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19 questions · self-marked practice — reveal the answer and mark yourself.

Question 13 Marks
Solve the equation 2y - 1 = y + 1 and represent it graphically on the coordinate plane.
Answer
We are given,

2y - 1 = y + 1

we get,

2y - y = 1 + 1

y = 2

The representation of the solution on the Cartesian plane, it is a line parallel to y axis passing through the point (0, 2) is shown below

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Question 23 Marks
Write two solutions of the form x = 0, y = a and x = b, y = 0 for the following equations:
5x - 2y = 10
Answer
We are given, 5x - 2y = 10 Substituting x = 0 in the given equation, We get; 5 × 0 - 2y = 10 - 2y = 10 - y $=\frac{10}{2}$ y = -5 Thus x = 0 and y = -5 is the solution of 5x - 2y = 10 Substituting y = 0 in the given equation, we get 5x - 2 × 0 = 10 5x = 10$\text{x} = \frac{10}{5}$
x = 2 Thus x = 2 and y = 0 is a solution of 5x - 2y = 10
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Question 33 Marks
Give the geometric representations of the following equations:
  1. On the number line.
  2. On the Cartesain plane.
2x + 9 = 0
Answer
2x + 9 = 0 2x = -9$\text{X}=\text{x}=\frac{-9}{2}=-4.5$
Point A represents -4.5 on the number line. On Cartesian plane, equation represents all points on y axis for which x = -4.5
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Question 43 Marks
Give the geometrical representation of 2x + 13 = 0 as an equation in:
One variable.
Answer


One variable representation of 2x + 13 = 0

2x = -13

$\text{x}=\frac{-13}{2}=-6\frac{1}{2}$

Point A represents $-\frac{13}{2}.$
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Question 53 Marks
Write two solutions of the form x = 0, y = a and x = b, y = 0 for the following equations:
-4x + 3y = 12
Answer
We are given, -4x + 3y = 12 Substituting x = 0 in the given equation, we get; -4 × 0 + 3y = 12 3y = 12 y = 4 Thus x = 0 and y = 4 is a solution of the -4x + 3y = 12 Substituting y = 0 in the given equation, we get; -4x + 3 × 0 = 12 - 4x = 12$\text{x} = -\frac{12}{4}$
x = -3 Thus x = -3 and y = 0 is a solution of -4x + 3y = 12
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Question 63 Marks
Give the geometric representations of the following equations:
  1. On the number line.
  2. On the Cartesain plane.
x = 2
Answer

x = 2
Point A represents x = 2 number line.
On Cartesian plane, eqution represents all points on y axis for which x = 2
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Question 73 Marks
Write two solutions for the following equations:$\frac{2}{3}\text{x} - \text{y} = 4$
Answer
We are given,$\frac{2}{3}\text{x} - \text{y} = 4$
Substituting x = 0 in the given equation, we get
$\frac{2}{3}\text{x} - \text{y} = 4$
0 - y = 4
y = -4
Thus x = 0 and y = -4 is the solution of $\frac{2}{3}\text{x} - \text{y} = 4$
Substituting x = 6 in the given equation, we get
$\frac{2}{3}\text{x} - \text{y} = 4$
-y = 4 - 2
y = -2
Thus x = 3 and y = -2 is the solution of $\frac{2}{3}\text{x} - \text{y} = 4$
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Question 83 Marks
Write two solutions of the form x = 0, y = a and x = b, y = 0 for the following equations:
2x + 3y = 24
Answer
We are given, 2x + 3y = 24 Substituting x = 0 in the given equation, we get; 2 × 0 + 3y = 24 3y = 24$\text{y}=\frac{24}{3}$
y = 8 Thus x = 0 and y = 8 is a solution of 2x + 3y = 24 Substituting y = 0 in the given equation, we get; 2x + 3 × 0 = 24 2x = 24$\text{x} = \frac{24}{2}$
x = 12 Thus x = 12 and y = 0 is a solution of 2x + 3y = 24
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Question 93 Marks
Give the geometric representations of the following equations:
  1. On the number line.
  2. On the Cartesain plane.
y = 3
Answer

y = 3
Point A represents 3 on number line.
On Cartesian plane, equation represents all points on x axis for which y = 3
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Question 103 Marks
If$ x = 1$ and $y = 6$ is a solution of the equation $8x - ay + a^2 = 0$, find the values of a
Answer
We are given,
$8x - ay + a^2 = 0 (1, 6)$ is a solution of equation$ 8x - ay + a^2 = 0$
Substituting $x = 1$ and $y = 6$ in $8x - ay + a^2 = 0$, we get $8 \times 1 - a \times 6 + a^2 = 0$
$\Rightarrow a^2 - 6a + 8 = 0$
Using quadratic factorization $a^2 - 4a - 2a + 8 = 0 a(a - 4) - 2(a - 4) = 0 (a - 2)(a - 4) = 0$
$a = 2, 4$
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Question 113 Marks
Write two solutions for the following equations:
x = 6y
Answer
We are given, x = 6y Substituting x = 0 in the given equation, we get 0 = 6y$\text{y}=\frac{0}{6}$
y = 0 Thus x = 0 and y = 0 is the solution of x = 6y Substituting x = 6 in the given equation, we get 6 = 6y$\text{y}=\frac{6}{6}$
y = 1 Thus x = 6 and y = 1 is the solution of x = 6y
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Question 123 Marks
Write two solutions for the following equations:$\text{x}+\pi\text{y} = 4 $
Answer
We are given,$\text{x}+\pi\text{y} = 4 $
Substituting x = 0 in the given equation, we get$\text{x}+\pi\text{y} = 4 $
$\pi\text{y}=4-0$
$\text{y}=\frac{4}{\pi}$
Thus x = 0 and $\text{y}=\frac{4}{\pi}$ is the solution of $\text{x}+\pi\text{y} = 4 $
Substituting x = 6 in the given equation, we get$\text{x}+\pi\text{y} = 4 $
$\pi\text{y}=4-0$
$\text{y}=\frac{0}{\pi}$
$\text{y}=0$
Thus x = 4 and y = 0 is the solution of $\text{x}+\pi\text{y} = 4 $
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Question 133 Marks
Give the geometrical representation of 2x + 13 = 0 as an equation in:
Two variables.
Answer


Two variable representation of 2x + 13 = 0

2x + 0y + 13 = 0

2x = 13 = 0

2x = -13

$\text{x}=-\frac{13}{2}=-6\frac{1}{2}$

On Cartesian plane, equation represents all points on y axis for which x = -6.5
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Question 143 Marks
Find the value of k for which the point (1, -2) lies on the graph of the linear equation
x - 2y + k = 0.
Answer
We are given (1, -2) lies on the graph of linear equation x - 2y + k = 0.

So, the given co-ordinates are the solution of the equation x - 2y + k = 0.

Therefore, we can calculate the value of k by substituting the value of given co-ordinates in equation x - 2y + k = 0.

Substituting x = 1 and y = -2 in equation 2x - 3y + 8 = 0, we get

1 - 2(-2) + k = 0

1 + 4 + k = 0

k = -5
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Question 153 Marks
Write two solutions for the following equations:
3x - 4y = 7
Answer
We are given, 3x 1 + 4y = 7 Substituting x = 1 in the given equation, we get 3x 1 + 4y = 7 4y = 7 - 3$\text{y}=\frac{4}{4}$
Thus x = 1 and y = 1 is the solution of 3x + 4y = 7 Substituting x = 2 in the given equation, we get 3 × 2 + 4y = 7$\text{y}=\frac{1}{4}$
$\text{y}=\frac{1}{4}$
Thus x = 2 and $\text{y}=\frac{1}{4}$ is the solution of 3x + 4y = 7
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Question 163 Marks
Give the geometric representations of the following equations:
  1. On the number line.
  2. On the Cartesain plane.
y + 3 = 0
Answer

y + 3 = 0
y = -3
Point A represents -3 on number line.
On Cartesian plane, equation represents all points on x axis for which y = -3
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Question 173 Marks
If x = 2a + 1 and y = a -1 is a solution of the equation 2x - 3y + 5 = 0, find the value of a.
Answer
We are given,
2x - 3y + 5 = 0 (2a + 1, a - 1) is the solution of equation 2x - 3y + 5 = 0.
Substituting x = 2a + 1 and y = a - 1 in 2x - 3y + 5 = 0,
We get 2 × 2a + (1- 3) × a - 1 + 5 = 0
⇒ 4a + 2 - 3a + 3 + 5 = 0
⇒ a + 10 = 0
⇒ a = -10
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Question 183 Marks
If the point (a, 2) lies on the graph of the linear equatio 2x - 3y + 8 = 0, find the value of a.
Answer
We are given (a, 2) lies on the graph of linear equation 2x - 3y + 8 = 0.

So, the given co-ordinates are the solution of the equation 2x - 3y + 8 = 0.

Therefore, we can calculate the value of a by substituting the value of given co-ordinates in equation 2x - 3y + 8 = 0.

Substituting x = a and y = 2 in equation 2x - 3y + 8 = 0, we get

2 × a - 3 × 2 + 8 = 0

2a - 6 + 8 = 0

2a + 2 = 0

2a = -2

$\text{a}=-\frac{2}{2}$

a = -1
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Question 193 Marks
Give the geometric representations of the following equations:
  1. On the number line.
  2. On the Cartesain plane.
3x - 5 = 0
Answer
3x - 5 = 0 3x = 5$\text{x}=\frac{5}{3}=1\frac{2}{3}=1.6\text{ (Approx)}$
Point A represents $1\frac{1}{2}$ or $\frac{5}{3}$ on number line. On Cartesian plane, equation represents all points on y axis for which x = 1.6
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