MCQ 11 Mark
The lengths of parallel chords which are on opposite sides of the centre of a circle are 6 cm and 8 cm. If radius of the circle is 5 cm, then the distance between these chords is _____.
- A$2 cm$
- B$1 cm$
- C$8 cm$
- ✓$7 cm$
Answer
$P Q=8 cm, M N=6 cm$
$\therefore A Q=4 cm, B N=3 cm$
$\therefore O Q^2=O A^2+A Q^2$
$\therefore 5^2=O A^2+4^2$
$\therefore O A^2=25-16=9$
$\therefore O A=3 cm$
Also, $ON ^2= OB ^2+ BN ^2$
$\therefore 5^2= OB ^2+3^2$
$\therefore OB =4 cm$
Now, $A B=O A+O B=3+4=7 cm$
View full question & answer→Correct option: D.
$7 cm$
$P Q=8 cm, M N=6 cm$
$\therefore A Q=4 cm, B N=3 cm$
$\therefore O Q^2=O A^2+A Q^2$
$\therefore 5^2=O A^2+4^2$
$\therefore O A^2=25-16=9$
$\therefore O A=3 cm$
Also, $ON ^2= OB ^2+ BN ^2$
$\therefore 5^2= OB ^2+3^2$
$\therefore OB =4 cm$
Now, $A B=O A+O B=3+4=7 cm$
