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2 Marks Questions

Question 512 Marks
Two cylinders A and B of equal capacity are connected to each other via a stopcock. A contains a gas at standard temperature and pressure. B is completely evacuated. The entire system is thermally insulated. The stopcock is suddenly opened. Answer the following: What is the change in internal energy of the gas?
Answer
Zero. The internal energy of the gas can change only when work is done by or on the gas. Since in this case no work is done by or on the gas, the internal energy of the gas will not change.
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Question 522 Marks
How the atmosphere is important thermodynamically?
Answer
The atmosphere is important thermo-dynamically because:
  1. The temperature difference brings wind.
  2. The reflected energy from surface is prevented from escaping so that appropriate life supporting temperature exists.
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Question 542 Marks
When ice melts, then change in internal energy is greater than the heat supplied, why?
Answer
When ice melts, volume of water formed is less than that of ice. So, surroundings (environment) does work on the system (ice). And by first law, $\Delta\text{Q}=\Delta\text{W}+\Delta\text{W}$ $\Rightarrow\Delta\text{U}=\Delta\text{Q}-\Delta\text{W}$ $(\Delta\text{W}=$ negative as work is done on the system$)$ $\Rightarrow\Delta\text{U}>\Delta\text{Q}$
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Question 552 Marks
What do you mean by the "phases" of a substance?
Answer
The three states of a substance, namely solid, liquid and gas are called its phases. Whenever a substance can occur in several forms which are homogeneous, physically distinct, and mechanically separable from each other, the forms are called the phases of the same substance. The phases of a substance generally involve either absorption or evolution of heat.
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Question 562 Marks
Write the statements of second law of thermodynamics applicable to:
  1. Heat engine.
  2. Refrigerator.
Answer
  1. Heat engine: One cannot devise a process whose only purpose is to convert heat into work.
  2. Refrigerator: One cannot make heat to flow from a cold to a hot body by itself, without using any external agency.
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Question 572 Marks
The climate of a harbour town is more temperate than that of a town in a desert at the same altitude. Why?
Answer
The relative humidity in a harbour town is more than that in a town in a desert. Hence the climate of a harbour town is more temperate than that of a town in a desert.
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Question 582 Marks
Calculate the fall in temperature of helium initially at 15°C, when it is suddenly expanded to 8 times of its volume. Given $\gamma=\frac53.$
Answer
$\text{T}_1=273+15=278\text{k},\text{T}_2=?$ $\text{V}_2=8\text{V}_1,\gamma=\frac53$ $\text{T}_2\text{V}_2^{\gamma-1}=\text{T}_1\text{V}_1^{\gamma-1}$ $\text{T}_2=\text{T}_1\Big(\frac{\text{V}-1}{\text{V}_2}\Big)^{\gamma-1};\text{T}_2=288\Big(\frac{\text{V}_1}{8\text{V}_1}\Big)^{\frac53-1}$ $\log\text{T}_2=\log288+\frac23\log\Big(\frac13\Big)=1.8573$ $\text{T}_2=\text{antilog }1.8573=71.99\text{K}$ Fall in temperature of helium, $\text{T}_1-\text{T}_2=288-71.99=216.01\text{K}$
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Question 592 Marks
Calculate the difference between two principal specific heats of 1g of helium gas at N.T.P. Molecular weight of helium = 4u and $J = 4.186Jcal^{-1}$ and $R = 8.31 J ~mole^{-1} K^{-1}$.
Answer
Here, $C_P - C_V$ = ? Molecular weight, $m = 4 R = 8.31 J ~mole^{-1} K^{-1}​​​​​​​$ As, $\text{C}_\text{P}-\text{C}_\text{v}=\frac{\text{R}}{\text{J}}=\frac{\text{R}}{\text{mJ}}$ $\therefore\text{C}_\text{P}-\text{C}_\text{V}=\frac{8.31}{4\times4.186}=0.496\text{ cal g}^{-1}\text{K}^{-1}$
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Question 602 Marks
Air pressure in a car tyre increases during driving. Explain.
Answer
Volume of a car tyre is fixed. During driving, temperature of the gas increases while its volume remains constant. So, according to Charle’s law, at constant volume (V), Pressure (P) $\propto$ Temperature (T) Therefore, pressure of gas increases
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