Question 1012 Marks
Why is FeO(s) not formed in stoichiometric composition?
Answer
View full question & answer→In the crystals of FeO , some of the $\mathrm{Fe}^{2+}$ cations are replaced by $\mathrm{Fe}^{3+}$ ions. Three $\mathrm{Fe}^{2+}$ ions are replaced by two $\mathrm{Fe}^{3+}$ ions to make up for the loss of positive charge. Eventually there would be less amount of metal as compared to stoichiometric proportion.