Question 12 Marks
Find the surface area of a chalk box, whose length, breadth and height are $18 cm, 10 cm$ and 8 cm respectively.
Answer
View full question & answer→Length $=18 cm$
Breadth $=10 cm$
Height $=8 cm$
$\therefore$ Total surface area
$=2(l b+l h+b h)=2(18 \times 10+18 \times 8+10 \times 8)=2(180+144+80)=808 cm^2$
Breadth $=10 cm$
Height $=8 cm$
$\therefore$ Total surface area
$=2(l b+l h+b h)=2(18 \times 10+18 \times 8+10 \times 8)=2(180+144+80)=808 cm^2$