A square and an equilateral triangle have equal perimeters. If the diagonal of the square is $12\sqrt{2}\text{ cm},$ then area of the triangle is:
- A$24\sqrt{2}\text{ cm}^2$
- B$24\sqrt{3}\text{ cm}^2$
- C$48\sqrt{3}\text{ cm}^2$
- ✓$64\sqrt{3}\text{ cm}^2$
Answer: D.
View full solution →