MCQ 11 Mark
The area of the triangle formed by the points $A(2, 0), B(6, 0)$ and $C(4, 6)$ is:
- A$24$ sq. unit
- ✓$12$ sq. unit
- C$10$ sq. unit
- DNone of these
Answer
Let $CD$ be perpendicular drawn from $C$ to $AB$.
The length of the perpendicular will be equal to the ordinate of point $C$.
$\Rightarrow CD = 6 $ unit
$AB = 4$ unit
Now, area of $\triangle\text{ABC}=\frac{1}{2}\times\text{Base}\times\text{height}$
$\triangle\text{ABC}=\frac{1}{2}\times\text{5}\times\text{6}$
$12\text{sq. units}$
View full question & answer→Correct option: B.
$12$ sq. unit

Let $CD$ be perpendicular drawn from $C$ to $AB$.
The length of the perpendicular will be equal to the ordinate of point $C$.
$\Rightarrow CD = 6 $ unit
$AB = 4$ unit
Now, area of $\triangle\text{ABC}=\frac{1}{2}\times\text{Base}\times\text{height}$
$\triangle\text{ABC}=\frac{1}{2}\times\text{5}\times\text{6}$
$12\text{sq. units}$
