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Question 14 Marks
Construct a quadrilateral ABCD given that AB = 4cm, BC = 3cm, $\angle\text{A}=75^\circ,$ $\angle\text{B}=80^\circ$ and $\angle\text{C}=120^\circ.$
Answer

Steps of construction:
Step I: Draw AB = 4cm.
Step II: Construct $\angle\text{XAB}=75^\circ$ at A and $\angle\text{ABY}=80^\circ$ at B.
Step III: With B as the centre and radius 3cm, cut off BC = 3cm.
Step IV: At C, draw $\angle\text{BCZ}=120^\circ$ such that it meets AX at D.
The quadrilateral so obtained is the required quadrilateral.
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Question 24 Marks
Construct, if possible, a quadrilateral ABCD in which AB = 6cm, BC = 7cm, CD = 3cm, AD = 5.5cm and AC = 11cm. Give reasons for not being able to construct, if you cannot. (Not possible, because in triangle ACD, AD + CD < AC).
Answer
Such a quadrilateral cannot be constructed because in a triangle, the sum of the length of its two sides must be greater than the that of the third side But here in triangle ACD.
AD + CD = 5.5 + 3 = 8.5cm
and AC = 11cm. i.e., AD + CD < AC, which is not possible.
So, the construction is not possible.
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