
- A
$\frac{67}{8}$
- B
$\frac{57}{8}$
- C
$\frac{-57}{8}$
- ✓
$\frac{-67}{8}$
AnswerCorrect option: D. $\frac{-67}{8}$
$\frac{31}{4}+\frac{-5}{8}$
$=\frac{-62-5}{7}$
$=\frac{-67}{8}$
View full question & answer→MCQ 281 Mark
Mark $(\checkmark)$ against the correct answer of the following:$\Big(\frac{-5}{6}\div\frac{-2}{3}\Big)=\ ?$
- A
$\frac{-5}{4}$
- ✓
$\frac{5}{4}$
- C
$\frac{-4}{5}$
- D
$\frac{4}{5}$
AnswerCorrect option: B. $\frac{5}{4}$
$\frac{-5}{6}\div\frac{-2}{3}$
$=\frac{-5}{6}\times\frac{3}{-2}$
$=\frac{-5\times3}{6\times-2}$
$=\frac{-15}{-12}$
$=\frac{-15\times-1}{-12\times-1}$
$=\frac{15}{12}$
$=\frac{15\div3}{12\div3}$
$=\frac{5}{4}$
View full question & answer→